2,89 moles of aluminium contain 17,40398707673.1023 atoms.
1,46 moles of aluminum fluoride contain 35,16848.10e23 atoms.
0.125 moles x 6.02x10^23 atoms/mole = 7.53x10^22 atoms
To find the number of moles of atoms in 9 grams of aluminum, you can use the molar mass of aluminum, which is approximately 27 g/mol. Dividing the mass of aluminum (9 g) by its molar mass (27 g/mol) gives you about 0.33 moles of aluminum. Since each aluminum atom is a single atom, there are also 0.33 moles of atoms in 9 grams of aluminum.
6.3x10^24 aluminum atoms represent 1 mole of aluminum atoms because Avogadro's number is approximately 6.022x10^23.
There are approximately 1.93 x 10^24 atoms in 3.20 moles of aluminum. This calculation is based on Avogadro's number, which states that 1 mole of any substance contains 6.022 x 10^23 particles (atoms, molecules, ions, etc.).
1,46 moles of aluminum fluoride contain 35,16848.10e23 atoms.
In one mole of aluminum III oxide (Al2O3), there are 2 moles of aluminum atoms (since there are 2 aluminum atoms in each formula unit of Al2O3) and 3 moles of oxygen atoms. Therefore, one mole of aluminum III oxide contains 2 + 3 = 5 moles of atoms. Avogadro's number (6.022 x 10^23) of atoms can be found in one mole of any substance.
To find the number of moles, you first need to convert the number of atoms to moles using Avogadro's number, which is 6.022 x 10^23 atoms/mol. Then divide the given number of atoms by Avogadro's number to get the answer.
Aluminum sulfide has a molar mass of 150.16 grams per mole. This means there are 0.666 moles present, or 4.01 E23 molecules. Each molecule of Al2S3 has 2 aluminum atoms, so there are 8.02 E23 atoms of aluminum present.
0.125 moles x 6.02x10^23 atoms/mole = 7.53x10^22 atoms
Answer: 8.6 Mol. To Find this you need to set up your dimensional analysis as: (5.2x1024atoms)(1 mol/6.022x1023atoms)= 8.6 Mol. Your atoms cancel out, so finish working the math out and your left with moles of Aluminum.
6.3x10^24 aluminum atoms represent 1 mole of aluminum atoms because Avogadro's number is approximately 6.022x10^23.
2,2 moles of plutonium: 13,248711938.1023 atoms.
There are approximately 1.93 x 10^24 atoms in 3.20 moles of aluminum. This calculation is based on Avogadro's number, which states that 1 mole of any substance contains 6.022 x 10^23 particles (atoms, molecules, ions, etc.).
1 mole of atoms = 6.022 x 1023 atoms 6.2mol x 6.022 x 1023 atoms/mol = 3.7 x 1024 atoms Al
The gram molecular mass of Al2O3 is 2(26.982) + 3 (15.999) = 101.96. Therefore, the number of moles of Al2O3 is 291.257/101.96 = 2.857 moles. Each mole contains two moles of aluminum atoms; therefore the number of aluminum atoms in this mass equals 2 X 2.857 X 6.022 X 1023 = 3.4410 X 1024 atoms.
Well, one mole is 26.98 g, right? Your ten grams is thus (10/26.98) moles.