Moles Al2S3 = 14.2 g / 150.16 g/mol =0.9456
the rario between Al2S3 and Al(OH)3 is 1 : 2
moles Al(OH)3 = 2 x 0.9456 =0.1891
Mass Al(OH)3 = 0.1891 mol x 78 g/mol =14.75 g
The molar mass of potassium hydroxide (KOH) is 56.11 g/mol. Therefore, 1 mole of potassium hydroxide weighs 56.11 grams.
It is not possible to convert miles directly to grams without additional information such as the density or molecular weight of potassium sulfide. Can you provide that information?
For this you need the atomic (molecular) mass of Al2O3. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. Al2O3= 102 grams408 grams Al / (102 grams) = 4.00 moles Al
The molecular formula H2S indicates that in every molecule of hydrogen sulfide, there are 2 atoms of hydrogen and 1 atom of sulfur. Therefore, in a 1.0-gram sample of hydrogen sulfide, there would be 0.67 grams of hydrogen (2/3 of 1.0 grams) and 0.33 grams of sulfur (1/3 of 1.0 grams).
To neutralize calcium hydroxide, the molar ratio is 2:1 (2 moles of boric acid for every 1 mole of calcium hydroxide). Calculate the molar mass of boric acid (H3BO3) and calcium hydroxide (Ca(OH)2), then use these values to convert the mass of calcium hydroxide to moles and then to grams of boric acid.
To determine the grams of aluminum hydroxide obtained from 17.2 grams of aluminum sulfide, we need to consider the stoichiometry of the reaction between aluminum sulfide and water to form aluminum hydroxide. Given the balanced chemical equation, we can calculate the molar mass of aluminum hydroxide and use it to convert the mass of aluminum sulfide to grams of aluminum hydroxide formed.
To find the grams of aluminum hydroxide from 15.7 grams of aluminum sulfide, you first need to balance the chemical equation. The balanced equation is 2Al2S3 + 6H2O -> 4Al(OH)3 + 3H2S. Next, calculate the molar mass of aluminum sulfide (Al2S3) and aluminum hydroxide (Al(OH)3), then use the stoichiometry from the balanced equation to find the grams of aluminum hydroxide produced.
266,86 g aluminium chloride are obtained.
The equation for the reaction specified is 2 NaOH + H2S -> Na2S + H2O. Therefore, if the yield were 100 %, two formula masses of sodium hydroxide are required to produce one formula mass of sodium sulfide. The gram formula mass of NaOH is 40.00 and that of sodium sulfide is 78.04. The specified number of grams of sodium hydroxide corresponds to 2.53/40.00 or 0.06325 formula masses and therefore would provide half this many formula masses of sodium sulfide, for a mass of (0.06325)(78.04)/2.000 or 2.568 grams of sodium sulfide. Since the yield is specified as 91.0 %, the actual amount of sodium sulfide produced is 2.25 grams, to the justified number of significant digits.
None, as pure Aluminium is an element which contains only atoms of Aluminium and nothing else.
To calculate the grams of iron II sulfide needed, we start by finding the moles of hydrogen sulfide produced. This is done by dividing the given mass of hydrogen sulfide by its molar mass. Then, we use the balanced chemical equation to determine that for every 4 moles of hydrogen sulfide, 1 mole of iron II sulfide is needed. From this, we find the grams of iron II sulfide required by multiplying the moles of iron II sulfide by its molar mass.
The molar mass of potassium hydroxide (KOH) is 56.11 g/mol. Therefore, 1 mole of potassium hydroxide weighs 56.11 grams.
It is not possible to convert miles directly to grams without additional information such as the density or molecular weight of potassium sulfide. Can you provide that information?
It depends on whether it is iron (II) hydroxide or iron (III) hydroxide.
242.594 g
The molar mass of sodium hydroxide (NaOH) is approximately 40 grams/mol. To find the mass of 25 moles of NaOH, you would multiply the number of moles by the molar mass: 25 mol * 40 g/mol = 1000 grams. So, the mass of 25 moles of sodium hydroxide is 1000 grams.
The molar mass of sodium hydroxide (NaOH) is approximately 40 grams per mole. Therefore, a 6.94 mole sample of sodium hydroxide would contain approximately 278 grams (6.94 moles x 40 grams/mole).