How much h2so4 is needed to dissolve a 15.2 gram aluminum block?

Answer 1

I am presuming the chemical reaction here is:

2Al (s) + 3H2SO4 ---> Al2(SO4)3 + 3H2

Based on this, you would set your dimensional analysis up as:

15.2 g Al . 1 mol Al . 3 mol H2SO4 . 98 g H2SO4 = 165.5 g H2SO4

__________ 27 g Al _ 2 mol Al ___1 mol H2SO4

Please ignore the lines in the denominator - this is only to keep the spacing accurate in the answer's format.

Answer 2

The minimum mass of H2SO4 in G you would need to dissolve a 15.2 G aluminum block would be 166 grams of H2SO4. To get the answer you convert the amount of aluminum into moles.