550 g of nitrogen dioxide is equal to 11,94 moles.
To find the number of grams in 5.0x10^22 molecules of nitrogen monoxide (NO), you need to convert the number of molecules to moles and then from moles to grams. First, calculate the number of moles by dividing the number of molecules by Avogadro's number (6.022x10^23 molecules/mol). Then, use the molar mass of NO (30.01 g/mol) to convert moles to grams.
15 grams of nitrogen are equal to 1,071 moles.
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
As a rule of thumb, the atomic mass of an element equals the number of grams of that element equals a mole. Since the atomic mass of Nitrogen is 14, there are 14 grams in one mole of Nitrogen. Next, we just have to divide 42 by 14 and we get our answer: There are 2.9988 moles in 42 grams of Nitrogen.
The answer is 24,92 g nitrogen.
To find the grams of nitrogen dioxide needed, first calculate the moles of nitrogen monoxide using Avogadro's number. Then, use the balanced chemical equation to determine the moles of nitrogen dioxide required. Finally, convert moles to grams using the molar mass of nitrogen dioxide.
To find the number of grams in 5.0x10^22 molecules of nitrogen monoxide (NO), you need to convert the number of molecules to moles and then from moles to grams. First, calculate the number of moles by dividing the number of molecules by Avogadro's number (6.022x10^23 molecules/mol). Then, use the molar mass of NO (30.01 g/mol) to convert moles to grams.
To find the number of moles in 10.0 g of nitrogen dioxide (NO2), you first need to find the molar mass of NO2, which is approximately 46.01 g/mol. Then, divide the given mass by the molar mass to get the number of moles. In this case, 10.0 g / 46.01 g/mol ≈ 0.22 moles of nitrogen dioxide.
15 grams of nitrogen are equal to 1,071 moles.
To find the number of moles, you need to first convert 21.4 mg of nitrogen dioxide to grams by dividing by 1000 (since 1 gram = 1000 mg). Then, calculate the moles using the molar mass of nitrogen dioxide (NO2), which is 46.01 g/mol. 21.4 mg is equal to 0.0214 grams. Dividing 0.0214 g by the molar mass of NO2 gives you approximately 0.00047 moles of nitrogen dioxide.
To calculate the weight of nitric acid produced from 18.5 grams of nitrogen dioxide, you need to consider the stoichiometry of the reaction. The balanced chemical equation is: 2NO2 + H2O -> HNO3 + NO From the equation, we see that 2 moles of nitrogen dioxide produce 1 mole of nitric acid. First, convert 18.5 grams of nitrogen dioxide to moles, then use the mole ratio to find the moles of nitric acid produced. Finally, convert the moles of nitric acid to grams using the molar mass of nitric acid.
There are 29/14, or just over 2 moles of nitrogen in 19 grams.
To determine the number of nitrogen molecules in 12.88g of nitrogen gas, you first need to convert grams to moles using the molar mass of nitrogen (28.02 g/mol). Then, you can use Avogadro's number (6.022 x 10^23) to find the number of molecules in that number of moles.
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
To calculate the number of moles of carbon dioxide in 19 grams, divide the given mass by the molar mass of carbon dioxide, which is approximately 44 grams/mol. Therefore, 19 grams of carbon dioxide is equal to 19/44 ≈ 0.43 moles.
Multiply the number of moles by the molecular weight.
3 x 12 = 36 moles of Nitrogen atoms N or 18 moles of Nitrogen molecules N2