Assuming you mean 138.08 grams, you set up a direct proportion between the molar mass of NO2 and your given mass. NO2 comes in at 46g/mol (14+16+16), and your proportion should be 46/1=138.08/x. Solve for x to get approx. 3 moles.
The reaction to form nitrogen dioxide using nitric oxide is; 2NO(g) + O2(g) -> 2NO2(g) As the stoichiometry between the substances are 1:1, 1.35 moles of nitrogen monoxide is needed.
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The answer is 5,213.10 ex.23.
Ga is Gallium and NO2 is the nitrite anion. Thus, Ga(NO2)3 is gallium nitrite.
1.5 moles of N2O5 Each molecule of NO3 contains one atom of nitrogen, so 3 moles of the compound will contain 3 moles of N atoms. However, N2O5 molecules each contain two nitrogen atoms, so each mole of N2O5 has two moles of nitrogen. So, in order to have three moles of N atoms, you need only 3/2 = 1.5 moles of N2O5.
If the reaction is not specified, we can't determine the exact moles of NO formed from NO2 based on this information alone. The reaction and stoichiometry are needed to calculate the moles of NO produced from 8.44 moles of NO2.
It takes 2 moles of NO to form 2 moles of NO2, so to form 4.67 moles of NO2 you would need 4.67 moles of NO.
To calculate the number of moles in 25.6 g of NO2, you need to divide the given mass by the molar mass of NO2, which is 46.01 g/mol. Moles = 25.6 g / 46.01 g/mol = 0.556 moles. Therefore, there are 0.556 moles of NO2 in 25.6 g.
To determine the grams of oxygen needed to produce 4.50 moles of NO2, use the coefficients in the balanced equation. In this case, 7 moles of O2 are required to produce 4 moles of NO2. Calculate: (4.50 moles of NO2) * (7 moles of O2 / 4 moles of NO2) = 7.88 moles of O2. Finally, convert moles to grams using the molar mass of O2 (32.00 g/mol): 7.88 moles * 32.00 g/mol = 252.16 grams of O2.
To find the number of moles in 1.18 g of NO2, you need to divide the given mass by the molar mass of NO2. The molar mass of NO2 is approximately 46 g/mol. So, 1.18 g / 46 g/mol = roughly 0.026 moles of NO2.
There are 4.81 x 10^23 atoms of nitrogen in 2.50 moles of NO2. This is because each molecule of NO2 contains 1 atom of nitrogen.
Determine the molar mass of NO2 using the subscripts in the formula and the atomic weights in grams from the periodic table. 1 mole NO2 = (1 x 14.0067g N) + (2 x 15.9994g O) = 46.0055g NO2 Calculate the moles NO2 by dividing the given mass by the molar mass. 25.5g NO2 x (1mol NO2/46.0055g NO2) = 0.554mol NO2
To find the number of moles in 19 g of NO2, we first need to determine the molar mass of NO2, which is 46.01 g/mol. Next, we divide the given mass by the molar mass: 19 g / 46.01 g/mol ≈ 0.413 moles of NO2.
4.651024 molecules of NO2 equals 7,721 moles.
The molar mass of NO2 is 46.01 g/mol. Therefore, 3.00 moles of NO2 have a mass of 138.03 grams (3.00 moles x 46.01 g/mol).
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will get half the number of moles of NO2. So, you will have 0.2 moles of nitric acid.
N2O5(g) → 4NO2(g) + O2(g)