388.grams Fe divided by mass of Fe
388.2g/55.85= 6.95moles of Fe
To determine how many moles of bromide are in iron (III) bromide (FeBr3), you can use the chemical formula FeBr3 to see that there are three moles of bromide ions for every mole of iron (III) bromide. So, the number of moles of bromide ions is equal to the number of moles of FeBr3.
There are 4.17 moles of H2O present in 75.0g of H2O.
The number of moles is 4.
To find the number of moles in 1.5 grams of iron, you need to divide the mass of iron by its molar mass. The molar mass of iron is approximately 55.85 g/mol. So, 1.5 grams of iron is equal to 1.5 g / 55.85 g/mol = 0.027 moles of iron.
To find the number of moles in 233.2 g of iron (Fe), you need to divide the given mass by the molar mass of iron, which is approximately 55.85 g/mol. So, 233.2 g ÷ 55.85 g/mol ≈ 4.17 moles of iron.
55.8 moles
55.8 moles
For every one mole of iron-III-chromate, there are three moles of chromate ions present. Therefore, in a sample containing 3.71 moles of iron-III-chromate, there would be 3.71 moles multiplied by 3, which is 11.13 moles of chromate ions.
55.8 moles
0.4965 moles rounded to 4 significant figures
738 grams iron are equivalent to:- 12,626 moles- 76.10e23 atoms
233,2 g iron Feis equivalent to 4,176 moles.
To determine how many moles of bromide are in iron (III) bromide (FeBr3), you can use the chemical formula FeBr3 to see that there are three moles of bromide ions for every mole of iron (III) bromide. So, the number of moles of bromide ions is equal to the number of moles of FeBr3.
9,003 x 1023 atoms of iron correspond to 1,495 moles.
The answer is 8,33 moles.
The answer is 0,615 moles.
250 g iron (III) oxide is equal to 1,565 moles.