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how many moles of NO2 are in 7.4 mol N2O5?
N2O5(g) → 4NO2(g) + O2(g)
4) How many moles are in 1.18 g of NO2?
To find the number of moles in 1.18 g of NO2, you need to divide the given mass by the molar mass of NO2. The molar mass of NO2 is approximately 46 g/mol. So, 1.18 g / 46 g/mol = roughly 0.026 moles of NO2.
How many moles are in 19 g of NO2?
To find the number of moles in 19 g of NO2, we first need to determine the molar mass of NO2, which is 46.01 g/mol. Next, we divide the given mass by the molar mass: 19 g / 46.01 g/mol ≈ 0.413 moles of NO2.
What is the equilibrium constant for the reaction so2 (g) no2 (g) so3 (g) no (g)?
SO2(g) + NO2(g) ==> SO3(g) + NO(g)Keq = [SO3][NO]/[SO2][NO2] Without knowing concentrations, one cannot calculate the actual value of Keq.
What is the equilibrium constant for the reaction SO2(g) plus NO2(g) --- SO3(g) plus NO(g)?
The equilibrium constant for the reaction SO2(g) + NO2(g) ⇌ SO3(g) + NO(g) is given by the expression Kc = [SO3][NO]/[SO2][NO2], where square brackets denote molar concentrations. The numerical value of this equilibrium constant would depend on the specific conditions of the reaction.
How many molecules are in 25.0 g NO2?
To find the number of molecules in 25.0 g of NO2, you can start by converting the mass to moles using the molar mass of NO2. Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
how many moles of NO2 are in 7.4 mol N2O5?
N2O5(g) → 4NO2(g) + O2(g)
4) How many moles are in 1.18 g of NO2?
To find the number of moles in 1.18 g of NO2, you need to divide the given mass by the molar mass of NO2. The molar mass of NO2 is approximately 46 g/mol. So, 1.18 g / 46 g/mol = roughly 0.026 moles of NO2.
How many moles are in 25.6 g of NO2?
To calculate the number of moles in 25.6 g of NO2, you need to divide the given mass by the molar mass of NO2, which is 46.01 g/mol. Moles = 25.6 g / 46.01 g/mol = 0.556 moles. Therefore, there are 0.556 moles of NO2 in 25.6 g.
How many moles of molecules are in 25.5g of NO2?
Determine the molar mass of NO2 using the subscripts in the formula and the atomic weights in grams from the periodic table. 1 mole NO2 = (1 x 14.0067g N) + (2 x 15.9994g O) = 46.0055g NO2 Calculate the moles NO2 by dividing the given mass by the molar mass. 25.5g NO2 x (1mol NO2/46.0055g NO2) = 0.554mol NO2
How many kg are in 196 g?
196 g = 0.196 kgTo convert from g to kg, divide by 1000.
How many moles are in 19 g of NO2?
To find the number of moles in 19 g of NO2, we first need to determine the molar mass of NO2, which is 46.01 g/mol. Next, we divide the given mass by the molar mass: 19 g / 46.01 g/mol ≈ 0.413 moles of NO2.
How many grams of nitrogen dioxide must react with water to produce 5.00x10 22 molecules of nitrogen monoxide?
To produce 5.00x10^22 molecules of nitrogen monoxide (NO), you need an equal number of molecules of nitrogen dioxide (NO2). With the balanced chemical equation 2NO2 + H2O → 2NO + 2HNO3, you can calculate the mass of nitrogen dioxide needed using the molar masses of NO2 and NO.
What is the equilibrium constant for the reaction so2 (g) no2 (g) so3 (g) no (g)?
SO2(g) + NO2(g) ==> SO3(g) + NO(g)Keq = [SO3][NO]/[SO2][NO2] Without knowing concentrations, one cannot calculate the actual value of Keq.
What is the equilibrium constant for the reaction SO2(g) plus NO2(g) SO3(g) plus NO(g)?
SO2(g) + NO2(g) ==> SO3(g) + NO(g)Keq = [SO3][NO]/[SO2][NO2] Without knowing concentrations, one cannot calculate the actual value of Keq.
What is the equilibrium constant for the reaction SO2(g) plus NO2(g) --- SO3(g) plus NO(g)?
The equilibrium constant for the reaction SO2(g) + NO2(g) ⇌ SO3(g) + NO(g) is given by the expression Kc = [SO3][NO]/[SO2][NO2], where square brackets denote molar concentrations. The numerical value of this equilibrium constant would depend on the specific conditions of the reaction.
How would the equilibrium change if NO2 were added to SO2(g) NO2(g) NO(g) SO3(g) heat?
The amount of NO2 and SO2 eould
