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.0306 mol of barium hydroxide are added to a 5.00 M solution of hydrochloric acid in a neutralization reaction that produces water and barium chloride How many grams of barium chloride mw equals 208.2?
First, calculate the moles of HCl in the reaction using the volume and molarity provided. Since it is a 1:1 neutralization reaction, the moles of Ba(OH)2 are equal to the moles of HCl. Next, calculate the mass of barium chloride using the molar mass provided and the moles of BaCl2 produced in the reaction.
How many grams are there in 4.50 moles of barium nitrite?
To convert moles to grams, multiply the number of moles by the molar mass of the compound. The molar mass of barium nitrite (Ba(NO2)2) can be calculated as: 1Ba + 2(NO2) = 137.33 + 2(46.01) = 229.35 g/mol. So, 4.50 moles of barium nitrite would be 4.50 moles x 229.35 g/mol = 1032.08 grams of barium nitrite.
How many moles are in 0.98 grams of Potassium chloride?
To determine the number of moles in 0.98 grams of Potassium chloride, you need to divide the given mass by the molar mass of Potassium chloride. The molar mass of KCl is approximately 74.55 g/mol. So, 0.98 grams / 74.55 g/mol ≈ 0.013 moles of KCl.
How many chloride ions are there in one formula unit of barium chloride?
There are two chloride ions in one formula unit of barium chloride.
How many grams of ammonium chloride are contained in 0.500L of a 2.00M solution?
To find the number of grams of ammonium chloride in 0.500L of a 2.00M solution, we need to use the formula: concentration (M) = moles of solute / volume of solution (L). First, calculate the moles of ammonium chloride present in 0.500L of the solution using C = n/V. Then, convert moles to grams by multiplying by the molar mass of ammonium chloride (NH4Cl).
How many grams of barium chloride are needed to make 100 grams of barium sulfate?
Since barium sulfate and barium chloride have a 1:1 molar ratio, you would need the same amount of barium chloride as barium sulfate, so 100 grams.
How many grams of barium sulfate can be produced from 20.8 g of barium chloride?
To determine the grams of barium sulfate produced from 20.8 g of barium chloride, we first need to consider the balanced chemical reaction between barium chloride (BaCl₂) and sodium sulfate (Na₂SO₄) to produce barium sulfate (BaSO₄) and sodium chloride (NaCl). The molar mass of barium chloride is approximately 137.33 g/mol (for Ba) + 2 × 35.45 g/mol (for Cl) = 137.33 + 70.90 = 208.23 g/mol. The molar mass of barium sulfate is about 233.39 g/mol. Using stoichiometry: Calculate moles of BaCl₂: ( \text{moles} = \frac{20.8 , \text{g}}{208.23 , \text{g/mol}} \approx 0.100 , \text{mol} ). Since the reaction produces 1 mole of BaSO₄ for every mole of BaCl₂, 0.100 moles of BaCl₂ will produce 0.100 moles of BaSO₄. Convert moles of BaSO₄ to grams: ( 0.100 , \text{mol} \times 233.39 , \text{g/mol} \approx 23.34 , \text{g} ). Thus, approximately 23.34 grams of barium sulfate can be produced from 20.8 grams of barium chloride.
How many grams of barium chloride are needed to make 100. grams of barium sulfate?
89.3
How many moles of barium sulfate are produced from 0.100 mole of barium chloride?
Since both barium chloride and barium sulfate contain one mole of barium atoms pert mole of compound, the moles of barium sulfate will be the same, 0.100, when barium has the limiting concentration in the production of the sulfate.
How many moles of BaCl2 barium chloride is necessary to react with the 7.5 moles AgNo3 silver nitrate in 2AgNO3 BaCl-- 2AgCl Ba(NO3)2?
3,75 moles barium chloride
With 188 garms of barium chloride there would be how much moles?
First, you want to figure out how many grams 1 mol of barium is. Look at the periodic table of elements. (www.webelements.com) Barium is Ba. Scroll down a little bit after clicking and you will see atomic weight. It is 137g. Now get the atomic weight for chlorine. It is Cl. The atomic weight is 35.5g. Just add them together. 137+35.5 = 172.5g = 1 mol of barium chloride. For 188g, just divide it by 172.5g. Which is 1.09 moles.
.0306 mol of barium hydroxide are added to a 5.00 M solution of hydrochloric acid in a neutralization reaction that produces water and barium chloride How many grams of barium chloride mw equals 208.2?
First, calculate the moles of HCl in the reaction using the volume and molarity provided. Since it is a 1:1 neutralization reaction, the moles of Ba(OH)2 are equal to the moles of HCl. Next, calculate the mass of barium chloride using the molar mass provided and the moles of BaCl2 produced in the reaction.
How many grams are in four tenths moles of sodium chloride?
23.3772 grams are there in four tenths moles of sodium chloride
How many grams of barium chloride are needed to make 20 mL of a 2m solution?
To prepare a 2 m solution of barium chloride (BaCl₂), you need to know the molarity (moles per liter) and the molecular weight of BaCl₂, which is approximately 208.23 g/mol. For a 2 m solution, you need 2 moles per kilogram of solvent. Since 20 mL is 0.02 kg, you would need 0.04 moles of BaCl₂ (2 moles/kg × 0.02 kg). Multiplying 0.04 moles by the molar mass (208.23 g/mol) gives approximately 8.33 grams of barium chloride.
How many grams are in 0.40 moles of sodium chloride?
0,40 moles of sodium chloride contain 23,376 g.
How many grams are there in 4.50 moles of barium nitrite?
To convert moles to grams, multiply the number of moles by the molar mass of the compound. The molar mass of barium nitrite (Ba(NO2)2) can be calculated as: 1Ba + 2(NO2) = 137.33 + 2(46.01) = 229.35 g/mol. So, 4.50 moles of barium nitrite would be 4.50 moles x 229.35 g/mol = 1032.08 grams of barium nitrite.
How many moles of barium are present in a sample having a mass of 22.3 grams?
To determine the number of moles present, we first need to find the molar mass of barium (Ba), which is approximately 137.33 g/mol. Next, we use the formula n = m/M, where n is the number of moles, m is the mass of the sample (22.3 grams), and M is the molar mass (137.33 g/mol). By substituting these values, we find that there are approximately 0.162 moles of barium in the sample.
