To find the number of moles of calcium (Ca) in 40.1 grams, you can use the formula:
moles = mass (g) / molar mass (g/mol).
The molar mass of calcium is approximately 40.08 g/mol. Therefore, the calculation is 40.1 g / 40.08 g/mol, which is about 1.0005 moles of calcium.
2 moles of Ca and 4 moles of OH
425 g calcium (Ca) is equal to 10,604 moles.
978 g calcium contain 24,4 moles.
3 x 6.02E23 molecules.
(2.7 mol Ca / 1) * (40.078 g Ca / 1 mol Ca) = 108.21 g Ca. After significant figures, the answer is 110 g Ca.
2 moles of Ca and 4 moles of OH
425 g calcium (Ca) is equal to 10,604 moles.
3.8 grams calcium (1 mole Ca/40.08 grams) = 0.09 moles calcium ==============
978 g calcium contain 24,4 moles.
In Ca(HCO3)2, there are 2 moles of carbonate ions (CO3^2-), each containing 3 atoms. So there are 6 atoms in 1 molecule of Ca(HCO3)2. Therefore, in 4 moles of Ca(HCO3)2, there are 4 x 6 = 24 moles of atoms.
For this you need the atomic mass of Ca. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. Ca= 40.1 grams.761 moles Ca × (40.1 grams) = 30.5 grams Ca
There are 0.18 moles of Ca2+ ions in 0.18 moles of CaF2.
156 g calcium is equivalent to 3,89 moles.
3 x 6.02E23 molecules.
126 grams calcium (1 mole Ca/40.08 grams) = 3.14 moles of calcium ------------------------------
0,688 g calcium is equivalent to 0,017 moles.
To determine the number of moles of calcium atoms in 45.8 g of Ca, first find the molar mass of calcium (Ca) from the periodic table (40.08 g/mol). Then, divide the given mass by the molar mass of Ca to get the number of moles. In this case, 45.8 g of Ca is equal to 1.14 moles of Ca atoms.