Aluminium hydroxide, Al(OH)3 has molar mass 27.0+3(17.0) = 78.0
Amount of Al(OH)3 = 39.0/78.0 = 0.500mol
There are 0.5 moles of aluminium hydroxide in a 39.0g pure sample.
1
4 moles
16.3106
40 moles of LiOH
In the acid-base reaction where sodium hydroxide and sulfuric acid react, the formula is: H2SO4 + 2NaOH --> Na2SO4 + 2H2O. The coefficients shown are necessary to uphold the law of conservation of mass. So, if you have 17 moles of sulfuric acid, you will need twice as many moles of sodium hydroxide, so the answer is 34 moles NaOH.
98,3 molecules of aluminum hydroxide Al(OH)3 is equivalent to 16,323.10e-23 moles.
1,99 grams of aluminum is equal to 0,0737 moles.
1
10 grams aluminum (1 mole Al/26.98 grams) = 0.37 moles of aluminum ---------------------------------
The Answer is.56 moles OR 0.56 moles
4 moles
4 moles
33 grams aluminum (1 mole Al/26.98 grams) = 1.2 moles of aluminum ================
1,46 moles of aluminum fluoride contain 35,16848.10e23 atoms.
For this you need the atomic (molecular) mass of Al2O3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Al2O3= 102 grams408 grams Al / (102 grams) = 4.00 moles Al
456
0.1 moles