Number of particles (atoms) =
Avogadro's number (parts per mole) * [ mass (grams) / molar mass (grams per mole) ]
So: N = 6.02*10+23 * 23.0 / 22.99 = 6.02*10+23atoms sodium
23 g of sodium metal will have 6.023 x 1023 atoms (or 1 mole of atoms)
When the RAM of sodium is assumed as 23.1, the given mass contains 0.01 moles of the substance.
the formula does not show how many moles are in a compound, but it tells how many atoms of an element that are in the compound...
Sodium has an atomic mass of 29.990 g/mol. This means that 124 sodium atoms have a mass of 3718.76 amu, if the isotopes follow the average. To find in grams, the following must be used: 124 sodium atoms equal 2.0598 * 10-22 moles, so 124 sodium atoms have a mass of 6.177 *10-21 grams.
n = mass / gfm n = 46/23 n = 2 n x 6.0221415 × 1023 = the number of any paricle in this case it is 1.2x1024
41,1 g of sodium sulfate (Na2SO4, anhydrous) contain 10,455.10e23 atoms.
23 g of sodium metal will have 6.023 x 1023 atoms (or 1 mole of atoms)
1.13 × 10 23 oxygen atoms
When the RAM of sodium is assumed as 23.1, the given mass contains 0.01 moles of the substance.
dose 23 grams of sodium and 238 grams of uranium have equal number of atoms in them
the formula does not show how many moles are in a compound, but it tells how many atoms of an element that are in the compound...
The number of atoms of lead is 6,68.10e23.
Sodium has an atomic mass of 29.990 g/mol. This means that 124 sodium atoms have a mass of 3718.76 amu, if the isotopes follow the average. To find in grams, the following must be used: 124 sodium atoms equal 2.0598 * 10-22 moles, so 124 sodium atoms have a mass of 6.177 *10-21 grams.
n = mass / gfm n = 46/23 n = 2 n x 6.0221415 × 1023 = the number of any paricle in this case it is 1.2x1024
32.4 g (6.02 x 1023 at / 22.99 g) = 8.48 x 1023atoms
23 g The masses in your table represent the relative masses of the atoms of these elements. According to the table an average atom of sodium is 23/12 = 1.9 times as massive as an average atom of carbon. Thus, in order to have the same number of atoms of sodium we need a mass of carbon that is 23/12 times its mass. Since we have 12 g of carbon, we have 23/12 x 12 = 23 g sodium.
NaC2H3O2 14.5 g NaC2H3O2 (1 mole NaC2H3O2/82.034 grams)(6.022 X 10^23/1 mole NaC2H3O2) = 1.06 X 10^23 atoms of sodium acetate