FeS+2HCl-->FeCl2+H2S Moles of H2S produced equal to moles of FeS used. Moles of H2S=12\34=0.353mol Grams of Fes=0.353*88=31.05g
The formula for potassium hydrogen sulfide is KHS. Another name for this inorganic compound is potassium hydrosulfide. Its molar mass is 72.17 grams per mole, and it is soluble in water.
The equation for the reaction specified is 2 NaOH + H2S -> Na2S + H2O. Therefore, if the yield were 100 %, two formula masses of sodium hydroxide are required to produce one formula mass of sodium sulfide. The gram formula mass of NaOH is 40.00 and that of sodium sulfide is 78.04. The specified number of grams of sodium hydroxide corresponds to 2.53/40.00 or 0.06325 formula masses and therefore would provide half this many formula masses of sodium sulfide, for a mass of (0.06325)(78.04)/2.000 or 2.568 grams of sodium sulfide. Since the yield is specified as 91.0 %, the actual amount of sodium sulfide produced is 2.25 grams, to the justified number of significant digits.
17.9 grams
16.3106
there would be 50 grams of ammonia will be formed
The mass of sulfur is 6,118 g.
hydrochloric acid does not have an atomic number. Only elements have atomic numbers and hydrochloric acid is a compound composed of two non-metal elements: hydrogen and chlorine, as you might have guessed by the name. However: Hydrogen's atomic number is 1 and Chlorine's atomic number is 17
7
I assume you mean excess hydrochloric acid. Balanced equation. 2Al + 6HCl = 2AlCl3 + 3H2 2.70 grams Al (1 mole Al/26.98 grams)(3 mole H2/2 mole Al)(2.016 grams/1 mole H2) = 0.303 grams hydrogen gas produced --------------------------------------------------
The formula for potassium hydrogen sulfide is KHS. Another name for this inorganic compound is potassium hydrosulfide. Its molar mass is 72.17 grams per mole, and it is soluble in water.
The equation for the reaction specified is 2 NaOH + H2S -> Na2S + H2O. Therefore, if the yield were 100 %, two formula masses of sodium hydroxide are required to produce one formula mass of sodium sulfide. The gram formula mass of NaOH is 40.00 and that of sodium sulfide is 78.04. The specified number of grams of sodium hydroxide corresponds to 2.53/40.00 or 0.06325 formula masses and therefore would provide half this many formula masses of sodium sulfide, for a mass of (0.06325)(78.04)/2.000 or 2.568 grams of sodium sulfide. Since the yield is specified as 91.0 %, the actual amount of sodium sulfide produced is 2.25 grams, to the justified number of significant digits.
15.0
Molar mass of ammonia is 17.031 whereas molar mass of hydrogen chloride (or hydrochloric acid) is 36.461. Hence if given masses, there is 1 mole ammonia and 2 moles HCl. Hence there is more number of hydrogen chloride.
Cu + 2 HCl --> CuCl2 + H2 167.12 g HCl * (1 mol HCl/36.46 g HCl) * (1 mol H2/2 mol HCl) * (2.02 g/1 mol H2) = 4.629 g H2 4.63 grams of hydrogen gas is produced when 167.12 grams of hydrochloric acid reacts with copper.
17.9 grams
20,1588 grams of hydrogen
FeS + 2HCl >> FeCl2 + H2S 75 grams FeS (1mole FeS/87.92 grams)(2 mole HCl/1 mole FeS) = 1.71 moles HCl 2 Molar HCl = 1.71 moles HCl/Liters = 0.855 Liters HCl, or as asked for; 855 milliliters of hydrochloric acid needed