4.651024 molecules of NO2 equals 7,721 moles.
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will get half the number of moles of NO2. So, you will have 0.2 moles of nitric acid.
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will end up with half the moles of nitrogen dioxide (NO2)...so you will have 0.2 moles.
Molar mass NO2 = 46.0 g/mole1.18 g NO2 x 1 mol NO2/46.0 g = 0.0257 moles NO2 (to 3 significant figures)
4.67
1 mole NO2 = 46.0055g = 6.022 x 1023 molecules 19.6g NO2 x 6.022 x 1023 molecules/46.0055g = 2.57 x 1023 molecules NO2
Determine the molar mass of NO2 using the subscripts in the formula and the atomic weights in grams from the periodic table. 1 mole NO2 = (1 x 14.0067g N) + (2 x 15.9994g O) = 46.0055g NO2 Calculate the moles NO2 by dividing the given mass by the molar mass. 25.5g NO2 x (1mol NO2/46.0055g NO2) = 0.554mol NO2
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will get half the number of moles of NO2. So, you will have 0.2 moles of nitric acid.
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will end up with half the moles of nitrogen dioxide (NO2)...so you will have 0.2 moles.
Molecular mass of nitrogen dioxide, NO2 = 14.0+2(16) = 46.0Amount of NO2 = 25.6/46.0 = 0.557molThere are 0.557 moles of NO2 in a 25.6g sample.
Molar mass NO2 = 46.0 g/mole1.18 g NO2 x 1 mol NO2/46.0 g = 0.0257 moles NO2 (to 3 significant figures)
Balanced equation. 3NO2 + H2O -> 2HNO3 + NO 8.44 moles NO2 (1 mole NO/3 moles NO2) = 2.81 moles NO formed
4.67
4.50 moles NO2 X (46 grams NO2) / (1 mole NO2) x (4 moles NO2) / (7 moles O2) x (1 mole O2) / (32 gm O2) = 3.70 grams O2
1 mole NO2 = 46.0055g = 6.022 x 1023 molecules 19.6g NO2 x 6.022 x 1023 molecules/46.0055g = 2.57 x 1023 molecules NO2
0.41
10 grams NO2 (1 mole NO2/46.01 grams) = 0.217 moles nitrogen dioxide ======================
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