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What is the formula for potassium hydrogen sulfide?
The formula for potassium hydrogen sulfide is KHS. Another name for this inorganic compound is potassium hydrosulfide. Its molar mass is 72.17 grams per mole, and it is soluble in water.
How many grams of aluminum hydroxide are obtained from 17.2 grams of aluminum sulfide?
To determine the grams of aluminum hydroxide obtained from 17.2 grams of aluminum sulfide, we need to consider the stoichiometry of the reaction between aluminum sulfide and water to form aluminum hydroxide. Given the balanced chemical equation, we can calculate the molar mass of aluminum hydroxide and use it to convert the mass of aluminum sulfide to grams of aluminum hydroxide formed.
How many grams of sodium sulfide are formed if 1.90 of hydrogen sulfide is bubbled into a solution containing 2.53 of sodium hydroxide assuming that the sodium sulfide is made in 91.0 yield?
The equation for the reaction specified is 2 NaOH + H2S -> Na2S + H2O. Therefore, if the yield were 100 %, two formula masses of sodium hydroxide are required to produce one formula mass of sodium sulfide. The gram formula mass of NaOH is 40.00 and that of sodium sulfide is 78.04. The specified number of grams of sodium hydroxide corresponds to 2.53/40.00 or 0.06325 formula masses and therefore would provide half this many formula masses of sodium sulfide, for a mass of (0.06325)(78.04)/2.000 or 2.568 grams of sodium sulfide. Since the yield is specified as 91.0 %, the actual amount of sodium sulfide produced is 2.25 grams, to the justified number of significant digits.
How much hydrogyen will be formed by the reaction with 50g of zinc?
Do you mean this reaction? Zn + 2HCl -> ZnCl2 + H2 I will assume zinc is limiting. 50 grams Zn (1 mole Zn/65.41 grams)(1 mole H2/1 mole Zn)(2.016 grams/1 mole H2) = 1.5 grams of hydrogen gas
If you start with seventy grams of nitrogen and twenty grams of hydrogen how many grams of ammonia will be formed and how many grams of hydrogen are leftover?
To form ammonia (NH3) from nitrogen (N2) and hydrogen (H2), the balanced chemical equation is N2 + 3H2 → 2NH3. This means that for every mole of nitrogen, 3 moles of hydrogen are required. Given that nitrogen is limiting in this case, all 70 grams of nitrogen will react with 210 grams (3 times 70) of hydrogen to form 70 grams of ammonia. This reaction will consume all the hydrogen, leaving no grams of hydrogen leftover.
The molecular formula for hydrogen sulfide is H2S. What does the formula indicate about the composition of a 1.0-gram sample of hydrogen sulfide?
The molecular formula H2S indicates that in every molecule of hydrogen sulfide, there are 2 atoms of hydrogen and 1 atom of sulfur. Therefore, in a 1.0-gram sample of hydrogen sulfide, there would be 0.67 grams of hydrogen (2/3 of 1.0 grams) and 0.33 grams of sulfur (1/3 of 1.0 grams).
If 6.500 grams of hydrogen sulfide is decomposed to get 0.384 grams hydrogen how much sulfur is there?
The mass of sulfur is 6,118 g.
What is the molecular mass of hydrogen sulphide H2S?
The molecular mass of hydrogen sulfide (H2S) is 34.08 grams per mole.
What is the formula for potassium hydrogen sulfide?
The formula for potassium hydrogen sulfide is KHS. Another name for this inorganic compound is potassium hydrosulfide. Its molar mass is 72.17 grams per mole, and it is soluble in water.
How many grams of hydrogen is produced when 167.12 g of hydrochloric acid is reacted with copper?
Cu + 2 HCl --> CuCl2 + H2 167.12 g HCl * (1 mol HCl/36.46 g HCl) * (1 mol H2/2 mol HCl) * (2.02 g/1 mol H2) = 4.629 g H2 4.63 grams of hydrogen gas is produced when 167.12 grams of hydrochloric acid reacts with copper.
What is atomic no of hydrochloric acid?
hydrochloric acid does not have an atomic number. Only elements have atomic numbers and hydrochloric acid is a compound composed of two non-metal elements: hydrogen and chlorine, as you might have guessed by the name. However: Hydrogen's atomic number is 1 and Chlorine's atomic number is 17
What is the mass of hydrogen gas released from 2.70 g of aluminum metal and hydrochloric acid in grams?
I assume you mean excess hydrochloric acid. Balanced equation. 2Al + 6HCl = 2AlCl3 + 3H2 2.70 grams Al (1 mole Al/26.98 grams)(3 mole H2/2 mole Al)(2.016 grams/1 mole H2) = 0.303 grams hydrogen gas produced --------------------------------------------------
How many grams of aluminum hydroxide are obtained from 17.2 grams of aluminum sulfide?
To determine the grams of aluminum hydroxide obtained from 17.2 grams of aluminum sulfide, we need to consider the stoichiometry of the reaction between aluminum sulfide and water to form aluminum hydroxide. Given the balanced chemical equation, we can calculate the molar mass of aluminum hydroxide and use it to convert the mass of aluminum sulfide to grams of aluminum hydroxide formed.
How many moles of hydrogen gas H2 is produced if 20.0 mol of Zn are added to hydrochloric acid HCl according to the equation Zn plus 2HCl --- ZnCl2 plus H2?
20,1588 grams of hydrogen
How many millimeters of a 2 Molar solution of hydrochloric acid are needed to completely react with 75 grams of iron sulfide?
FeS + 2HCl >> FeCl2 + H2S 75 grams FeS (1mole FeS/87.92 grams)(2 mole HCl/1 mole FeS) = 1.71 moles HCl 2 Molar HCl = 1.71 moles HCl/Liters = 0.855 Liters HCl, or as asked for; 855 milliliters of hydrochloric acid needed
How many grams are in 3.3 miles of potassium sulfide?
It is not possible to convert miles directly to grams without additional information such as the density or molecular weight of potassium sulfide. Can you provide that information?
How many grams of sodium sulfide are formed if 1.90 of hydrogen sulfide is bubbled into a solution containing 2.53 of sodium hydroxide assuming that the sodium sulfide is made in 91.0 yield?
The equation for the reaction specified is 2 NaOH + H2S -> Na2S + H2O. Therefore, if the yield were 100 %, two formula masses of sodium hydroxide are required to produce one formula mass of sodium sulfide. The gram formula mass of NaOH is 40.00 and that of sodium sulfide is 78.04. The specified number of grams of sodium hydroxide corresponds to 2.53/40.00 or 0.06325 formula masses and therefore would provide half this many formula masses of sodium sulfide, for a mass of (0.06325)(78.04)/2.000 or 2.568 grams of sodium sulfide. Since the yield is specified as 91.0 %, the actual amount of sodium sulfide produced is 2.25 grams, to the justified number of significant digits.
