Pieces of atoms?
6.01024 atoms of aluminum (1 mole Al/6.022 X 10^23)
= 9.98047 X 10^-24 moles of aluminum
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Aluminium Oxide(Al2O3) has 2 moles of aluminum and 3 moles of oxygen. The total is 5 moles. One mole is 6.022 x 1023 atoms. Therefore, 5 moles = 30.110 x 1023 atoms
The gram molecular mass of Al2O3 is 2(26.982) + 3 (15.999) = 101.96. Therefore, the number of moles of Al2O3 is 291.257/101.96 = 2.857 moles. Each mole contains two moles of aluminum atoms; therefore the number of aluminum atoms in this mass equals 2 X 2.857 X 6.022 X 1023 = 3.4410 X 1024 atoms.
3.85 atoms Al (1 mole atoms Al/6.022 X 10^23) = 6.39 X 10^-24 moles aluminum ( though 3.85 atoms seems unlikely )
The answer is 9 manganese atoms.
1 mole of atoms = 6.022 x 1023 atoms 6.2mol x 6.022 x 1023 atoms/mol = 3.7 x 1024 atoms Al
1,46 moles of aluminum fluoride contain 35,16848.10e23 atoms.
3.20 moles aluminum (6.022 X 1023/1 mole Al) = 1.93 X 1024 atoms of aluminum -------------------------------------------
2,89 moles of aluminium contain 17,40398707673.1023 atoms.
Aluminium Oxide(Al2O3) has 2 moles of aluminum and 3 moles of oxygen. The total is 5 moles. One mole is 6.022 x 1023 atoms. Therefore, 5 moles = 30.110 x 1023 atoms
Answer: 8.6 Mol. To Find this you need to set up your dimensional analysis as: (5.2x1024atoms)(1 mol/6.022x1023atoms)= 8.6 Mol. Your atoms cancel out, so finish working the math out and your left with moles of Aluminum.
The gram molecular mass of Al2O3 is 2(26.982) + 3 (15.999) = 101.96. Therefore, the number of moles of Al2O3 is 291.257/101.96 = 2.857 moles. Each mole contains two moles of aluminum atoms; therefore the number of aluminum atoms in this mass equals 2 X 2.857 X 6.022 X 1023 = 3.4410 X 1024 atoms.
3.85 atoms Al (1 mole atoms Al/6.022 X 10^23) = 6.39 X 10^-24 moles aluminum ( though 3.85 atoms seems unlikely )
The answer is 9 manganese atoms.
Aluminum sulfide has a molar mass of 150.16 grams per mole. This means there are 0.666 moles present, or 4.01 E23 molecules. Each molecule of Al2S3 has 2 aluminum atoms, so there are 8.02 E23 atoms of aluminum present.
1,99 grams of aluminum is equal to 0,0737 moles.
1 mole of atoms = 6.022 x 1023 atoms 6.2mol x 6.022 x 1023 atoms/mol = 3.7 x 1024 atoms Al
10 grams aluminum (1 mole Al/26.98 grams) = 0.37 moles of aluminum ---------------------------------