Step1: Divide given # of molecules by Avogadro's number: 2.84x10e22 / 6.02x10e23 = 0.47mol. Step2: Multiply moles by molar mass of N2: 0.47(28) = 13.2g N2 gas.
The mass of 2,84 x 1022 molecules of nitrogen gas is 1,32 g.
(600 - 32)/2 = 284° c
Use the Ideal Gas Equation ; PV = nRT Hence n(moles) = PV/RT P = 5.9 Atm = 597817.5 Pa V = 5L = 5.0 x 10^-6 m^3 R = Gas Constant = 8.314 m^3.Pa .K^-1 mol^-1 T = 11oC = 284 K Substituting n = 597817.5 Pa X 5.0 x 10^06 m^3 / 8.314 m^3.Pa.K-1 mol^-1 x 284 K n = 1.29 x 10^-3 moles. = 0.00129 moles
Chemical symbol - H2S Relative Density - 1.89 Auto ignition temp- 260oC Flammability- Very flammable, distinctive blue flame Low Explosive limit - 2.3% in air by volume Upper explosive limit - 46% in air by volume Colour - colorless, invisible Odour - strong rotten egg Vapour pressure - 17.7 atm. At 20oC Boiling point - -600C Melting point- -83oC Reactivity - dangerous with acids and oxidizers Solubility - yes in water, hydrocarbons, alcohol Quoted from the national safety council data sheet 1-284-67
284
284
To find 10 percent of a value, multiply the value by 0.1. In this instance, 0.1 x 284 = 28.4. Therefore, if you are referring to a unit of mass, ten percent of 284 pounds is equal to 28.4 pounds, while ten percent of £284 is equal to £28.40.
284=CCLXXXIV
factors of 284 are 1, 2, 4, 71, 142, 284
157-284 = -127
You need at least two numbers to find a GCF.
The factors of 284 are: 1, 2, 4, 71, 142, 284
A number that 284 is divisible by is 24
The factors of 284 are 1, 2, 4, 71, 142, and 284. The prime factors of 284 are 2 x 2 x 71.1, 2, 4, 71, 142, 284
284 = CCLXXXIV
284 = CCLXXXIV