4 g of helium is equivalent to 1 mole of helium
The molarity of a NaOH solution is determined by the concentration of NaOH in moles per liter of solution. It is calculated by dividing the moles of NaOH by the volume of solution in liters. For example, a 0.1 M NaOH solution would contain 0.1 moles of NaOH per liter of solution.
Approximately 4.50 grams of NaOH are required to prepare 200 mL of a 0.450 M solution. This can be calculated using the formula: moles = Molarity x Volume (in L), and then converting moles to grams using the molar mass of NaOH.
Calcium is 40g per mole (according to the periodic table,) so 50/40=1.25 moles.
334.8 Joules
The density of the unknown solid is 20 g/ml. This is calculated by dividing the mass (40g) by the volume (2ml).
Since the gram atomic mass of calcium is 40.08 and calcium does not form polyatomic molecules, the number of moles in 40g of calcium is 1.0, to the justified number of significant digits.
To find the number of moles of NaOH in a 36.65g sample, you need to divide the given mass by the molar mass of NaOH. The molar mass of NaOH is 40g/mol (sodium 22.99g/mol + oxygen 16.00g/mol + hydrogen 1.01g/mol). So, 36.65g ÷ 40g/mol = 0.9163 moles of NaOH.
To determine the number of moles in 4g of sodium hydroxide (NaOH), divide the mass by the molar mass of NaOH. The molar mass of NaOH is approximately 40g/mol (Na = 23g/mol, O = 16g/mol, H = 1g/mol). Therefore, 4g of NaOH is equal to 0.1 moles.
The molecular weight of sodium hydroxide is 40g/mol. To get the amount of moles, you have to divide the weight by molecular mass. 12g / 40 is 0.3 moles. This is 300 millimoles.
To find out how many 40g portions are in 2kg, first convert 2kg to grams: 2kg is equal to 2000g. Then, divide 2000g by 40g: (2000g \div 40g = 50). Therefore, there are 50 portions of 40g in 2kg.
2Ca + O2 --> 2CaO The molar mass of Calcium is 40g/mol. 36.5g/40g gives you 0.9125 moles of Calcium. The moles of calcium are equivalent to the moles of Calcium oxide. The answer is 0.9125 moles of calcium oxide. Correct me if I am wrong.
To find the number of moles in 4.75g of sodium hydroxide, you first need to determine the molar mass of sodium hydroxide (NaOH), which is about 40g/mol. Then divide the given mass (4.75g) by the molar mass to obtain the number of moles: 4.75g / 40g/mol = 0.119 moles of NaOH.
This is a titration question: we want to have the same number of hydroxide ions as hydroxide ions so that they will form water and the pH will be neutral. In chemistry, we count atoms and molecules in moles, and we can calculate how many moles of HBr we have, because concentration in molarity is the number of moles divided by the volume in liters... M = moles/V. We plug in what we got: 1.45M = moles/0.0350L, and solve for moles: 0.0508 moles. Now we know we need 0.0508 moles of NaOH, whose molecular weight is 40g/mole. MW x moles = grams, so (40g/mole)(0.0508 moles) = 2.03 g of NaOH.
The molarity of a NaOH solution is determined by the concentration of NaOH in moles per liter of solution. It is calculated by dividing the moles of NaOH by the volume of solution in liters. For example, a 0.1 M NaOH solution would contain 0.1 moles of NaOH per liter of solution.
To find the mass of hydrogen needed to react with 40g of copper oxide (CuO), first calculate the molar mass of CuO. Then, use stoichiometry to determine the moles of CuO present in 40g. From the balanced chemical equation CuO + H2 -> Cu + H2O, you can determine the mole ratio between CuO and H2. Finally, use the molar mass of hydrogen to calculate the mass of hydrogen needed to react.
That is 0.176 cup
40g