0
What else can I help you with?
.0306 mol of barium hydroxide are added to a 5.00 M solution of hydrochloric acid in a neutralization reaction that produces water and barium chloride How many grams of barium chloride mw equals 208.2?
First, calculate the moles of HCl in the reaction using the volume and molarity provided. Since it is a 1:1 neutralization reaction, the moles of Ba(OH)2 are equal to the moles of HCl. Next, calculate the mass of barium chloride using the molar mass provided and the moles of BaCl2 produced in the reaction.
How many grams are there in 4.50 moles of barium nitrite?
To convert moles to grams, multiply the number of moles by the molar mass of the compound. The molar mass of barium nitrite (Ba(NO2)2) can be calculated as: 1Ba + 2(NO2) = 137.33 + 2(46.01) = 229.35 g/mol. So, 4.50 moles of barium nitrite would be 4.50 moles x 229.35 g/mol = 1032.08 grams of barium nitrite.
How many moles are in 0.98 grams of Potassium chloride?
To determine the number of moles in 0.98 grams of Potassium chloride, you need to divide the given mass by the molar mass of Potassium chloride. The molar mass of KCl is approximately 74.55 g/mol. So, 0.98 grams / 74.55 g/mol ≈ 0.013 moles of KCl.
How many chloride ions are there in one formula unit of barium chloride?
There are two chloride ions in one formula unit of barium chloride.
How many grams of potassium chloride are formed by the decomposition of excess potassium chlorate to yield 3.40 L of oxygen?
To determine the grams of potassium chloride formed, you first need to calculate the moles of oxygen produced by the decomposition of potassium chlorate. Then, use the stoichiometry of the balanced chemical equation to convert moles of oxygen to moles of potassium chloride. Finally, from the molar mass of potassium chloride, you can calculate the grams formed.
How many grams of barium chloride are needed to make 100 grams of barium sulfate?
Since barium sulfate and barium chloride have a 1:1 molar ratio, you would need the same amount of barium chloride as barium sulfate, so 100 grams.
How many grams of barium chloride are needed to make 100. grams of barium sulfate?
89.3
How many moles of barium sulfate are produced from 0.100 mole of barium chloride?
Since both barium chloride and barium sulfate contain one mole of barium atoms pert mole of compound, the moles of barium sulfate will be the same, 0.100, when barium has the limiting concentration in the production of the sulfate.
How many moles of BaCl2 barium chloride is necessary to react with the 7.5 moles AgNo3 silver nitrate in 2AgNO3 BaCl-- 2AgCl Ba(NO3)2?
3,75 moles barium chloride
How many grams are in four tenths moles of sodium chloride?
23.3772 grams are there in four tenths moles of sodium chloride
With 188 garms of barium chloride there would be how much moles?
First, you want to figure out how many grams 1 mol of barium is. Look at the periodic table of elements. (www.webelements.com) Barium is Ba. Scroll down a little bit after clicking and you will see atomic weight. It is 137g. Now get the atomic weight for chlorine. It is Cl. The atomic weight is 35.5g. Just add them together. 137+35.5 = 172.5g = 1 mol of barium chloride. For 188g, just divide it by 172.5g. Which is 1.09 moles.
.0306 mol of barium hydroxide are added to a 5.00 M solution of hydrochloric acid in a neutralization reaction that produces water and barium chloride How many grams of barium chloride mw equals 208.2?
First, calculate the moles of HCl in the reaction using the volume and molarity provided. Since it is a 1:1 neutralization reaction, the moles of Ba(OH)2 are equal to the moles of HCl. Next, calculate the mass of barium chloride using the molar mass provided and the moles of BaCl2 produced in the reaction.
How many grams are in 0.40 moles of sodium chloride?
0,40 moles of sodium chloride contain 23,376 g.
How many grams are there in 4.50 moles of barium nitrite?
To convert moles to grams, multiply the number of moles by the molar mass of the compound. The molar mass of barium nitrite (Ba(NO2)2) can be calculated as: 1Ba + 2(NO2) = 137.33 + 2(46.01) = 229.35 g/mol. So, 4.50 moles of barium nitrite would be 4.50 moles x 229.35 g/mol = 1032.08 grams of barium nitrite.
How many moles of barium are present in a sample having a mass of 22.3 grams?
To determine the number of moles present, we first need to find the molar mass of barium (Ba), which is approximately 137.33 g/mol. Next, we use the formula n = m/M, where n is the number of moles, m is the mass of the sample (22.3 grams), and M is the molar mass (137.33 g/mol). By substituting these values, we find that there are approximately 0.162 moles of barium in the sample.
When silver nitrate reacts with barium chloride silver chloride and barium nitrate are formed How many grams of silver chloride are formed when 10.8 g of silver nitrate reacts with 15 g of barium?
9.11 g
How many grams of NaCl are present in 10.00 moles?
10 moles of sodium chloride have 584,397 g.
