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How many moles of aluminum are in 1.99 grams of aluminum?
1,99 grams of aluminum is equal to 0,0737 moles.
How many moles of aluminum are in 10grams of aluminum?
10 grams aluminum (1 mole Al/26.98 grams) = 0.37 moles of aluminum ---------------------------------
How many grams in 1ounce of copper?
There are approximately 28.35 grams in 1 ounce of copper.
How many grams of aluminum hydroxide are obtained from 17.2 grams of aluminum sulfide?
To determine the grams of aluminum hydroxide obtained from 17.2 grams of aluminum sulfide, we need to consider the stoichiometry of the reaction between aluminum sulfide and water to form aluminum hydroxide. Given the balanced chemical equation, we can calculate the molar mass of aluminum hydroxide and use it to convert the mass of aluminum sulfide to grams of aluminum hydroxide formed.
How many moles of aluminum are produced from 33 grams of aluminum?
To determine how many moles of aluminum are produced from 33 grams, divide the given mass by the molar mass of aluminum, which is approximately 26.98 g/mol. So, 33 g / 26.98 g/mol ≈ 1.22 moles of aluminum are produced.
How many grams of copper does it take to kill you?
10 grams of copper can kill you. But copper sulphate won't kill you. So don't freak out!
How many grams of copper are in a one peso coin containing 75 copper by mass?
A one peso coin weighing 10 grams and containing 75% copper by mass would have 7.5 grams of copper. This is calculated by multiplying the total mass of the coin (10 grams) by the percentage of copper (0.75): 10 grams × 0.75 = 7.5 grams of copper.
How many grams of copper ii sulfate are required to produce 0.48 mol of aluminum iii sulfate?
To find the amount of copper (II) sulfate needed to react with 0.48 mol of aluminum (III) sulfate, start by writing a balanced chemical equation for the reaction between the two salts. From the balanced equation, determine the molar ratio between copper (II) sulfate and aluminum (III) sulfate. Then, use this ratio to calculate the amount of copper (II) sulfate needed to produce 0.48 mol of aluminum (III) sulfate.
How many moles are 4.12 grams aluminum sulfate?
4,12 grams aluminum sulfate is equivalent to 0,012 moles (for the anhydrous salt).
How many grams of copper are in a one peso containing 75 copper by mass?
A one peso coin weighs 20 grams and contains 75% copper by mass. To find the amount of copper, multiply the total mass by the percentage of copper: 20 grams × 0.75 = 15 grams. Therefore, there are 15 grams of copper in a one peso coin.
How many grams of aluminum chloride could be produced from 34.0 grams of aluminum and 39.0 grams of chlorine gas?
To find the limiting reactant, we need to calculate the moles of each reactant. Then, use the stoichiometry of the balanced chemical equation to determine which reactant limits the amount of aluminum chloride that can be produced. Finally, calculate the mass of aluminum chloride produced based on the limiting reactant.
How many grams of aluminum chloride are produced when 54 grams of aluminum react with chlorine gas?
266,86 g aluminium chloride are obtained.
