i believe its 28
The number of nitrogen molecules in a balloon depends on the volume of the balloon and the pressure of the gas inside. However, at standard conditions (1 atm pressure, 0°C temperature), a balloon with a volume of 22.4 liters would contain 6.02 x 10^23 nitrogen molecules, which is known as Avogadro's number.
Both nitrogen and oxygen exist at standard temperature and pressure as diatomic molecules. Therefore, the relative masses of equal numbers of molecules of the substance will the same as the ratios of their atomic masses, which are 15.9994 for oxygen and 14.0067 for nitrogen. The mass of oxygen that contains the same number of molecules as 42 g of nitrogen is 42(15.9994/14.0067) or 48 g, to the justified number of significant digits.
To calculate the mass of 2.50 x 10^4 molecules of nitrogen gas, you need to know the molecular weight of nitrogen. The molar mass of nitrogen (N2) is approximately 28.02 g/mol. Using this information, you can then calculate the mass of 2.50 x 10^4 molecules of nitrogen gas.
Since gases occupy the same volume at STP regardless of their identity, a 5 L cylinder will contain the same number of gas particles for both nitrogen and neon. However, nitrogen is heavier than neon, so it will contain a greater mass of gas particles.
To calculate the mass of nitrogen in 0.468 g of caffeine, you need to determine the molar mass of caffeine (C8H10N4O2) and the molar mass of nitrogen. Then, compute the proportion of nitrogen in caffeine by dividing the molar mass of nitrogen by the molar mass of caffeine, and multiply this by the mass of caffeine given. The mass of nitrogen in 0.468 g of caffeine is around 0.133 g.
Both nitrogen and oxygen exist at standard temperature and pressure as diatomic molecules. Therefore, the relative masses of equal numbers of molecules of the substance will the same as the ratios of their atomic masses, which are 15.9994 for oxygen and 14.0067 for nitrogen. The mass of oxygen that contains the same number of molecules as 42 g of nitrogen is 42(15.9994/14.0067) or 48 g, to the justified number of significant digits.
The number of nitrogen molecules in a balloon depends on the volume of the balloon and the pressure of the gas inside. However, at standard conditions (1 atm pressure, 0°C temperature), a balloon with a volume of 22.4 liters would contain 6.02 x 10^23 nitrogen molecules, which is known as Avogadro's number.
Both nitrogen and oxygen exist at standard temperature and pressure as diatomic molecules. Therefore, the relative masses of equal numbers of molecules of the substance will the same as the ratios of their atomic masses, which are 15.9994 for oxygen and 14.0067 for nitrogen. The mass of oxygen that contains the same number of molecules as 42 g of nitrogen is 42(15.9994/14.0067) or 48 g, to the justified number of significant digits.
To calculate the mass of 2.84 x 10^22 molecules of nitrogen gas, you first need to convert molecules to moles using Avogadro's number. Then, you can use the molar mass of nitrogen (28.02 g/mol) to determine the mass. The mass of 2.84 x 10^22 molecules of nitrogen gas would be approximately 5.04 grams.
To calculate the number of molecules in 28 grams of nitrogen gas, you first need to determine the number of moles of nitrogen gas using its molar mass. The molar mass of nitrogen gas (N2) is 28 g/mol. Therefore, 28 grams of nitrogen gas is equivalent to one mole. One mole of a gas contains approximately 6.022 x 10^23 molecules, which is Avogadro's number. So, 28 grams of nitrogen gas would contain approximately 6.022 x 10^23 molecules.
Both nitrogen and oxygen exist at standard temperature and pressure as diatomic molecules. Therefore, the relative masses of equal numbers of molecules of the substance will the same as the ratios of their atomic masses, which are 15.9994 for oxygen and 14.0067 for nitrogen. The mass of oxygen that contains the same number of molecules as 42 g of nitrogen is 42(15.9994/14.0067) or 48 g, to the justified number of significant digits.
To calculate the mass of 2.50 x 10^4 molecules of nitrogen gas, you need to know the molecular weight of nitrogen. The molar mass of nitrogen (N2) is approximately 28.02 g/mol. Using this information, you can then calculate the mass of 2.50 x 10^4 molecules of nitrogen gas.
To determine the number of molecules in 140g of nitrogen gas, you first need to convert the mass of nitrogen gas to moles using its molar mass. The molar mass of nitrogen gas (N2) is 28 g/mol. Once you have the number of moles of nitrogen gas, you can use Avogadro's number (6.022 x 10^23 molecules/mol) to calculate the number of molecules present in 140g of nitrogen gas.
Yes, air molecules do have mass. Air is made up of various gases such as nitrogen, oxygen, and carbon dioxide, and each of these gas molecules contributes to the overall mass of the air.
Since gases occupy the same volume at STP regardless of their identity, a 5 L cylinder will contain the same number of gas particles for both nitrogen and neon. However, nitrogen is heavier than neon, so it will contain a greater mass of gas particles.
To determine the number of nitrogen molecules in 12.88g of nitrogen gas, you first need to convert grams to moles using the molar mass of nitrogen (28.02 g/mol). Then, you can use Avogadro's number (6.022 x 10^23) to find the number of molecules in that number of moles.
To find the number of molecules in 67.9 g of nitrogen (N), you first need to convert the mass (in grams) to moles using the molar mass of nitrogen (28.02 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 molecules/mol) to calculate the number of molecules.