16. 2 grams aluminum (1 mole Al/26.98 grams)(6.022 X 1023/1 mole Al)
= 3.62 X 1023 atoms of aluminum
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Aluminum sulfide has a molar mass of 150.16 grams per mole. This means there are 0.666 moles present, or 4.01 E23 molecules. Each molecule of Al2S3 has 2 aluminum atoms, so there are 8.02 E23 atoms of aluminum present.
To determine the grams of aluminum hydroxide obtained from 17.2 grams of aluminum sulfide, we need to consider the stoichiometry of the reaction between aluminum sulfide and water to form aluminum hydroxide. Given the balanced chemical equation, we can calculate the molar mass of aluminum hydroxide and use it to convert the mass of aluminum sulfide to grams of aluminum hydroxide formed.
The gram atomic mass of aluminium is 26.9815, and the gram atomic mass of chlorine is 35.453. The formula shows that there are three chlorine atoms for each aluminium atom in the compound. Therefore, the mass fraction of aluminium in the compound is 26.9815/[26.9815 + 3*(35.453)] or about 0.20235004, and the grams of aluminium present are 20.24, to the justified number of significant digits. _______________________________________ *An exact integer.
To find the mass of 0.92 mol of aluminum chromate (Al2(CrO4)3), you need to calculate the molar mass of aluminum chromate. The molar mass is calculated by adding the atomic masses of all the atoms in the chemical formula. The molar mass of aluminum chromate is approximately 469.32 g/mol. Therefore, the mass of 0.92 mol of aluminum chromate is approximately 431.42 grams.
The mass of one mole of atoms is equal to the atomic mass of the element expressed in grams. This is known as the molar mass. For example, the molar mass of carbon (C) is 12 grams per mole, of oxygen (O) is 16 grams per mole, and so on.
Thast is one mole. 26.98 grams/per mole is the mass.
To find the number of moles of atoms in 9 grams of aluminum, you can use the molar mass of aluminum, which is approximately 27 g/mol. Dividing the mass of aluminum (9 g) by its molar mass (27 g/mol) gives you about 0.33 moles of aluminum. Since each aluminum atom is a single atom, there are also 0.33 moles of atoms in 9 grams of aluminum.
To calculate the number of aluminum atoms in 3.24g of aluminum, first find the molar mass of aluminum, which is 26.98 g/mol. Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert grams to atoms. Divide 3.24g by the molar mass of aluminum and then multiply by Avogadro's number to find approximately 3.01 x 10^22 atoms of aluminum in 3.24g.
The molar mass of aluminum is 26.98 g/mol. To find the number of atoms in 16.2 g of aluminum, first calculate moles (16.2 g / 26.98 g/mol), then use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of atoms.
6.02x1023 atoms = 1 Mole 5.6x1025 atoms = 5.6x1025 / 6.02x1023 = 93.02 moles Molecular weight of Aluminum = 27.0 g Therefore 93.02 Moles of Aluminum = 27.0 x 93.02 =2511.54 g 5.6x1025 atoms of Aluminum weighs 2511.54 grams.
To find the number of aluminum atoms in 30 grams, you first need to determine the number of moles of aluminum using its molar mass (26.98 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms.
the mass of one mole od aluminum is 65.2 grams
The gram molecular mass of Al2O3 is 2(26.982) + 3 (15.999) = 101.96. Therefore, the number of moles of Al2O3 is 291.257/101.96 = 2.857 moles. Each mole contains two moles of aluminum atoms; therefore the number of aluminum atoms in this mass equals 2 X 2.857 X 6.022 X 1023 = 3.4410 X 1024 atoms.
The molar mass of anhydrous aluminum chloride is 133,34 grams.
Aluminum sulfide has a molar mass of 150.16 grams per mole. This means there are 0.666 moles present, or 4.01 E23 molecules. Each molecule of Al2S3 has 2 aluminum atoms, so there are 8.02 E23 atoms of aluminum present.
To determine the grams of aluminum hydroxide obtained from 17.2 grams of aluminum sulfide, we need to consider the stoichiometry of the reaction between aluminum sulfide and water to form aluminum hydroxide. Given the balanced chemical equation, we can calculate the molar mass of aluminum hydroxide and use it to convert the mass of aluminum sulfide to grams of aluminum hydroxide formed.
To determine how many moles of aluminum are produced from 33 grams, divide the given mass by the molar mass of aluminum, which is approximately 26.98 g/mol. So, 33 g / 26.98 g/mol ≈ 1.22 moles of aluminum are produced.