0
What else can I help you with?
How many grams of aluminium hydroxide are obtained from 14.2g of aluminium sulfide?
To determine the grams of aluminum hydroxide produced from 14.2g of aluminum sulfide, first calculate the molar mass of aluminum sulfide by adding the atomic masses of aluminum and sulfur. Then, use the stoichiometry of the balanced chemical equation to find the molar ratio between aluminum sulfide and aluminum hydroxide. Next, convert the 14.2g of aluminum sulfide to moles, and then use the molar ratio to find the moles of aluminum hydroxide produced. Finally, convert the moles of aluminum hydroxide to grams using its molar mass.
How many moles of aluminum oxide are present in a sample having a mass of 178.43g?
For this you need the atomic (molecular) mass of Al2O3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Al2O3= 102 grams408 grams Al / (102 grams) = 4.00 moles Al
In the equation 3Na Plus AlCl30 equals 3NaCl plus Al how many aluminum molecules will be produced if you have 30 molecules of sodium?
If you have 30 molecules of sodium reacting with aluminum chloride (AlCl3), they will produce 10 molecules of aluminum. This is because the balanced equation shows that 3 moles of sodium react with 1 mole of aluminum, producing 1 mole of aluminum.
What is the mole ratio of aluminum to oxygen?
The mole ratio of aluminum to oxygen in aluminum oxide (Al2O3) is 4:3, which means for every 4 moles of aluminum, there are 3 moles of oxygen.
How many moles of sulfur are present in 3 moles of aluminum sulfate?
There are 6 moles of sulfur present in 3 moles of aluminum sulfate, because aluminum sulfate has a 2:3 ratio of aluminum to sulfur.
How do you Convert 42 grams AlOH3 to moles AlOH3?
That is aluminum hydroxide and as a polyatomic ion hydroxide needs to be in parenthesis. Thus; Al(OH)3 This shows aluminum's 3+ oxidation state and the three matching hydroxides 1- state. 42 grams Al(OH)3 ( 1 mole Al(OH)3/78.004 grams) = 0.538 moles Al(OH)3 As significant figures require; 0.54 moles Al(OH)3
How many moles of aluminum hydroxide is 39.0g?
Aluminium hydroxide, Al(OH)3 has molar mass 27.0+3(17.0) = 78.0Amount of Al(OH)3 = 39.0/78.0 = 0.500molThere are 0.5 moles of aluminium hydroxide in a 39.0g pure sample.
How many grams of aluminium hydroxide are obtained from 14.2g of aluminium sulfide?
To determine the grams of aluminum hydroxide produced from 14.2g of aluminum sulfide, first calculate the molar mass of aluminum sulfide by adding the atomic masses of aluminum and sulfur. Then, use the stoichiometry of the balanced chemical equation to find the molar ratio between aluminum sulfide and aluminum hydroxide. Next, convert the 14.2g of aluminum sulfide to moles, and then use the molar ratio to find the moles of aluminum hydroxide produced. Finally, convert the moles of aluminum hydroxide to grams using its molar mass.
Coefficients in front of sulfurous acid plus aluminum hydroxide -- aluminum sulfite plus water?
The balanced chemical equation for the reaction between sulfurous acid and aluminum hydroxide to form aluminum sulfite and water is: 3H2SO3 + 2Al(OH)3 → Al2(SO3)3 + 6H2O This equation shows that 3 moles of sulfurous acid and 2 moles of aluminum hydroxide react to produce 1 mole of aluminum sulfite and 6 moles of water.
What does the chemical equation 2AL2O3 mean?
The chemical equation 2Al2O3 represents the reaction of two aluminum atoms with three oxygen atoms to form two molecules of aluminum oxide. This equation shows that for every two moles of aluminum, three moles of oxygen are required to form two moles of aluminum oxide.
How many moles of aluminum oxide are present in a sample having a mass of 178.43g?
For this you need the atomic (molecular) mass of Al2O3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Al2O3= 102 grams408 grams Al / (102 grams) = 4.00 moles Al
How many moles are in 98.3 grams of aluminum hydroxide Al(OH)3?
To find the number of moles in 98.3 grams of aluminum hydroxide (Al(OH)₃), first calculate its molar mass. The molar mass of Al(OH)₃ is approximately 78.00 g/mol (26.98 g/mol for Al + 3 × 16.00 g/mol for O + 3 × 1.01 g/mol for H). Using the formula ( \text{moles} = \frac{\text{mass}}{\text{molar mass}} ), we have ( \text{moles} = \frac{98.3 , \text{g}}{78.00 , \text{g/mol}} \approx 1.26 , \text{moles} ). So, there are approximately 1.26 moles of aluminum hydroxide in 98.3 grams.
In the equation 3Na Plus AlCl30 equals 3NaCl plus Al how many aluminum molecules will be produced if you have 30 molecules of sodium?
If you have 30 molecules of sodium reacting with aluminum chloride (AlCl3), they will produce 10 molecules of aluminum. This is because the balanced equation shows that 3 moles of sodium react with 1 mole of aluminum, producing 1 mole of aluminum.
When 4 moles of aluminum are allowed to react with an excess of chlorine gas Cl2 how many moles of aluminum chloride are produced?
When 4 moles of aluminum react with an excess of chlorine gas, 4 moles of aluminum chloride are produced. This is because the balanced chemical equation for the reaction is: 2Al + 3Cl2 -> 2AlCl3 This means that 2 moles of aluminum react with 3 moles of chlorine gas to produce 2 moles of aluminum chloride, so 4 moles of aluminum will produce 4 moles of aluminum chloride.
What is the mole ratio of aluminum to oxygen?
The mole ratio of aluminum to oxygen in aluminum oxide (Al2O3) is 4:3, which means for every 4 moles of aluminum, there are 3 moles of oxygen.
How many moles of aluminum are in 1.99 grams of aluminum?
1,99 grams of aluminum is equal to 0,0737 moles.
How many moles of sulfur are present in 3 moles of aluminum sulfate?
There are 6 moles of sulfur present in 3 moles of aluminum sulfate, because aluminum sulfate has a 2:3 ratio of aluminum to sulfur.
