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How many moles are in 27.4 g of water?
27.4 g H2O x 1 mole/18 g = 1.52 moles
How many grams of 5 moles of lead?
5 moles of lead is equal to 1 036 g.
How many moles are present in gram's of silicon Si?
1 g silicon is equal to 0,0356 moles.
How many grams are in 34.7 moles of potassium?
34,7 moles of potassium 1 356,7 g.
How many moles are present in 1 g of ammonia nh3?
To find the number of moles in 1 g of ammonia (NH₃), first calculate its molar mass. The molar mass of NH₃ is approximately 17 g/mol (14 g/mol for nitrogen and 3 g/mol for hydrogen). Using the formula for moles (moles = mass/molar mass), we can calculate: 1 g NH₃ × (1 mol / 17 g) ≈ 0.059 moles of NH₃.
How many moles are there in 8 g sodium hydroxide?
8 g NaOH x 1 mole NaOH/40 g = 0.2 moles NaOH
What is the mass of 10 moles of sodium sulfite?
The desired outcome is the manipulation of moles to grams. Therefore, we need a conversion factor with these units. Molar masses have these units, so we begin by determining the molar mass of the compound. This is done by adding the molecular weights of the constituent elements, which are the numbers on the bottom of the entry of each element of most periodic tables. In mathematical notation: M(Na2SO3)=M(Na)+M(Na)+M(S)+M(O)+M(O)+M(O) or M(Na2SO3)=2*M(Na)+M(S)+3*M(O) Thus, for sodium sulfite, we get M=126.043 g/mol. The next step is manipulation of our given quantity into our desired units. Through dimensional analysis, we can see that multiplication will do the trick here, so 10 mol Na2SO3 *126.043 g/mol = 1260.43 g Na2SO3
How many moles are present in 1 g of ammonia?
There are approximately 0.023 moles of ammonia in 1 g of ammonia (NH3).
How many grams are in 55.0 moles of sodium?
55.0 moles of sodium are equal to 1 264,44 g.
How many moles are present in 40g of helium?
4 g of helium is equivalent to 1 mole of helium
How many moles of calcium are in a sample of 40 g?
There are approximately 1 mole of calcium in 40 g, as the molar mass of calcium is about 40 g/mol.
How many moles of NaCl is 43.83grams of NaCl?
1 mole of NaCl: Na = 1 * 22.99 g = 22.99 g Cl = 1* 35.45 g = 35.45 g Total = 58.44 g 238 g NaCl * (1 mol NaCl/58.44 g NaCl) = 4.07 mol NaCl There are approximately 4.1 moles in 238 grams of sodium chloride.
