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How many moles are in 25.6 g of NO2?
To calculate the number of moles in 25.6 g of NO2, you need to divide the given mass by the molar mass of NO2, which is 46.01 g/mol. Moles = 25.6 g / 46.01 g/mol = 0.556 moles. Therefore, there are 0.556 moles of NO2 in 25.6 g.
How many moles of molecules are in 25.5g of NO2?
Determine the molar mass of NO2 using the subscripts in the formula and the atomic weights in grams from the periodic table. 1 mole NO2 = (1 x 14.0067g N) + (2 x 15.9994g O) = 46.0055g NO2 Calculate the moles NO2 by dividing the given mass by the molar mass. 25.5g NO2 x (1mol NO2/46.0055g NO2) = 0.554mol NO2
4NH3 7O2 4NO2 6H2O how many grams of oxygen are necessary to produce 4.50 moles of NO2?
To determine the grams of oxygen needed to produce 4.50 moles of NO2, use the coefficients in the balanced equation. In this case, 7 moles of O2 are required to produce 4 moles of NO2. Calculate: (4.50 moles of NO2) * (7 moles of O2 / 4 moles of NO2) = 7.88 moles of O2. Finally, convert moles to grams using the molar mass of O2 (32.00 g/mol): 7.88 moles * 32.00 g/mol = 252.16 grams of O2.
What mass of NO2 is formed when NO reacts with 384g O2?
To determine the mass of NO2 formed when NO reacts with O2, we need to write and balance the chemical equation for the reaction. The balanced equation is 2NO + O2 -> 2NO2. From the equation, we see that 2 moles of NO will react with 1 mole of O2 to produce 2 moles of NO2. Next, we need to calculate the number of moles of O2 present in 384g using its molar mass. Finally, we can use the mole ratio from the balanced equation to find the mass of NO2 formed.
How many molecules are in 25.0 g NO2?
To find the number of molecules in 25.0 g of NO2, you can start by converting the mass to moles using the molar mass of NO2. Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
How many moles are in 25.6 g of NO2?
To calculate the number of moles in 25.6 g of NO2, you need to divide the given mass by the molar mass of NO2, which is 46.01 g/mol. Moles = 25.6 g / 46.01 g/mol = 0.556 moles. Therefore, there are 0.556 moles of NO2 in 25.6 g.
How many moles of molecules are in 25.5g of NO2?
Determine the molar mass of NO2 using the subscripts in the formula and the atomic weights in grams from the periodic table. 1 mole NO2 = (1 x 14.0067g N) + (2 x 15.9994g O) = 46.0055g NO2 Calculate the moles NO2 by dividing the given mass by the molar mass. 25.5g NO2 x (1mol NO2/46.0055g NO2) = 0.554mol NO2
4) How many moles are in 1.18 g of NO2?
To find the number of moles in 1.18 g of NO2, you need to divide the given mass by the molar mass of NO2. The molar mass of NO2 is approximately 46 g/mol. So, 1.18 g / 46 g/mol = roughly 0.026 moles of NO2.
How many moles are in 19 g of NO2?
To find the number of moles in 19 g of NO2, we first need to determine the molar mass of NO2, which is 46.01 g/mol. Next, we divide the given mass by the molar mass: 19 g / 46.01 g/mol ≈ 0.413 moles of NO2.
How many moles are there in 10.0 of nitrogen dioxide?
To find the number of moles in 10.0 g of nitrogen dioxide (NO2), you first need to find the molar mass of NO2, which is approximately 46.01 g/mol. Then, divide the given mass by the molar mass to get the number of moles. In this case, 10.0 g / 46.01 g/mol ≈ 0.22 moles of nitrogen dioxide.
4NH3 7O2 4NO2 6H2O how many grams of oxygen are necessary to produce 4.50 moles of NO2?
To determine the grams of oxygen needed to produce 4.50 moles of NO2, use the coefficients in the balanced equation. In this case, 7 moles of O2 are required to produce 4 moles of NO2. Calculate: (4.50 moles of NO2) * (7 moles of O2 / 4 moles of NO2) = 7.88 moles of O2. Finally, convert moles to grams using the molar mass of O2 (32.00 g/mol): 7.88 moles * 32.00 g/mol = 252.16 grams of O2.
What mass of NO2 is formed when NO reacts with 384g O2?
To determine the mass of NO2 formed when NO reacts with O2, we need to write and balance the chemical equation for the reaction. The balanced equation is 2NO + O2 -> 2NO2. From the equation, we see that 2 moles of NO will react with 1 mole of O2 to produce 2 moles of NO2. Next, we need to calculate the number of moles of O2 present in 384g using its molar mass. Finally, we can use the mole ratio from the balanced equation to find the mass of NO2 formed.
How many molecules are in 25.0 g NO2?
To find the number of molecules in 25.0 g of NO2, you can start by converting the mass to moles using the molar mass of NO2. Then, use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
How many moles no must react to form 4.67 moles no2?
It takes 2 moles of NO to form 2 moles of NO2, so to form 4.67 moles of NO2 you would need 4.67 moles of NO.
What is the mass of 99.01of NO2 at STP?
To find the mass of 99.01 moles of NO2 at STP (Standard Temperature and Pressure), you can use the ideal gas law. At STP, one mole of any gas occupies 22.4 L, so 99.01 moles of NO2 would occupy 99.01 x 22.4 = 2219.02 L. Using the molar mass of NO2 (46.01 g/mol), you can calculate the mass by multiplying the number of moles by the molar mass. So, 99.01 moles x 46.01 g/mol = 4546.46 grams.
Approximately how many moles are in 300 grams of sulfur?
To determine the number of moles in 300 grams of sulfur, you need to know the molar mass of sulfur. The molar mass of sulfur is 32.06 g/mol. You can calculate the number of moles by dividing the given mass by the molar mass: 300 g / 32.06 g/mol ≈ 9.35 moles.
How many moles of no2 are present in 138.08?
Assuming you mean 138.08 grams, you set up a direct proportion between the molar mass of NO2 and your given mass. NO2 comes in at 46g/mol (14+16+16), and your proportion should be 46/1=138.08/x. Solve for x to get approx. 3 moles.
