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One mole weights 26.98 grams, so it is arouind 27 g.
So 4 moles weight almost 108 grams.
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How many moles of aluminum are present in an aluminum cylinder with a mass of 15 g?
The Answer is.56 moles OR 0.56 moles
How many moles of aluminum are present in 856g of aluminum sample?
Moles = Mass/ Relative Molecular Mass Aluminum forms Al2 compounds, so the relative molecular mass is 2 * 13 = 26. 856/26 = 32.9 (3sf)
Aluminum will react with bromine to form aluminum bromide Al2Br6 What mass of bromine g is needed to form 1.42 mol of Al2Br6?
The gram formula unit or molar mass for aluminum bromide is 533.38.* Therefore, 1.42 moles has a mass of 757.4 grams. The mass of 6 moles of bromine atoms is 479.42. Therefore, the mass fraction of bromine in aluminum bromide is 479.42/757.4 or 0.633, and the mass in grams of bromine required to form 1.42 moles of aluminum bromide is 0.633 X 757.4 or 479 grams, to the justified number of significant digits (limited by the precision given for the number of moles.) ___________________ *This is equal to the sum of (2 times the gram atomic mass of aluminum) and (6 times the gram atomic mass of bromine).
How many moles of aluminum oxide are present in a sample having a mass of 178.43g?
For this you need the atomic (molecular) mass of Al2O3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Al2O3= 102 grams408 grams Al / (102 grams) = 4.00 moles Al
How many grams of aluminum would be in 3.0 moles of aluminum?
Because the atomic mass of aluminum is 26.99, this means that there are 26.99 grams of aluminum in one mole. For 3 moles multiply 26.99 by 3 = 80.97grams.
What is the mass of 0.25 moles of aluminum sulphate?
What is the mass of 0.25 moles of aluminum sulfate
How many moles of aluminum are present in an aluminum cylinder with a mass of 15 g?
The Answer is.56 moles OR 0.56 moles
The mass in grams of 2.8 moles aluminum?
200
How many moles of aluminum are present in 856g of aluminum sample?
Moles = Mass/ Relative Molecular Mass Aluminum forms Al2 compounds, so the relative molecular mass is 2 * 13 = 26. 856/26 = 32.9 (3sf)
How many moles aluminum exist in 100.0 grams of aluminum?
The formular you need is M = n/m (molar mass = amount of substance/mass), or n = m/MAluminium has a molar mass of 26.982 g/mol. The given mass is 3 grams. Therefore:n(Al) = 3g / (26.982g/mol) = 0.11mol
What is the mass in grams for 4.5 moles of aluminum?
2.38 mol Al
How many moles of aluminum ions are in 45.0 g of aluminum oxide?
Steps to take: Write the chemical formula : Al2O3 Calculate the number of moles for aluminum oxide. You should know the formula which is the mass given (0.051g) divided by the Mass of aluminum oxide. Since there is '2' moles of Aluminium you multiplly the number of moles calculated for aluminum oxide by 2. Then you have calculated the number of Ions.
What is the mass of four moles of aluminium?
For this you need the atomic mass of Al. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.00 moles Al × (27.0 grams) = 54.0 grams Al
How would you determine the number of moles of aluminum in 96.7 grams of aluminum?
Number of moles = mass of the sample/atomic weight of Al = 96,7/26,987 = 3,58
Aluminum will react with bromine to form aluminum bromide Al2Br6 What mass of bromine g is needed to form 1.42 mol of Al2Br6?
The gram formula unit or molar mass for aluminum bromide is 533.38.* Therefore, 1.42 moles has a mass of 757.4 grams. The mass of 6 moles of bromine atoms is 479.42. Therefore, the mass fraction of bromine in aluminum bromide is 479.42/757.4 or 0.633, and the mass in grams of bromine required to form 1.42 moles of aluminum bromide is 0.633 X 757.4 or 479 grams, to the justified number of significant digits (limited by the precision given for the number of moles.) ___________________ *This is equal to the sum of (2 times the gram atomic mass of aluminum) and (6 times the gram atomic mass of bromine).
2.91 moles of aluminum are how many grams?
For this you need the atomic mass of Al. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.91 moles Al × (27.0 grams) = 78.6 grams Al
How many moles are in 89.0 grams of aluminum?
all you have to do to fine the moles of any element is divide the given grams by the molar mass (which you can find on a periodic table of elements) Likewise, if you need to find the grams, just multiply the number of moles by molar mass. moles = grams/molar mass grams = moles x molar mass your equation should look like this: moles = 89.0 / 17.0 moles = .471
