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For this you need the Atomic Mass of Al. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.
2.00 moles Al × (27.0 grams) = 54.0 grams Al
What else can I help you with?
How many moles of aluminum are in 10.8 grams?
Well, one mole is 26.98 g, right? Your ten grams is thus (10/26.98) moles.
How many moles of aluminum ions are in 45.0 g of aluminum oxide?
Steps to take: Write the chemical formula : Al2O3 Calculate the number of moles for aluminum oxide. You should know the formula which is the mass given (0.051g) divided by the Mass of aluminum oxide. Since there is '2' moles of Aluminium you multiplly the number of moles calculated for aluminum oxide by 2. Then you have calculated the number of Ions.
How many atoms of aluminum are there in 2.89 moles of metal?
2,89 moles of aluminium contain 17,40398707673.1023 atoms.
How do you calculate the maximum mass of aluminium chloride that can be formed when reacting 15.0g of aluminium with 2.0g chlorine?
2 Al + 3Cl2 --Ã 2AlCl3 so 2 moles of Aluminium atoms react with 3 moles of chlorine molecules or 1 atom of Al reacts with 3 atoms of chlorine. Aluminium has an atomic weight of 27 and Chlorine atoms 35.5. Multiplying by Avagadro's number 1 mole of Al atoms reacts with 3 moles of chlorine atoms. So 27 g of Al reacts with 106.5 g Chlorine (3 x 35.5) to produce 133.5 g AlCl3 15g Al = 15/27 = 0.5556 moles (4 decimal places) 2g Cl = 2/35.5 = 0.0563 moles of chlorine atoms but 3 needed per molecule of AlCl3 so 0.0563/3 = 0.0188 (4 decimal places) maximum number of moles of product possible. 0.0188 x 133.5 = 2.51 g maximum yield.
What is the atomic mass and number of aluminium?
Aluminium is a metal element. Atomic number of it is 13.
How many moles of aluminum are in 10.8 grams?
Well, one mole is 26.98 g, right? Your ten grams is thus (10/26.98) moles.
How many grams Al from 0.4 moles AlCl3?
The mass of aluminium is 11,2 g.
how many moles of Aluminium oxide are in 12.75g of aluminium oxideNeed to know?
To determine the number of moles of aluminum oxide in 12.75g of aluminum oxide, you first need to find the molar mass of aluminum oxide, which is 101.96 g/mol. Then, divide the given mass (12.75g) by the molar mass to find the number of moles. So, 12.75g / 101.96 g/mol ≈ 0.125 moles of aluminum oxide.
What is the mass in grams of 1.05 moles of AlCl3?
The answer is 144,007 g for the anhydrous aluminium chloride.
How many moles of aluminum hydroxide is 39.0g?
Aluminium hydroxide, Al(OH)3 has molar mass 27.0+3(17.0) = 78.0Amount of Al(OH)3 = 39.0/78.0 = 0.500molThere are 0.5 moles of aluminium hydroxide in a 39.0g pure sample.
How many moles of aluminum oxide are present in a sample having a mass of 178.43g?
For this you need the atomic (molecular) mass of Al2O3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Al2O3= 102 grams408 grams Al / (102 grams) = 4.00 moles Al
How many moles of aluminum ions are in 45.0 g of aluminum oxide?
Steps to take: Write the chemical formula : Al2O3 Calculate the number of moles for aluminum oxide. You should know the formula which is the mass given (0.051g) divided by the Mass of aluminum oxide. Since there is '2' moles of Aluminium you multiplly the number of moles calculated for aluminum oxide by 2. Then you have calculated the number of Ions.
How many grams Four moles of methane would have a mass of how many grams?
2344222.445
The formula for methane is CH4. Four moles of methane would have a mass of how many grams?
To calculate the mass of four moles of methane (CH4), we first need to determine the molar mass of methane. The molar mass of CH4 is the sum of the atomic masses of carbon (12.01 g/mol) and hydrogen (1.008 g/mol) multiplied by the number of atoms in the compound. Therefore, the molar mass of CH4 is 12.01 g/mol + 4(1.008 g/mol) = 16.04 g/mol. To find the mass of four moles of methane, we multiply the molar mass by the number of moles: 16.04 g/mol x 4 mol = 64.16 grams. Therefore, four moles of methane would have a mass of 64.16 grams.
How many atoms of aluminum are there in 2.89 moles of metal?
2,89 moles of aluminium contain 17,40398707673.1023 atoms.
The formula for methane is CH4 Four moles of methanes would have a mass of?
The molar mass of methane (CH4) is 16 g/mol. Therefore, four moles of methane would have a mass of 64 grams.
How do you calculate the maximum mass of aluminium chloride that can be formed when reacting 15.0g of aluminium with 2.0g chlorine?
2 Al + 3Cl2 --Ã 2AlCl3 so 2 moles of Aluminium atoms react with 3 moles of chlorine molecules or 1 atom of Al reacts with 3 atoms of chlorine. Aluminium has an atomic weight of 27 and Chlorine atoms 35.5. Multiplying by Avagadro's number 1 mole of Al atoms reacts with 3 moles of chlorine atoms. So 27 g of Al reacts with 106.5 g Chlorine (3 x 35.5) to produce 133.5 g AlCl3 15g Al = 15/27 = 0.5556 moles (4 decimal places) 2g Cl = 2/35.5 = 0.0563 moles of chlorine atoms but 3 needed per molecule of AlCl3 so 0.0563/3 = 0.0188 (4 decimal places) maximum number of moles of product possible. 0.0188 x 133.5 = 2.51 g maximum yield.
