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For this you need the atomic (molecular) mass of NO. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel. NO=30.0 grams
6.64 grams NO / (30.0 grams)= .221 moles NO
What else can I help you with?
How many grams of nitrogen dioxide must react with water to produce 5.00 x 1022 molecules of nitrogen monoxide?
To find the grams of nitrogen dioxide needed, first calculate the moles of nitrogen monoxide using Avogadro's number. Then, use the balanced chemical equation to determine the moles of nitrogen dioxide required. Finally, convert moles to grams using the molar mass of nitrogen dioxide.
When 40 grams of ammonium nitrate explode 14 grams of nitrogen and 8 grams of oxygen form how many grams of water form?
the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
How many moles of nitrogen gas are there in 35.7 gm of nitrogen gas?
To calculate the number of moles of nitrogen gas in 35.7 g, you can use the molar mass of nitrogen, which is 28 g/mol. First, divide the given mass by the molar mass to find the number of moles: ( \frac{35.7 , \text{g}}{28 , \text{g/mol}} \approx 1.275 , \text{mol}). Therefore, there are approximately 1.275 moles of nitrogen gas in 35.7 g.
How many molecules of carbon monoxide are present in 3.69 grams of this compound?
To find the number of molecules of carbon monoxide in 3.69 grams, first calculate the number of moles using the molar mass of carbon monoxide (28.01 g/mol). Next, use Avogadro's number to determine the number of molecules in those moles of carbon monoxide.
How many moles are in 21.4 mg of nitrogen dioxide?
To find the number of moles, you need to first convert 21.4 mg of nitrogen dioxide to grams by dividing by 1000 (since 1 gram = 1000 mg). Then, calculate the moles using the molar mass of nitrogen dioxide (NO2), which is 46.01 g/mol. 21.4 mg is equal to 0.0214 grams. Dividing 0.0214 g by the molar mass of NO2 gives you approximately 0.00047 moles of nitrogen dioxide.
How many grams of nitrogen dioxide must react with water to produce 5.00 x 1022 molecules of nitrogen monoxide?
To find the grams of nitrogen dioxide needed, first calculate the moles of nitrogen monoxide using Avogadro's number. Then, use the balanced chemical equation to determine the moles of nitrogen dioxide required. Finally, convert moles to grams using the molar mass of nitrogen dioxide.
How many grams in 5.0x1022 molecules of nitrogen monoxide?
To find the number of grams in 5.0x10^22 molecules of nitrogen monoxide (NO), you need to convert the number of molecules to moles and then from moles to grams. First, calculate the number of moles by dividing the number of molecules by Avogadro's number (6.022x10^23 molecules/mol). Then, use the molar mass of NO (30.01 g/mol) to convert moles to grams.
How many moles of nitrogen are in 15 grams of nitrogen?
15 grams of nitrogen are equal to 1,071 moles.
How many moles of nitrogen are there in 29 grams of nitrogen?
There are 29/14, or just over 2 moles of nitrogen in 19 grams.
How many moles are in 56 grams of carbon monoxide?
moles = weight in grams / molecular weight = 56 / 28 = 2 moles
How many grams of nitrogen are present in 1.78 moles of nitrogen trifluoride?
The answer is 24,92 g nitrogen.
How many moles of NO2 can be produced given 1.35 moles of nitrogen monoxide?
The reaction to form nitrogen dioxide using nitric oxide is; 2NO(g) + O2(g) -> 2NO2(g) As the stoichiometry between the substances are 1:1, 1.35 moles of nitrogen monoxide is needed.
How many moles of molecules are in 550 grams of nitrogen dioxide?
550 g of nitrogen dioxide is equal to 11,94 moles.
How many moles of nitrogen in 42 grams of nitrogen?
As a rule of thumb, the atomic mass of an element equals the number of grams of that element equals a mole. Since the atomic mass of Nitrogen is 14, there are 14 grams in one mole of Nitrogen. Next, we just have to divide 42 by 14 and we get our answer: There are 2.9988 moles in 42 grams of Nitrogen.
How many grams of carbon monoxide (CO) are there in 2.55 moles of the ompound?
To determine the mass of carbon monoxide in 2.55 moles, we first find the molar mass of CO, which is 28.01 g/mol. Then, we multiply the molar mass by the number of moles: 28.01 g/mol * 2.55 mol = 71.53 grams of CO in 2.55 moles of the compound.
When 40 grams of ammonium nitrate explode 14 grams of nitrogen and 8 grams of oxygen form how many grams of water form?
the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
How many moles of nitrogen are in 4.0 times 10 with the power of 2 of quinine?
The clarity of this question is not clear. I will assume grams and possibly moles as that number does not look like a number of atoms. Grams first, then moles. 4.0 X 102 grams quinine (1 moleC20H2N2O2/302.236 grams)(2 moles N/1 mole C20H2N2O2) = 2.6 moles nitrogen =============== Pretty much the same procedure if you meant moles just no dividing out a mass.
