0.8 moles
Explanation:
from the equation we can see,
2
mole
A
l
is needed to react completely with
3
mole
F
e
O
so,
3
moles of
F
e
O
needs
2
moles
A
l
so,
1
mole
F
e
O
needs
2
3
moles
A
l
so,
1.2
mol
F
e
O
needs
2
×
1.2
3
moles
A
l
=
0.8
moles
A
l
I am presuming the chemical reaction here is: 2Al (s) + 3H2SO4 ---> Al2(SO4)3 + 3H2 Based on this, you would set your dimensional analysis up as: 15.2 g Al . 1 mol Al . 3 mol H2SO4 . 98 g H2SO4 = 165.5 g H2SO4 __________ 27 g Al _ 2 mol Al ___1 mol H2SO4 Please ignore the lines in the denominator - this is only to keep the spacing accurate in the answer's format.
To find the total number of moles needed, use the formula n = M x V, where n is the number of moles, M is the molarity, and V is the volume in liters. Thus, n = 2.0 mol/L x 5.0 L = 10 moles of H2SO4 are needed.
There are 5 moles of sulfur in 5 moles of H2SO4, as there is 1 mole of sulfur in each mole of H2SO4.
2,89 moles of aluminium contain 17,40398707673.1023 atoms.
1.5 moles of Hydrogen. In every mole of H2SO4 (Sulfuric Acid) there are 2 moles of Hydrogen atoms. So, in .75 moles of Sulfuric Acid, there would be 1.5 (double the moles of sulfuric acid) moles of Hydrogen.
To calculate the moles of H2SO4 in a titration, you can use the formula: moles Molarity x Volume. First, determine the molarity of the H2SO4 solution. Then, measure the volume of the solution used in the titration. Multiply the molarity by the volume to find the moles of H2SO4.
Molarity = moles of solute/volume of solution ( so, not a great molarity expected ) 4.60 grams H2SO4 (1mol H2SO4/98.086g) = 0.0469 moles/450ml = 1.04 X 10^-4 Molarity.
To find the number of moles of H2SO4 in 100 mL of 12M H2SO4 solution, you first need to convert the volume to liters, which is 0.1 L. Then, you multiply the volume in liters by the molarity to get the moles of H2SO4. So, 0.1 L * 12 mol/L = 1.2 moles of H2SO4.
To calculate the mass of H2SO4 required, first calculate the number of moles needed using the formula: moles = molarity x volume (in liters). Then, multiply the moles by the molar mass of H2SO4 (98.08 g/mol) to find the mass. moles = 0.15 mol/L x 0.75 L = 0.1125 mol mass = 0.1125 mol x 98.08 g/mol ≈ 11.04 g of H2SO4.
In the reaction 4 moles of aluminum will react with 3 moles of oxygen to form 2 moles of aluminum oxide. Since we have 2.0 moles of aluminum, we would need (2.0 mol Al) x (3 mol O2 / 4 mol Al) = 1.5 moles of O2 to react with it.
These reagents doesn't react.
9.62 Mol H2SO4 ( 6.022 X 10^23/1mol H2SO4 ) = 5.79 X 10^24 molecules of H2SO4