Well, one mole is 26.98 g, right? Your ten grams is thus (10/26.98) moles.
The answer is 6 moles.
108g is 0.238 pound.
According to the periodic table, silver (Ag) has an atomic mass of about 108 grams per mole. If you have 802 grams, set up a direct proportion where 108/1=802/x and solve for x. You get about 7.43 moles of silver.
The reaction between Isopropyl alcohol and oxygen is 2 C3H8O + 9 O2 equals 6 CO2 + 8 H2O. So for every mole of isopropyl alcohol, 4.5 moles of oxygen are consumed. 6.5 grams of C3H8O is .108 moles and 12.3 grams of O2 is .384 moles. This means that O2 is the limiting reactant as it needs .486 moles of O2 to finish.
5.8
31/108 =0.287037037
One mole weights 26.98 grams, so it is arouind 27 g. So 4 moles weight almost 108 grams.
To find the number of moles in 108 grams of HCl, you need to know the molar mass of HCl, which is about 36.5 g/mol. You can then use this molar mass to calculate the number of moles by dividing the given mass by the molar mass. In this case, 108 grams divided by 36.5 g/mol gives you about 2.96 moles of HCl.
The answer is 6 moles.
To calculate the amount of AlO produced, you first need to determine the limiting reactant by converting the grams of Al and FeO to moles, then comparing their molar ratios. Once you find the limiting reactant, use stoichiometry to calculate the moles of AlO produced. Finally, convert the moles of AlO to grams. The same steps can be used to find the amount of Fe produced.
Answer: 108 lb = 48.99 kg
I assume you mean 3.55 grams of silver. Don't forget your units! Silver (Ag, #47) has an atomic mass of about 108 grams per mole. Set up a direct proportion: 108/1=3.55/x, where x is the unknown number of moles in 3.55 grams Ag. Solve for x to get approx. 0.033 moles Ag. Multiply this number by Avogadro's constant of 6.02x1023 to get the number of representative particles. So, 0.033(6.02x1023)=1.99x1022 atoms of silver.
To find the number of atoms in 0.0001 grams of silver (Ag), first determine the number of moles in 0.0001 grams using the molar mass of Ag (108 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, 0.0001 g of Ag is equal to 6.94 x 10^16 Ag atoms.
108g is 0.238 pound.
in dimensional analysis (for chemistry) your usually converting substances to moles or grams to figure out whatever you need for the problem. For units, you always want the units to cancel out as 1/7 * 7 cancels out to 1/1 or 1.for example, if i want to find the molar mass of 3.00 moles of Carbon (C), this is your set up:(3.00 moles Carbon)(36.03 grams Carbon/1mole Carbon)=108.09/1 grams Carbon=108 grams Carbon(using sig. figs)in the problem above, since moles are the numerator, and you want to find how many grams are in 3 moles of carbon, you want to set up a ratio of moles per grams. Ratios can be flip flopped based on which units you need. So i look at the periodic table and see there are 12.01 grams per 1 mole, setting the ratio up so that when it multiplies 3 moles of carbon, the moles cancel and im left with grams of carbon, the units i want. It seems complicated but gets easier with practice.
Oxidation-reduction reaction:Ag^+(aq) + Al(s) ===> Ag(s) + Al^3+ or looked at another way... 3AgNO3(aq) + Al(s) ===> Al(NO3)3(aq) + 3Ag(s) moles AgNO3 present = 92.8 g x 1 mole/170 g =0.546 moles moles Al present = 1.34 g x 1 mole/26.9 g = 0.0498 moles Al is limiting based on mole ratio of 3 AgNO3 : 1 Al moles Ag(s) produced = 0.0498 moles Al x 3 moles Ag/mole Al = 0.1494 moles Ag mass of Ag = 0.1494 moles Ag x 108 g/mole = 16.1 g Ag formed
According to the periodic table, silver (Ag) has an atomic mass of about 108 grams per mole. If you have 802 grams, set up a direct proportion where 108/1=802/x and solve for x. You get about 7.43 moles of silver.