For complete reaction, the equation is 3 H2SO4 + 2 Al = Al2(SO4)3 + 3 H2.
The reaction equation for hydrogen sulfate (H2SO4) and aluminum hydroxide (Al(OH)3) is: 2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O
The balanced chemical equation is: 3H2SO4 + 2Al → Al2(SO4)3 + 3H2. This shows that 3 moles of H2SO4 react with 2 moles of Al. Therefore, using a mole ratio calculation: (18 mol Al) x (3 mol H2SO4 / 2 mol Al) = 27 moles of H2SO4 will react with 18 moles of Al.
I am presuming the chemical reaction here is: 2Al (s) + 3H2SO4 ---> Al2(SO4)3 + 3H2 Based on this, you would set your dimensional analysis up as: 15.2 g Al . 1 mol Al . 3 mol H2SO4 . 98 g H2SO4 = 165.5 g H2SO4 __________ 27 g Al _ 2 mol Al ___1 mol H2SO4 Please ignore the lines in the denominator - this is only to keep the spacing accurate in the answer's format.
Al and AgNO3. Al has a 3plus charge plus 3e negative. 3(Ag positive plus le negative equals Ag). Al plus 3Ag plus is equal to Al with a 3 plus charge plus 3Ag.
This is a single displacement reaction, also known as a replacement reaction or a substitution reaction. In this reaction, aluminum (Al) replaces nickel (Ni) in nickel(II) bromide (NiBr2) to form aluminum bromide (AlBr3) and nickel (Ni).
The reaction is:2 Al + 3 H2SO4 = Al2(SO4)3 + 3 H2
Displacement reaction
In the chemical reaction 2AlCl3 equals 2Al plus 3Cl2, the substances Al and Cl2 are called products. They are formed as a result of the chemical reaction between aluminum chloride (AlCl3).
The reaction equation for hydrogen sulfate (H2SO4) and aluminum hydroxide (Al(OH)3) is: 2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O
The balanced chemical equation is: 3H2SO4 + 2Al → Al2(SO4)3 + 3H2. This shows that 3 moles of H2SO4 react with 2 moles of Al. Therefore, using a mole ratio calculation: (18 mol Al) x (3 mol H2SO4 / 2 mol Al) = 27 moles of H2SO4 will react with 18 moles of Al.
Sulphuric Acid:- H2SO4 Aluminium Hydroxide:- Al(OH)3
This reaction is called "metal-metal exchange reaction".
I am presuming the chemical reaction here is: 2Al (s) + 3H2SO4 ---> Al2(SO4)3 + 3H2 Based on this, you would set your dimensional analysis up as: 15.2 g Al . 1 mol Al . 3 mol H2SO4 . 98 g H2SO4 = 165.5 g H2SO4 __________ 27 g Al _ 2 mol Al ___1 mol H2SO4 Please ignore the lines in the denominator - this is only to keep the spacing accurate in the answer's format.
The reaction between aluminum (Al) and sulfuric acid (H2SO4) to form aluminum sulfate (Al2(SO4)3) and hydrogen gas (H2) is a single displacement or single replacement reaction. In this reaction, aluminum displaces hydrogen from sulfuric acid to form aluminum sulfate and hydrogen gas is formed as a byproduct.
Al and AgNO3. Al has a 3plus charge plus 3e negative. 3(Ag positive plus le negative equals Ag). Al plus 3Ag plus is equal to Al with a 3 plus charge plus 3Ag.
The balanced chemical equation for the reaction between aluminum and sulfuric acid is: 2Al + 3H2SO4 → Al2(SO4)3 + 3H2. Therefore, 250g of H2SO4 would react with 108g of Al to form 342g of Al2(SO4)3 according to the stoichiometry of the reaction.
Al + H2so4= AlSo2 + H2o