2Ca + O2 --> 2CaO
The molar mass of Calcium is 40g/mol. 36.5g/40g gives you 0.9125 moles of Calcium. The moles of calcium are equivalent to the moles of Calcium oxide. The answer is 0.9125 moles of calcium oxide.
Correct me if I am wrong.
There are actually two products made.When Calcium reacts with water, Calcium Hydroxide is produced and so is Hydrogen. So, both Calcium Hydroxide and Hydrogen are produced, looking like this in a word equation:Calcium + Water = Calcium Hydroxide + Hydrogen
calcium oxide (quick lime) produces calcium hydroxide (slaked lime) when reacts with water.
The two outer shell electrons of a calcium atom are donated to an oxygen atom, forming calcium cations and oxygen anions that together constitute the salt compound calcium oxide.
the outer cell will burn up leaving calcium-oxide
Calcium contains only one atom per molecule, while oxygen contains two. The usual reaction product from a reaction between calcium and oxygen has the formula CaO and therefore contains one atom of each element per molecule. 4 moles of oxygen provides 8 moles of oxygen atoms, so that under the conditions given, calcium is the limiting reactant, and 6.55 moles of calcium oxide will be formed.
calcium oxide, CaO
Hydrogen gas is released when calcium and water react.
When barium reacts with oxygen barium oxide is produced. Ba + O2 -> BaO
calcium carbonate (CaCO3)
carbon dioxide
There are actually two products made.When Calcium reacts with water, Calcium Hydroxide is produced and so is Hydrogen. So, both Calcium Hydroxide and Hydrogen are produced, looking like this in a word equation:Calcium + Water = Calcium Hydroxide + Hydrogen
Rust.
calcium oxide (quick lime) produces calcium hydroxide (slaked lime) when reacts with water.
The mass of heavy water produced when 7,00grams of oxygen reacts with excess D2 is 7,875 g.
gypsum
A good one A good one
The two outer shell electrons of a calcium atom are donated to an oxygen atom, forming calcium cations and oxygen anions that together constitute the salt compound calcium oxide.