I assume you mean 3.55 grams of silver. Don't forget your units! Silver (Ag, #47) has an Atomic Mass of about 108 grams per mole. Set up a direct proportion: 108/1=3.55/x, where x is the unknown number of moles in 3.55 grams Ag. Solve for x to get approx. 0.033 moles Ag. Multiply this number by Avogadro's constant of 6.02x1023 to get the number of representative particles. So, 0.033(6.02x1023)=1.99x1022 atoms of silver.
The answer is approx. 1,5.10e23 atoms of silver.
Silver is an atom.
Silver is an atom.
29
Silver is an element, pure silver would contain only silver atoms.
about 30
There are 6.022x1023 atoms in a mole. You multiply 6.022x1023 by 8.68, which equals 52.20796x1023 atoms
One formula unit of silver sulfate, Ag2SO4 has 7 atoms.
It depends on the weight of the silver in the material. 107.89 g of silver will have 6.023 x 1023 atoms of silver
There are 5 atoms in silver nitrate (1 silver, 1 nitrogen and 3 oxygens).
2.17*10^22
2.26*1024