Depending on some textbooks it can differ somewhat, but 1 mole of Na weighs 22.99 grams, and 1 mole of Cl weighs 35.45 grams. So if you combine the two.
Na + Cl --> NaCl
Then you would just add the two up to give you 58.44 g/mol.
Hope that helps.
--Zdrum
The chemical formula for sodium hypochlorite is NaClO, and so each mole contains 1 mole of Na and 1 mole of Cl and one mole of O. Now, what is the 5.25 in your question? Is that 5.25 moles, or 5.25 grams, or 5.25 mg? If it's grams, then you divide the 5.25 g by the molar mass of NaClO to get moles NaClO. After that, you multiply that number by 35.5 g/mole Cl to get grams of Cl. Divide that by 1000 to get mg of Cl and then since it is in 500 ml (0.5 L) multiply that by 2 to get mg/liter which is the same as ppm.
1.409 moles chlorine (35.45 grams/1 mole Cl) = 49.95 grams of chlorine ==================
1) Get the chemical formula to determine the number of each type of atom present in the compound. 2) Multiply the atomic weight (get it from the periodic table) of each element by the number of atoms of that element present your specific compound 3) Do the Sum in unit grams/mole NaCl (1x23 grams/mole Na) + (1x 35.5 grams/mole Cl) = 58.5 grams/mole NaCl
Find the atomic or molecular weight of each and multiply it by the number of moles. atomic weight of carbon is 12 g/mole. atomic weight of chlorine is 35.45 g/mole molecular weight of fructose is 180.16 g/mole So just find the total grams. 10 moles Carbon * 12g/mole Carbon = 120 grams carbon 3 moles Chlorine * 35.45g/mole Chlorine = 106.35 grams Chlorine 1 mole Fructose * 180.16 g/mole Fructose = 180.16 grams Fructose So the answer is 1 mole of fructose.
Silver chloride - AgClAg (107.89 grams) + Cl (35.45 grams) = 143.34 grams
15cL equals 0.15L* There are 100cL per liter
One mole of chloride (Cl-) to one mole of Ag+ ions: Cl- + Ag+ --> AgCl(s)
The chemical formula for sodium hypochlorite is NaClO, and so each mole contains 1 mole of Na and 1 mole of Cl and one mole of O. Now, what is the 5.25 in your question? Is that 5.25 moles, or 5.25 grams, or 5.25 mg? If it's grams, then you divide the 5.25 g by the molar mass of NaClO to get moles NaClO. After that, you multiply that number by 35.5 g/mole Cl to get grams of Cl. Divide that by 1000 to get mg of Cl and then since it is in 500 ml (0.5 L) multiply that by 2 to get mg/liter which is the same as ppm.
1.409 moles chlorine (35.45 grams/1 mole Cl) = 49.95 grams of chlorine ==================
There are 2 moles of Cl in 1 mole of CaCl2. The molar mass of Cl is 35.45 g/mol. So, in 435 g of CaCl2, there would be 2 moles of Cl, which is equal to 70.9 g of Cl.
Mole = Mass/RMM Ar for Na=23 & Ar for Cl = 35.5 Therefore 1mole = Mass / (35.5+23) 1 mole of NaCl is 58.5g Mole = Mass/RMM Ar for Na=23 & Ar for Cl = 35.5 Therefore 1mole = Mass / (35.5+23) 1 mole of NaCl is 58.5g But that can be misleading. NaCl does not form into molecules (and salts in general do not). If you dissolve 58.5g of NaCl into water, it will dissociate into ions, and there will be 2 moles of particles in solution: 1 mole of Na+ ions, and 1 mole of Cl- ions. Knowing that will be important for calculating various things, such as how many degrees the freezing point will be depressed, when you dissolve so much salt in so much water.
1) Get the chemical formula to determine the number of each type of atom present in the compound. 2) Multiply the atomic weight (get it from the periodic table) of each element by the number of atoms of that element present your specific compound 3) Do the Sum in unit grams/mole NaCl (1x23 grams/mole Na) + (1x 35.5 grams/mole Cl) = 58.5 grams/mole NaCl
246 g
The balanced equation for the reaction is: CH₄ + 4Cl₂ → CCl₄ + 4HCl Using the stoichiometry of the reaction, one mole of chlorine (Cl₂) produces one mole of carbon tetrachloride (CCl₄). Since the molar mass of Cl₂ is 70.91 g/mol and that of CCl₄ is 153.82 g/mol, 709.0 grams of chlorine would produce 709.0 grams of carbon tetrachloride.
1 mole Cl = 35.453g Cl 28.4g Cl x 1mol Cl/35.453g Cl = 0.801 mole Cl
I'll see if I can type it out for you.. 79g NaCl x (1 mol NaCl)/(58.44g NaCl) = 1.35 mol NaCl 1 mol NaCl = 58.44g (because Na is 22.99g and Cl is 35.45g)
I assume that is 28.0 grams.28.0 grams MgCl2 (1 mole MgCl2/95.21 grams)= 0.294 moles magnesium chloride==========================Now,One mole Mg 2+ = 0.294 moles Mg 2+ ions=============================2 moles Cl - = 0.588 moles Cl - ions=========================