Silver nitrate and sodium phosphate react to form silver phosphate and sodium nitrate. The balanced equation is 3 AgNO3(aq) + Na3PO4(aq) equals Ag3PO4(s) + 3 NaNO3(aq).
If you mean the chemical formula, it is Ag3PO4
To find the mass of the precipitate that forms when 100.0mL of 0.887M AgNO3 is added to a Na3PO4 solution, you need to determine the limiting reactant. Since Na3PO4 is in excess, AgNO3 is the limiting reactant. Calculate the moles of AgNO3 using its molarity and volume, then use the mole ratio between AgNO3 and the precipitate to find the moles of the precipitate. Finally, convert the moles of the precipitate to mass using its molar mass.
The net ionic equation for Na3PO4 is 3Na+ + PO4^3- -> Na3PO4. This equation shows that the sodium ion (Na+) and phosphate ion (PO4^3-) combine to form sodium phosphate (Na3PO4) without any spectator ions.
Silver nitrate doesn't react with nitric acid.
The balanced equation for this reaction is: 2 Na2S + 2 AgNO3 → Ag2S + 2 NaNO3
my balance sheet does not balance why?
If you mean the chemical formula, it is Ag3PO4
Na3PO4+H2O->NaOH+H3PO4 just balance it.
To find the mass of the precipitate that forms when 100.0mL of 0.887M AgNO3 is added to a Na3PO4 solution, you need to determine the limiting reactant. Since Na3PO4 is in excess, AgNO3 is the limiting reactant. Calculate the moles of AgNO3 using its molarity and volume, then use the mole ratio between AgNO3 and the precipitate to find the moles of the precipitate. Finally, convert the moles of the precipitate to mass using its molar mass.
I assume double displacement reaction. Balanced equation. 3AgNO3 + Na3PO4 -> Ag3PO4 + 3NaNO3 2.00 moles sodium phosphate ( 3 moles AgNO3/1 mole Na3PO4) = 6.00 moles silver nitrate needed =========================
The net ionic equation for Na3PO4 is 3Na+ + PO4^3- -> Na3PO4. This equation shows that the sodium ion (Na+) and phosphate ion (PO4^3-) combine to form sodium phosphate (Na3PO4) without any spectator ions.
To balance an equation involving sodium (Na) and phosphate (PO4), ensure the number of sodium atoms is equal on both sides by adding coefficients. For example, in the reaction Na3PO4 + CaCl2 -> Ca3(PO4)2 + NaCl, balance by adding a coefficient of 3 in front of NaCl to ensure equal numbers of sodium atoms on both sides.
The net ionic equation for silver nitrate (AgNO3) mixed with sodium phosphate (Na3PO4) is: Ag⁺(aq) + PO4^3-(aq) -> Ag3PO4(s)
Silver nitrate doesn't react with nitric acid.
To balance the equation AgNO3 + (NH4)2CrO4 → Ag2CrO4 + NH4NO3, first count the number of atoms for each element on both sides. Then adjust the coefficients to balance the equation, making sure to keep the same number of atoms of each element on both sides. Finally, double-check to ensure that the equation is balanced: 2AgNO3 + (NH4)2CrO4 → Ag2CrO4 + 2NH4NO3.
balanced equation:- AgNO3(aq) + HBr(aq) ----> AgBr(s) + HNO3(aq)
(NH4)NO3 + AgNO3 --> (NH4)NO3 + AgNO3