Determine the molar mass of NO2 using the subscripts in the formula and the atomic weights in grams from the periodic table.
1 mole NO2 = (1 x 14.0067g N) + (2 x 15.9994g O) = 46.0055g NO2
Calculate the moles NO2 by dividing the given mass by the molar mass.
25.5g NO2 x (1mol NO2/46.0055g NO2) = 0.554mol NO2
To find the number of molecules in 25.0 g of NO2, you can start by converting the mass to moles using the molar mass of NO2. Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
To calculate the number of moles in 25.6 g of NO2, you need to divide the given mass by the molar mass of NO2, which is 46.01 g/mol. Moles = 25.6 g / 46.01 g/mol = 0.556 moles. Therefore, there are 0.556 moles of NO2 in 25.6 g.
If the reaction is not specified, we can't determine the exact moles of NO formed from NO2 based on this information alone. The reaction and stoichiometry are needed to calculate the moles of NO produced from 8.44 moles of NO2.
To determine the grams of oxygen needed to produce 4.50 moles of NO2, use the coefficients in the balanced equation. In this case, 7 moles of O2 are required to produce 4 moles of NO2. Calculate: (4.50 moles of NO2) * (7 moles of O2 / 4 moles of NO2) = 7.88 moles of O2. Finally, convert moles to grams using the molar mass of O2 (32.00 g/mol): 7.88 moles * 32.00 g/mol = 252.16 grams of O2.
The molar mass of NO2 is 46.01 g/mol. Therefore, 3.00 moles of NO2 have a mass of 138.03 grams (3.00 moles x 46.01 g/mol).
4.651024 molecules of NO2 equals 7,721 moles.
To find the number of molecules in 25.0 g of NO2, you can start by converting the mass to moles using the molar mass of NO2. Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
To determine the number of molecules in 19.6 g of NO2, you first need to calculate the number of moles in the sample. Then, you can use Avogadro's number (6.022 x 10^23 molecules per mole) to convert moles to molecules.
It takes 2 moles of NO to form 2 moles of NO2, so to form 4.67 moles of NO2 you would need 4.67 moles of NO.
N2O5(g) → 4NO2(g) + O2(g)
To calculate the number of moles in 25.6 g of NO2, you need to divide the given mass by the molar mass of NO2, which is 46.01 g/mol. Moles = 25.6 g / 46.01 g/mol = 0.556 moles. Therefore, there are 0.556 moles of NO2 in 25.6 g.
If the reaction is not specified, we can't determine the exact moles of NO formed from NO2 based on this information alone. The reaction and stoichiometry are needed to calculate the moles of NO produced from 8.44 moles of NO2.
To determine the grams of oxygen needed to produce 4.50 moles of NO2, use the coefficients in the balanced equation. In this case, 7 moles of O2 are required to produce 4 moles of NO2. Calculate: (4.50 moles of NO2) * (7 moles of O2 / 4 moles of NO2) = 7.88 moles of O2. Finally, convert moles to grams using the molar mass of O2 (32.00 g/mol): 7.88 moles * 32.00 g/mol = 252.16 grams of O2.
To find the number of moles in 1.18 g of NO2, you need to divide the given mass by the molar mass of NO2. The molar mass of NO2 is approximately 46 g/mol. So, 1.18 g / 46 g/mol = roughly 0.026 moles of NO2.
There are 4.81 x 10^23 atoms of nitrogen in 2.50 moles of NO2. This is because each molecule of NO2 contains 1 atom of nitrogen.
To find the number of moles in 19 g of NO2, we first need to determine the molar mass of NO2, which is 46.01 g/mol. Next, we divide the given mass by the molar mass: 19 g / 46.01 g/mol ≈ 0.413 moles of NO2.
The molar mass of NO2 is 46.01 g/mol. Therefore, 3.00 moles of NO2 have a mass of 138.03 grams (3.00 moles x 46.01 g/mol).