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5.0 X 10^22 molecules of NO (1 mole NO/6.022 X 10^23)(30.01 grams/1 mole NO)

= 2.5 grams of nitrogen monoxide

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How many grams of nitrogen dioxide must react with water to produce 5.00 x 1022 molecules of nitrogen monoxide?

To find the grams of nitrogen dioxide needed, first calculate the moles of nitrogen monoxide using Avogadro's number. Then, use the balanced chemical equation to determine the moles of nitrogen dioxide required. Finally, convert moles to grams using the molar mass of nitrogen dioxide.


How many grams of nitrogen dioxide must react with water to produce 5.00x10 22 molecules of nitrogen monoxide?

To produce 5.00x10^22 molecules of nitrogen monoxide (NO), you need an equal number of molecules of nitrogen dioxide (NO2). With the balanced chemical equation 2NO2 + H2O → 2NO + 2HNO3, you can calculate the mass of nitrogen dioxide needed using the molar masses of NO2 and NO.


Why does 10 gram of nitrogen gas contain the same number of molecules as 10 gram of carbonmonoxide?

Both nitrogen gas and carbon monoxide have the same molecular weight, around 28 grams per mole. Therefore, 10 grams of each substance contain approximately one-third of a mole of molecules. Since Avogadro's number (6.022 x 10^23) represents the number of molecules in one mole of a substance, both 10 grams of nitrogen gas and 10 grams of carbon monoxide contain the same number of molecules, which is roughly 2 x 10^23.


How many moles are in 6.64 grams of nitrogen monoxide?

For this you need the atomic (molecular) mass of NO. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NO=30.0 grams6.64 grams NO / (30.0 grams)= .221 moles NO


How many molecules of carbon monoxide are present in 3.69 grams of this compound?

To find the number of molecules of carbon monoxide in 3.69 grams, first calculate the number of moles using the molar mass of carbon monoxide (28.01 g/mol). Next, use Avogadro's number to determine the number of molecules in those moles of carbon monoxide.


How many molecules are in 28 grams of nitrogen gas?

To calculate the number of molecules in 28 grams of nitrogen gas, you first need to determine the number of moles of nitrogen gas using its molar mass. The molar mass of nitrogen gas (N2) is 28 g/mol. Therefore, 28 grams of nitrogen gas is equivalent to one mole. One mole of a gas contains approximately 6.022 x 10^23 molecules, which is Avogadro's number. So, 28 grams of nitrogen gas would contain approximately 6.022 x 10^23 molecules.


How many moles of molecules are in 550 grams of nitrogen dioxide?

550 g of nitrogen dioxide is equal to 11,94 moles.


How many grams are in 8.200 x 1022 molecules of N2I6?

The nitrogen iodide is NI3.


How much mass would a mole of nitrogen molecules contain?

One mole of nitrogen molecules contains approximately 28 grams (since the atomic mass of nitrogen is approximately 14 g/mol).


Which has the greater number of monlecules. 10 g of N2 or 10 grams of O2?

10 grams of N2 would have a greater number of molecules than 10 grams of O2 because nitrogen (N2) has a smaller molar mass compared to oxygen (O2), so there would be more nitrogen molecules in 10 grams.


How many nitrogen molecules are in 12.88g of nitrogen gas?

To determine the number of nitrogen molecules in 12.88g of nitrogen gas, you first need to convert grams to moles using the molar mass of nitrogen (28.02 g/mol). Then, you can use Avogadro's number (6.022 x 10^23) to find the number of molecules in that number of moles.


For the following reaction grams of nitrogen monoxide are mixed with excess oxygen gas . The reaction yields grams of nitrogen dioxide .What is the theoretical yield of nitrogen dioxide grams What?

First, balance the equation: 2NO + O2 -> 2NO2 Calculate the molar mass of NO2 using the periodic table. Calculate the number of moles of NO involved using the given mass. Use the stoichiometry of the balanced equation to find the theoretical yield of NO2 in grams.