To answer this you must first be given the mass of the sample or at least percentage and molecular formula that phosphorus is in
it is 20456678
there are 0.675moles
4.00
The gram atomic mass of phosphorus is 30.9738, and by definition, a mole of such atoms contains Avogadro's Number of atoms. Therefore, 100 g of phosphorus contains 100/30.9738 or 3.23 moles, to the justified number of significant digits.
mole = mass/molar mass mass=2.3 grams molar mass=30.97 2.3/30.97=0.0742 moles
Since 14 (4+10) moles of P4O10 contains 4 moles of Phosphorus, 8 moles of P4O10 will contain :: (8 x 4)/14 = 2.286 moles of Phosphorus
3,42 moles of phosphorus trichloride have 469,6686 g.
it is 20456678
4,70 moles of tetraphosphorus decaoxide contain 582,56 g phosphorus.
there are 0.675moles
8,75 moles of oxygen are needed.
Quite a few! 392 grams phosphorous (1 mole P/30.97 grams) = 12.7 moles phosphorous ===================
4.00
The number of phosphorus atoms is 63,181.10e23.
The gram atomic mass of phosphorus is 30.9738, and by definition, a mole of such atoms contains Avogadro's Number of atoms. Therefore, 100 g of phosphorus contains 100/30.9738 or 3.23 moles, to the justified number of significant digits.
Molar mass of P2O5 is 142gmol-1. You need 17.2 moles of p.
mole = mass/molar mass mass=2.3 grams molar mass=30.97 2.3/30.97=0.0742 moles