16. 2 grams aluminum (1 mole Al/26.98 grams)(6.022 X 1023/1 mole Al)
= 3.62 X 1023 atoms of aluminum
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Aluminum sulfide has a molar mass of 150.16 grams per mole. This means there are 0.666 moles present, or 4.01 E23 molecules. Each molecule of Al2S3 has 2 aluminum atoms, so there are 8.02 E23 atoms of aluminum present.
Atomic mass of carbon: 12.0 grams1.90 grams × (6.02 × 1023 atoms) / (12.0 grams) = 9.53 × 1022 atoms C
mass of CaF3 = 61.96g mass of Al2CO3 =61.104 g
There are 13 protons in aluminum and 13 electrons. So, there are 13 atoms in aluminum. In oxygen, there are 8 protons and 8 electrons. thus there are 8 atoms. EDIT: This answer is absolutely and completely incorrect. (Dr.J.)
Gold has a molar mass of 196.96655 grams per mole. 100 grams then is equal to .508 moles which makes 3.059 E23 atoms of gold.
16.2 grams aluminum (1 mole Al/26.98 grams)(6.022 X 1023/1 mole Al) = 3.62 X 1023 atoms of aluminum ------------------------------------------
Aluminum sulfide has a molar mass of 150.16 grams per mole. This means there are 0.666 moles present, or 4.01 E23 molecules. Each molecule of Al2S3 has 2 aluminum atoms, so there are 8.02 E23 atoms of aluminum present.
6.02x1023 atoms = 1 Mole 5.6x1025 atoms = 5.6x1025 / 6.02x1023 = 93.02 moles Molecular weight of Aluminum = 27.0 g Therefore 93.02 Moles of Aluminum = 27.0 x 93.02 =2511.54 g 5.6x1025 atoms of Aluminum weighs 2511.54 grams.
Thast is one mole. 26.98 grams/per mole is the mass.
the mass of one mole od aluminum is 65.2 grams
The molar mass of anhydrous aluminum chloride is 133,34 grams.
The gram molecular mass of Al2O3 is 2(26.982) + 3 (15.999) = 101.96. Therefore, the number of moles of Al2O3 is 291.257/101.96 = 2.857 moles. Each mole contains two moles of aluminum atoms; therefore the number of aluminum atoms in this mass equals 2 X 2.857 X 6.022 X 1023 = 3.4410 X 1024 atoms.
What is the mass, in grams, of 2 × 1012 atoms of potassium?
use the following formula to determine number of moles number of moles = mass given/molar mass (mass on periodic table) one mole = 6.02x10^23 particles (molecules or atoms depending on substance) hence whichever mass has the greatest number of moles has the more atoms
Atomic mass of Ag: 107.9 grams5.00 grams × (6.02 × 1023 atoms) / (107.9 grams) = 2.79 × 1022 atoms Ag
For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023.5.0 grams Fe / (55.9 grams) × (6.02 × 1023 atoms) = 5.38 × 1022 atoms
For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023. AlCl3= 133.5 grams10.5 grams Cu / (133.5 grams) × (6.02 × 1023 atoms) = 4.73 × 1022 atoms