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14.2g Fe2O3 (1mol Fe2O3/159.7g(2mol Fe/1mol Fe2O3) = 0.178 moles Fe

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14y ago
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6y ago

The number of moles in 14,1 g of Fe is 0,252.

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10y ago

The answer is 14,3 g iron(III) oxide.

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8y ago

The mass of Fe2O3 is 7,7 g.

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Q: The formula for rust can be represented by Fe2O3 How many moles of Fe are present in 14.2 g of the compound?
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