The gram molecular mass of Al2O3 is 2(26.982) + 3 (15.999) = 101.96. Therefore, the number of moles of Al2O3 is 291.257/101.96 = 2.857 moles. Each mole contains two moles of aluminum atoms; therefore the number of aluminum atoms in this mass equals 2 X 2.857 X 6.022 X 1023 = 3.4410 X 1024 atoms.
16.2 grams aluminum (1 mole Al/26.98 grams)(6.022 X 1023/1 mole Al) = 3.62 X 1023 atoms of aluminum ------------------------------------------
6.02x1023 atoms = 1 Mole 5.6x1025 atoms = 5.6x1025 / 6.02x1023 = 93.02 moles Molecular weight of Aluminum = 27.0 g Therefore 93.02 Moles of Aluminum = 27.0 x 93.02 =2511.54 g 5.6x1025 atoms of Aluminum weighs 2511.54 grams.
For this you need the atomic (molecular) mass of Al2O3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Al2O3= 102 grams408 grams Al / (102 grams) = 4.00 moles Al
There are 13 electrons in an Aluminum atom.
The number of aluminium atoms ia 0,44638973.10e23.
Aluminum oxide has the molecular formula of Al2O3. It is composed of aluminum (Al) and oxygen (O) and is 102.0 grams per mole.
Need moles aluminum oxide first. 51 grams Al2O3 (1 mole Al2O3/101.96 grams) = 0.5002 moles Al2O3 ======================Now, Molarity = moles of solute/Liters of solution (500 ml = 0.500 Liters ) Molarity =0.5002 moles Al2O3/0.500 Liters = 1.0 M Al2O3 solution ----------------------------
16. 2 grams aluminum (1 mole Al/26.98 grams)(6.022 X 1023/1 mole Al) = 3.62 X 1023 atoms of aluminum -------------------------------------------
16.2 grams aluminum (1 mole Al/26.98 grams)(6.022 X 1023/1 mole Al) = 3.62 X 1023 atoms of aluminum ------------------------------------------
Aluminium oxide, Al2O3; the atomic weight of aluminum is 26,981 538 6.
6.02x1023 atoms = 1 Mole 5.6x1025 atoms = 5.6x1025 / 6.02x1023 = 93.02 moles Molecular weight of Aluminum = 27.0 g Therefore 93.02 Moles of Aluminum = 27.0 x 93.02 =2511.54 g 5.6x1025 atoms of Aluminum weighs 2511.54 grams.
I assume you mean grams of aluminum. 4.1 X 10 -5 grams aluminum (1 mole Al/26.98 grams)(6.022 X 1023/1 mole Al) = 9.2 X 1017 atoms of aluminum ------------------------------------------
For this you need the atomic (molecular) mass of Al2O3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Al2O3= 102 grams408 grams Al / (102 grams) = 4.00 moles Al
There are 13 electrons in an Aluminum atom.
Aluminum sulfide has a molar mass of 150.16 grams per mole. This means there are 0.666 moles present, or 4.01 E23 molecules. Each molecule of Al2S3 has 2 aluminum atoms, so there are 8.02 E23 atoms of aluminum present.
The number of aluminium atoms ia 0,44638973.10e23.
Well to find how many grams are in moles you would eventually multiply the mole by the molar mass. The molar mass of aluminum oxide would be 101.96 ( you would find that by multiplying the atomic mass of al by 2 and o by 3 and adding them together). But the molar mass of Oxygen is just about 48 (rounded to 16 instead of 15.9994)5.75 moles of Al2O3 X 48 g oxygen/1 mole of Al2O3=276 g oxygen in 5.75 mole Al2O3