0
To convert moles to grams, multiply the number of moles by the molar mass of the compound. The molar mass of barium nitrite (Ba(NO2)2) can be calculated as: 1Ba + 2(NO2) = 137.33 + 2(46.01) = 229.35 g/mol. So, 4.50 moles of barium nitrite would be 4.50 moles x 229.35 g/mol = 1032.08 grams of barium nitrite.
What else can I help you with?
How many grams of barium chloride are there in 286 moles?
To convert moles to grams, you need to use the molar mass of barium chloride, which is 208.23 g/mol. Multiply the number of moles (286 moles) by the molar mass to find the grams of barium chloride: 286 moles * 208.23 g/mol = 59,545.78 grams.
.0306 mol of barium hydroxide are added to a 5.00 M solution of hydrochloric acid in a neutralization reaction that produces water and barium chloride How many grams of barium chloride mw equals 208.2?
First, calculate the moles of HCl in the reaction using the volume and molarity provided. Since it is a 1:1 neutralization reaction, the moles of Ba(OH)2 are equal to the moles of HCl. Next, calculate the mass of barium chloride using the molar mass provided and the moles of BaCl2 produced in the reaction.
How many nitrogen atoms are in 18.8 g of barium nitride?
Barium nitride is Ba3N2 (from the rules of ionic bonding). Its molar mass is 439 grams/mole (from the periodic table), so 18.8 grams of it is 0.0428 moles (by algebraic direct proportion). Multiply this by Avogadro's number (6.02x1023; the number of particles in 1 mole) and you get 2.58x1022 formula units of barium nitride, and there are 2 nitrogen atoms per formula unit, so double it to 5.16x1022 atoms of nitrogen.
How many moles in 60 grams of H2O?
1 mole is equal to 18 grams of H2O, so 60 grams is 3.33 moles.
How many grams are in 2.8 moles of gold?
The molar mass of gold is approximately 197 grams/mol. To convert moles to grams, you multiply the number of moles by the molar mass. Therefore, 2.8 moles of gold would be approximately 2.8 * 197 = 551.6 grams.
How many moles of barium are present in a sample having a mass of 22.3 grams?
To determine the number of moles present, we first need to find the molar mass of barium (Ba), which is approximately 137.33 g/mol. Next, we use the formula n = m/M, where n is the number of moles, m is the mass of the sample (22.3 grams), and M is the molar mass (137.33 g/mol). By substituting these values, we find that there are approximately 0.162 moles of barium in the sample.
How many grams of barium chloride are there in 286 moles?
To convert moles to grams, you need to use the molar mass of barium chloride, which is 208.23 g/mol. Multiply the number of moles (286 moles) by the molar mass to find the grams of barium chloride: 286 moles * 208.23 g/mol = 59,545.78 grams.
How many grams of barium sulfate can be produced from 20.8 g of barium chloride?
To determine the grams of barium sulfate produced from 20.8 g of barium chloride, we first need to consider the balanced chemical reaction between barium chloride (BaCl₂) and sodium sulfate (Na₂SO₄) to produce barium sulfate (BaSO₄) and sodium chloride (NaCl). The molar mass of barium chloride is approximately 137.33 g/mol (for Ba) + 2 × 35.45 g/mol (for Cl) = 137.33 + 70.90 = 208.23 g/mol. The molar mass of barium sulfate is about 233.39 g/mol. Using stoichiometry: Calculate moles of BaCl₂: ( \text{moles} = \frac{20.8 , \text{g}}{208.23 , \text{g/mol}} \approx 0.100 , \text{mol} ). Since the reaction produces 1 mole of BaSO₄ for every mole of BaCl₂, 0.100 moles of BaCl₂ will produce 0.100 moles of BaSO₄. Convert moles of BaSO₄ to grams: ( 0.100 , \text{mol} \times 233.39 , \text{g/mol} \approx 23.34 , \text{g} ). Thus, approximately 23.34 grams of barium sulfate can be produced from 20.8 grams of barium chloride.
With 188 garms of barium chloride there would be how much moles?
First, you want to figure out how many grams 1 mol of barium is. Look at the periodic table of elements. (www.webelements.com) Barium is Ba. Scroll down a little bit after clicking and you will see atomic weight. It is 137g. Now get the atomic weight for chlorine. It is Cl. The atomic weight is 35.5g. Just add them together. 137+35.5 = 172.5g = 1 mol of barium chloride. For 188g, just divide it by 172.5g. Which is 1.09 moles.
How many grams of barium chloride are needed to make 100. grams of barium sulfate?
89.3
What is 16 grams of oxygen how many moles?
16 grams of oxygen how many moles is 0,5 moles.
How many GRAMS of barium bromide BaBr2 are present in 3.56 moles of this compound?
1058 grams How to find it; moles (n) = mass (m) / molar mass (M) Or rearranging, m = n*M Looking at the periodic table to find M for BaBr2, we get, M = 137.33 + 79.9*2 = 297.13 So, m = 3.56 * 297.13 = 1058 g
How many moles of barium sulfate are produced from 0.100 mole of barium chloride?
Since both barium chloride and barium sulfate contain one mole of barium atoms pert mole of compound, the moles of barium sulfate will be the same, 0.100, when barium has the limiting concentration in the production of the sulfate.
How many grams of solid barium hydroxide are needed to exactly neutralize 14.7 mL of a 0.597 M perchloric acid solution?
To find the number of moles of perchloric acid, use the formula Molarity (M) = moles/volume (L). Then, since the balanced equation for the reaction is 2 HClO4 + Ba(OH)2 -> Ba(ClO4)2 + 2 H2O, you need 2 moles of Ba(OH)2 for every 2 moles of perchloric acid neutralized. After finding the moles of perchloric acid, convert it to grams of barium hydroxide using the molar mass of Ba(OH)2.
.0306 mol of barium hydroxide are added to a 5.00 M solution of hydrochloric acid in a neutralization reaction that produces water and barium chloride How many grams of barium chloride mw equals 208.2?
First, calculate the moles of HCl in the reaction using the volume and molarity provided. Since it is a 1:1 neutralization reaction, the moles of Ba(OH)2 are equal to the moles of HCl. Next, calculate the mass of barium chloride using the molar mass provided and the moles of BaCl2 produced in the reaction.
How many grams of barium chloride are needed to make 100 grams of barium sulfate?
Since barium sulfate and barium chloride have a 1:1 molar ratio, you would need the same amount of barium chloride as barium sulfate, so 100 grams.
How many grams of barium chloride are needed to make 20 mL of a 2m solution?
To prepare a 2 m solution of barium chloride (BaCl₂), you need to know the molarity (moles per liter) and the molecular weight of BaCl₂, which is approximately 208.23 g/mol. For a 2 m solution, you need 2 moles per kilogram of solvent. Since 20 mL is 0.02 kg, you would need 0.04 moles of BaCl₂ (2 moles/kg × 0.02 kg). Multiplying 0.04 moles by the molar mass (208.23 g/mol) gives approximately 8.33 grams of barium chloride.
