I am presuming the chemical reaction here is:
2Al (s) + 3H2SO4 ---> Al2(SO4)3 + 3H2
Based on this, you would set your dimensional analysis up as:
15.2 g Al . 1 mol Al . 3 mol H2SO4 . 98 g H2SO4 = 165.5 g H2SO4
__________ 27 g Al _ 2 mol Al ___1 mol H2SO4
Please ignore the lines in the denominator - this is only to keep the spacing accurate in the answer's format.
Yes, sulfuric acid (H2SO4) will dissolve in water. When sulfuric acid is added to water, it dissociates into hydronium ions and bisulfate ions, resulting in a homogeneous solution. The process of dissolving the acid in water is exothermic and generates heat.
For complete reaction, the equation is 3 H2SO4 + 2 Al = Al2(SO4)3 + 3 H2.
To prepare a 0.005 M solution of H2SO4 with pH 4, you can first calculate the concentration of H+ ions needed to achieve a pH of 4. Then, use the dissociation of H2SO4 to determine the amount of H2SO4 needed to provide that concentration of H+ ions. Finally, dilute the calculated amount of H2SO4 with water to reach the desired volume of the solution.
To find the volume of 0.270 M H2SO4 needed to react with 46.0 mL of 0.100 M NaOH, you need to use the stoichiometry of the balanced equation. The balanced equation tells you that 1 mole of H2SO4 reacts with 2 moles of NaOH. From this information, you can set up a ratio using the concentrations and volumes of the two solutions to calculate the volume of 0.270 M H2SO4 needed.
how 2.5N H2SO4 prepared from concentrated H2SO4
When aluminum oxide (Al2O3) is added to sulfuric acid (H2SO4), it typically reacts to form aluminum sulfate (Al2(SO4)3) and water (H2O). This is a common reaction in which the sulfuric acid breaks down the aluminum oxide to form the aluminum sulfate salt.
Yes, sulfuric acid (H2SO4) will dissolve in water. When sulfuric acid is added to water, it dissociates into hydronium ions and bisulfate ions, resulting in a homogeneous solution. The process of dissolving the acid in water is exothermic and generates heat.
To prepare a 0.005 M solution of H2SO4 with pH 4, you can first calculate the concentration of H+ ions needed to achieve a pH of 4. Then, use the dissociation of H2SO4 to determine the amount of H2SO4 needed to provide that concentration of H+ ions. Finally, dilute the calculated amount of H2SO4 with water to reach the desired volume of the solution.
For complete reaction, the equation is 3 H2SO4 + 2 Al = Al2(SO4)3 + 3 H2.
You need 252 g sulfuric acid.
To find the volume of 0.270 M H2SO4 needed to react with 46.0 mL of 0.100 M NaOH, you need to use the stoichiometry of the balanced equation. The balanced equation tells you that 1 mole of H2SO4 reacts with 2 moles of NaOH. From this information, you can set up a ratio using the concentrations and volumes of the two solutions to calculate the volume of 0.270 M H2SO4 needed.
how 2.5N H2SO4 prepared from concentrated H2SO4
The balanced chemical equation for the reaction is 1 mol of sulfuric acid reacts with 2 mol of ammonium hydroxide. Therefore, for 8 mol of ammonium hydroxide, 4 mol of sulfuric acid are needed. To calculate the grams of sulfuric acid needed, you would multiply the number of moles by the molar mass of sulfuric acid.
Some strong acid such as H2SO4 (Sulfuric) probably would dissolve copper bronze the quickest.
The balanced chemical equation for the reaction between aluminum and sulfuric acid is: 2Al + 3H2SO4 → Al2(SO4)3 + 3H2. Therefore, 250g of H2SO4 would react with 108g of Al to form 342g of Al2(SO4)3 according to the stoichiometry of the reaction.
The reaction is:2 Al + 3 H2SO4 = Al2(SO4)3 + 3 H2
Nylon will readily dissolve in diluted strong acid or base. ie H2SO4, HCL, NaOH,