Starting with the formula:
2HNO3 --> H2O + NO2
If you have 0.4 moles of nitric acid (HNO3), you will get half the number of moles of NO2.
So, you will have 0.2 moles of nitric acid.
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will end up with half the moles of nitrogen dioxide (NO2)...so you will have 0.2 moles.
20 moles of NaOH needed to neutralize 20 moles of nitric acid
Magnesium react with nitric acid and magnesium nitrate is obtained.
4 moles HNO3 (63.018 grams/1 mole HNO3) = 252 grams nitric acid ================
ahsu
Starting with the formula: 2HNO3 --> H2O + NO2 If you have 0.4 moles of nitric acid (HNO3), you will end up with half the moles of nitrogen dioxide (NO2)...so you will have 0.2 moles.
20 moles of NaOH needed to neutralize 20 moles of nitric acid
Magnesium react with nitric acid and magnesium nitrate is obtained.
4 moles HNO3 (63.018 grams/1 mole HNO3) = 252 grams nitric acid ================
Sulphuric acid
Lead nitrate is obtained.
ahsu
3Cu + 8HNO3 ----> 3Cu(NO3)2 + 2NO + 4H2O is the equation if it is dilute nitric acid. In concentrated nitric acid the equation is different. So 3 moles of copper produce 2 moles of NO. Therefore it requires 6 moles of copper to produce 4 moles of NO.
1+7+(8x3) =32 =32x2 (2 moles) =64
The answer is 0,07 moles Ca(OH)2.
Sulfuric acid is not obtained from water.
Sulfuric acid and nitric acid are obtained.