1,4 moles carbon monoxide are produced.
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
The reaction is:2 C + O2 = 2 COSo 2,1 moles are obtained.
Sodium reacts with water. 0.652 NaOH moles will form.
If carbon dioxide reacts with hydrogen to form water, the balanced chemical equation is: CO2 + 2H2 -> CH2O + 2H2O. It shows that 1 mole of CO2 produces 2 moles of H2O. Therefore, from 25 moles of CO2, 50 moles of H2O can be produced.
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
How many moles of NH3 are produced when 1.2 mol of nitrogen reacts with hydrogen?
If 1 mole of carbon reacts, 1 mole of CO is produced according to the balanced chemical equation for the reaction. Therefore, if 1.4 moles of carbon react, 1.4 moles of CO will be produced.
The reaction is:2 C + O2 = 2 COSo 2,1 moles are obtained.
The balanced chemical equation for the reaction between H2 and NH3 is: 3H2 + N2 → 2NH3 From the equation, we can see that 3 moles of H2 produce 2 moles of NH3. Therefore, when 1.2 moles of H2 react, we can calculate the moles of NH3 produced as: 1.2 mol H2 * (2 mol NH3 / 3 mol H2) = 0.8 mol NH3.
3.03
Sodium reacts with water. 0.652 NaOH moles will form.
To calculate the moles of gas produced, first find the moles of Mg reacting by dividing the mass by the molar mass of Mg. Next, determine the mole ratio of Mg to gas produced from the balanced chemical equation of the reaction. Finally, multiply the moles of Mg by the mole ratio to find the moles of gas produced.
1 mole of silver nitrate produces 1 mole of silver when it reacts to completion. Therefore, 7 moles of silver nitrate will produce 7 moles of silver.
Balanced equation. N2 + 3H2 --> 2NH3 1.4 moles H2 (2 moles NH3/3 moles H2) = 0.93 moles NH3 produced =======================
If carbon dioxide reacts with hydrogen to form water, the balanced chemical equation is: CO2 + 2H2 -> CH2O + 2H2O. It shows that 1 mole of CO2 produces 2 moles of H2O. Therefore, from 25 moles of CO2, 50 moles of H2O can be produced.
The balanced reaction equation is 4Al + 3O2 -> 2Al2O3. Therefore, 3 moles of O2 reacts with 4 moles of Al to form 2 moles of Al2O3. Since 0.78 mol of O2 is reacted, the number of moles of Al2O3 formed can be calculated using the stoichiometry of the reaction.