1 mol of Na+ = 22.989g Na+
(0.350 mol) x (22.989 g/mol) = 8.05 g Na+
The molar mass of an element corresponds to the atomic mass of the element (found on the periodic table). The atomic mass of Sodium-Na is 22.990 g, which is also the molar mass of Na. So for 1 mole of Na, there are 22.990 grams of Na. If we had 3 moles of Na, then we would simply multiply the molar mass by 3.
Na2SO4 10.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(2 mole Na/1 mole Na2SO4)(22.99 grams/1 mole Na) = 3.24 grams of sodium -------------------------------
The molar mass of sodium (Na) is approximately 22.99 grams per mole. Therefore, the weight of 1 mole of pure sodium is 22.99 grams.
molar mass Na = 22.99g/mol (atomic weight in grams) 0.0135mol Na x (22.99g/mol) = 0.310g Na
To determine the number of atoms in 72.6 grams of sodium, you first need to convert grams to moles using the molar mass of sodium. Sodium has a molar mass of approximately 22.99 g/mol. Then, you use Avogadro's number (6.022 x 10^23) to convert moles to atoms.
The molar mass of an element corresponds to the atomic mass of the element (found on the periodic table). The atomic mass of Sodium-Na is 22.990 g, which is also the molar mass of Na. So for 1 mole of Na, there are 22.990 grams of Na. If we had 3 moles of Na, then we would simply multiply the molar mass by 3.
3.5 grams Na (1 mole Na/22.99 grams)(6.022 X 1023/1 mole Na) = 9.2 X 1022 atoms of sodium ===================
Na2SO4 10.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(2 mole Na/1 mole Na2SO4)(22.99 grams/1 mole Na) = 3.24 grams of sodium -------------------------------
145 grams NaCl (1 mole NaCl/58.44 grams)(1 mole Na +/1 mole NaCl)(6.022 X 1023/1 mole Na +) = 1.49 X 1024 ions of sodium =====================
5 grams of table salt is 5 grams of NaCl. NaCl has a molar mass of 58.443 grams/mol, so 5 grams would be .0855 mol NaCl. In one mole of NaCl there is one mole of Na, so there would be .0855 mol Na, or 5.235 * 1022 atoms Na.
Find moles. 365 grams Na (1 mole Na/22.99 grams) = 15.876 moles Na ======================================================================= Now, sodium and nitrogen are about one to one, so they will be 1 in the empirical formula and either can be the divisor of oxygen's mole number 47 mole O/15.774 mole N = 2.979 moles oxygen ----------------------------------we call this 3 NaNO3 -----------the empirical formula of the compound ( sodium nitrate )
1) Get the chemical formula to determine the number of each type of atom present in the compound. 2) Multiply the atomic weight (get it from the periodic table) of each element by the number of atoms of that element present your specific compound 3) Do the Sum in unit grams/mole NaCl (1x23 grams/mole Na) + (1x 35.5 grams/mole Cl) = 58.5 grams/mole NaCl
The molar mass of sodium (Na) is approximately 22.99 grams per mole. Therefore, the weight of 1 mole of pure sodium is 22.99 grams.
Number of particles (atoms) =Avogadro's number (parts per mole) * [ mass (grams) / molar mass (grams per mole) ]So: N = 6.02*10+23 * 23.0 / 22.99 = 6.02*10+23atoms sodium
molar mass Na = 22.99g/mol (atomic weight in grams) 0.0135mol Na x (22.99g/mol) = 0.310g Na
Depending on some textbooks it can differ somewhat, but 1 mole of Na weighs 22.99 grams, and 1 mole of Cl weighs 35.45 grams. So if you combine the two.Na + Cl --> NaClThen you would just add the two up to give you 58.44 g/mol.Hope that helps.--Zdrum
1 mole Na = 22.989770g 10 moles Na = 10 x 22.989770g = 229.89770g