0
Because the Atomic Mass of aluminum is 26.99, this means that there are 26.99 grams of aluminum in one mole. For 3 moles multiply 26.99 by 3 = 80.97grams.
What else can I help you with?
How many moles of aluminum are produced from 33 grams of aluminum?
To determine how many moles of aluminum are produced from 33 grams, divide the given mass by the molar mass of aluminum, which is approximately 26.98 g/mol. So, 33 g / 26.98 g/mol ≈ 1.22 moles of aluminum are produced.
How many grams are contained in 5.5 moles of aluminum phosphate?
To convert moles to grams, you need to use the molar mass of the substance. The molar mass of aluminum phosphate is 122.94 g/mol. Therefore, for 5.5 moles of aluminum phosphate, you would have 5.5 moles x 122.94 g/mol = 676.17 grams of aluminum phosphate.
How many grams in 6.5 moles of aluminum phosphate?
To convert moles to grams, you need to use the molar mass of aluminum phosphate. The molar mass of aluminum phosphate (AlPO4) is 122.98 g/mol. Therefore, 6.5 moles of aluminum phosphate would be 6.5 moles * 122.98 g/mol = 798.37 grams.
What is 18.32 grams of aluminum and excess oxygen how many grams of aluminin oxiode are preduced?
Given the balanced chemical equation: 4Al + 3O2 → 2Al2O3, we can see that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. In this case, 18.32 grams of aluminum is equivalent to 0.684 moles. Using stoichiometry, we find that this would produce 0.456 grams of aluminum oxide.
How many grams of aluminum oxide can be formed by the reaction of 1020g of aluminum with oxygen?
To determine the grams of aluminum oxide formed, we need to consider the balanced chemical equation for the reaction between aluminum and oxygen. The molar ratio between aluminum and aluminum oxide is 4:2. So, first calculate the moles of aluminum in 1020g, then use this to find the moles of aluminum oxide produced, and finally convert moles of aluminum oxide to grams.
How many moles of aluminum are in 1.99 grams of aluminum?
1,99 grams of aluminum is equal to 0,0737 moles.
How many moles of aluminum are in 10grams of aluminum?
10 grams aluminum (1 mole Al/26.98 grams) = 0.37 moles of aluminum ---------------------------------
How many moles are 4.12 grams aluminum sulfate?
4,12 grams aluminum sulfate is equivalent to 0,012 moles (for the anhydrous salt).
How many moles of aluminum are produced from 33 grams of aluminum?
To determine how many moles of aluminum are produced from 33 grams, divide the given mass by the molar mass of aluminum, which is approximately 26.98 g/mol. So, 33 g / 26.98 g/mol ≈ 1.22 moles of aluminum are produced.
How many grams are contained in 5.5 moles of aluminum phosphate?
To convert moles to grams, you need to use the molar mass of the substance. The molar mass of aluminum phosphate is 122.94 g/mol. Therefore, for 5.5 moles of aluminum phosphate, you would have 5.5 moles x 122.94 g/mol = 676.17 grams of aluminum phosphate.
How many grams in 6.5 moles of aluminum phosphate?
To convert moles to grams, you need to use the molar mass of aluminum phosphate. The molar mass of aluminum phosphate (AlPO4) is 122.98 g/mol. Therefore, 6.5 moles of aluminum phosphate would be 6.5 moles * 122.98 g/mol = 798.37 grams.
How many moles are there in 9g of Al show working?
9 grams aluminum (1 mole Al/26.98 grams) = 0.3 moles aluminum ==============
What is 18.32 grams of aluminum and excess oxygen how many grams of aluminin oxiode are preduced?
Given the balanced chemical equation: 4Al + 3O2 → 2Al2O3, we can see that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. In this case, 18.32 grams of aluminum is equivalent to 0.684 moles. Using stoichiometry, we find that this would produce 0.456 grams of aluminum oxide.
2.91 moles of aluminum are how many grams?
For this you need the atomic mass of Al. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel.2.91 moles Al × (27.0 grams) = 78.6 grams Al
How many grams of zinc chloride does it take to react to 45 grams of aluminum?
To determine how many grams of zinc chloride (ZnCl₂) are needed to react with 45 grams of aluminum (Al), we first need to look at the balanced chemical equation for the reaction, which is: [ 2Al + 3ZnCl₂ \rightarrow 2AlCl₃ + 3Zn ] From the equation, 2 moles of aluminum react with 3 moles of zinc chloride. The molar mass of aluminum is approximately 27 g/mol, so 45 grams of aluminum corresponds to about 1.67 moles of Al. Thus, we need 2.5 moles of ZnCl₂ (since 1.67 moles Al will require 2.5 moles ZnCl₂). The molar mass of ZnCl₂ is about 136.3 g/mol, so 2.5 moles of ZnCl₂ would weigh approximately 340.75 grams.
How many grams of aluminum oxide can be formed by the reaction of 1020g of aluminum with oxygen?
To determine the grams of aluminum oxide formed, we need to consider the balanced chemical equation for the reaction between aluminum and oxygen. The molar ratio between aluminum and aluminum oxide is 4:2. So, first calculate the moles of aluminum in 1020g, then use this to find the moles of aluminum oxide produced, and finally convert moles of aluminum oxide to grams.
Given 18.32 grams of aluminum and excess oxygen how many grams of oxygen are used?
To determine the grams of oxygen used, we need to compare the moles of aluminum with the moles of oxygen in the reaction. The balanced chemical equation for the reaction between aluminum and oxygen is 4Al + 3O2 -> 2Al2O3. Using the molar mass of aluminum (26.98 g/mol) and oxygen (16.00 g/mol), we can calculate that 18.32 grams of aluminum would use 27.27 grams of oxygen in the reaction.
