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The gram molecular mass of Al2O3 is 2(26.982) + 3 (15.999) = 101.96. Therefore, the number of moles of Al2O3 is 291.257/101.96 = 2.857 moles. Each mole contains two moles of aluminum atoms; therefore the number of aluminum atoms in this mass equals 2 X 2.857 X 6.022 X 1023 = 3.4410 X 1024 atoms.
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What weight of aluminum may be obatained from 1kg of aluminum oxide?
Al2O3 on thermal decomposition gives Al & O2. 1 mole Al2O3 gives 2 mole Al. 102 kg Al2O3 gives 54kg Al 1 kg Al2O3 gives 0.512 kg Al.
What is the number of aluminum and oxygen atoms in 4Al2O3?
To determine the number of atoms in 4Al2O3, we first need to calculate the molar mass of Al2O3. Aluminum has a molar mass of 26.98 g/mol, oxygen has a molar mass of 16.00 g/mol. Therefore, the molar mass of Al2O3 is (226.98) + (316.00) = 101.96 g/mol. Next, we convert 4 moles of Al2O3 to grams: 4 moles * 101.96 g/mol = 407.84 grams. Finally, we use Avogadro's number to find the number of atoms: 407.84 grams / 101.96 g/mol * 6.022 x 10^23 atoms/mol = 2.42 x 10^24 atoms of aluminum and oxygen in 4Al2O3.
What is the gram formula mass of Al2O3?
The gram formula mass of Al2O3 is 101.96 g/mol. This is calculated by adding the atomic masses of two aluminum atoms (26.98 g/mol) and three oxygen atoms (16.00 g/mol).
How many moles of aluminum oxide are present in a sample having a mass of 178.43g?
For this you need the atomic (molecular) mass of Al2O3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Al2O3= 102 grams408 grams Al / (102 grams) = 4.00 moles Al
How many grams of oxygen are needed to produce 95.6 g of aluminum oxide?
To find the amount of oxygen needed to produce 95.6 g of aluminum oxide (Al2O3), first calculate the molar mass of Al2O3 (101.96 g/mol). Then, set up a ratio using the molar mass ratio of oxygen to Al2O3 (3:2). Calculate the amount of oxygen needed using the given mass of Al2O3 and the molar ratio.
What does al2o3 stand for?
Aluminum oxide has the molecular formula of Al2O3. It is composed of aluminum (Al) and oxygen (O) and is 102.0 grams per mole.
What weight of aluminum may be obatained from 1kg of aluminum oxide?
Al2O3 on thermal decomposition gives Al & O2. 1 mole Al2O3 gives 2 mole Al. 102 kg Al2O3 gives 54kg Al 1 kg Al2O3 gives 0.512 kg Al.
What is the number of aluminum and oxygen atoms in 4Al2O3?
To determine the number of atoms in 4Al2O3, we first need to calculate the molar mass of Al2O3. Aluminum has a molar mass of 26.98 g/mol, oxygen has a molar mass of 16.00 g/mol. Therefore, the molar mass of Al2O3 is (226.98) + (316.00) = 101.96 g/mol. Next, we convert 4 moles of Al2O3 to grams: 4 moles * 101.96 g/mol = 407.84 grams. Finally, we use Avogadro's number to find the number of atoms: 407.84 grams / 101.96 g/mol * 6.022 x 10^23 atoms/mol = 2.42 x 10^24 atoms of aluminum and oxygen in 4Al2O3.
What is the gram formula mass of Al2O3?
The gram formula mass of Al2O3 is 101.96 g/mol. This is calculated by adding the atomic masses of two aluminum atoms (26.98 g/mol) and three oxygen atoms (16.00 g/mol).
How many grams of aluminum are in 25.0g of aluminum oxide?
To find how many grams of aluminum are in 25.0g of aluminum oxide, first, determine the molar mass of aluminum oxide (Al2O3), which is 101.96 g/mol. Next, calculate the molar mass of aluminum (Al), which is 26.98 g/mol. Then, set up a ratio using the molar masses to find the amount of aluminum in 25.0g of aluminum oxide: (2 mol Al / 1 mol Al2O3) x (26.98 g Al / 101.96 g Al2O3) x 25.0g Al2O3 = 6.63g of aluminum.
How many grams of oxygen are in 5.75 moles of aluminum oxide?
Well to find how many grams are in moles you would eventually multiply the mole by the molar mass. The molar mass of aluminum oxide would be 101.96 ( you would find that by multiplying the atomic mass of al by 2 and o by 3 and adding them together). But the molar mass of Oxygen is just about 48 (rounded to 16 instead of 15.9994)5.75 moles of Al2O3 X 48 g oxygen/1 mole of Al2O3=276 g oxygen in 5.75 mole Al2O3
What is the molarity of a solution in which 51 grams of aluminum oxide Al2O3 is dissolved in 500 mL of solution?
Need moles aluminum oxide first. 51 grams Al2O3 (1 mole Al2O3/101.96 grams) = 0.5002 moles Al2O3 ======================Now, Molarity = moles of solute/Liters of solution (500 ml = 0.500 Liters ) Molarity =0.5002 moles Al2O3/0.500 Liters = 1.0 M Al2O3 solution ----------------------------
Avogadro's number of aluminum atoms has a mass equal to?
Thast is one mole. 26.98 grams/per mole is the mass.
How many aluminum atoms are there in a mass of 16.2 grams?
To calculate the number of atoms in 16.2 grams of aluminum, you first need to determine the number of moles using the molar mass of aluminum (26.98 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. Finally, multiply the number of moles by Avogadro's number to find the number of aluminum atoms in 16.2 grams.
How many moles of aluminum oxide are present in a sample having a mass of 178.43g?
For this you need the atomic (molecular) mass of Al2O3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Al2O3= 102 grams408 grams Al / (102 grams) = 4.00 moles Al
What is the average mass of a single aluminum atom in grams?
6.02x1023 atoms = 1 Mole 5.6x1025 atoms = 5.6x1025 / 6.02x1023 = 93.02 moles Molecular weight of Aluminum = 27.0 g Therefore 93.02 Moles of Aluminum = 27.0 x 93.02 =2511.54 g 5.6x1025 atoms of Aluminum weighs 2511.54 grams.
What is the number of atoms in 4.1x10-5 of Al?
I assume you mean grams of aluminum. 4.1 X 10 -5 grams aluminum (1 mole Al/26.98 grams)(6.022 X 1023/1 mole Al) = 9.2 X 1017 atoms of aluminum ------------------------------------------
