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To determine the number of atoms in 4Al2O3, we first need to calculate the molar mass of Al2O3. Aluminum has a molar mass of 26.98 g/mol, oxygen has a molar mass of 16.00 g/mol. Therefore, the molar mass of Al2O3 is (226.98) + (316.00) = 101.96 g/mol.

Next, we convert 4 moles of Al2O3 to grams: 4 moles * 101.96 g/mol = 407.84 grams.

Finally, we use Avogadro's number to find the number of atoms: 407.84 grams / 101.96 g/mol * 6.022 x 10^23 atoms/mol = 2.42 x 10^24 atoms of aluminum and oxygen in 4Al2O3.

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7mo ago

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