To find the mass in grams of 3.5 moles of chlorine (Cl), you can use the molar mass of chlorine, which is approximately 35.45 grams/mole. Multiply the number of moles by the molar mass:
3.5 moles × 35.45 g/mole = 124.575 grams.
Therefore, there are approximately 124.58 grams in 3.5 moles of Cl.
0,5 moles Cl-
it wouldn't be moles of Cl it would be Cl2 as chlorine doesn't exist as an atom it exsists as two joined to form a compound this is very easy stuff the answer is 15 moles of Cl2 as there 30 moles of Cl hope this helps learn your moles it's easy stuff
To find the mass of 4.50 moles of chlorine gas (Cl₂), we first need to determine the molar mass of Cl₂. Chlorine has an atomic mass of approximately 35.45 g/mol, so the molar mass of Cl₂ is about 70.90 g/mol (2 * 35.45 g/mol). Therefore, the mass of 4.50 moles of Cl₂ is calculated as follows: 4.50 moles × 70.90 g/mol = 318.45 grams.
1.409 moles chlorine (35.45 grams/1 mole Cl) = 49.95 grams of chlorine ==================
For this problem you need the atomic masses of the elements to find the molecular mass (added atomic masses). Then take the atomic mass of Cl and divide it by the molecular mass (multiplied by 100) to get a percent. This will be the percent of Cl in all compounds of HCl. Then you can use this percent and apply it to the 2 moles.H- 1.00Cl- 35.5HCl- 36.535.5 / 36.5 × 100 = 97.3% Cl in HClSo we know that in 2 moles of HCl, 97.3% of it is Cl.97.3% of 2.00 moles HCl = 1.95 moles of Cl in 2 moles HClNow we have to find out how many atoms this is (convert moles to atoms). Take the number of moles and multiply it by Avogadro's constant, 6.02 × 1023.1.95 moles Cl × 6.02 × 1023 = 1.17 × 1024atoms of Cl in 2 moles of HCl
To find the mass of 64 moles of Cl (chlorine), you need to multiply the number of moles by the molar mass of Cl. The molar mass of Cl is approximately 35.45 g/mol. Therefore, 64 moles of Cl would be approximately 2267.2 grams (64 moles x 35.45 g/mol).
There are 2 moles of Cl in 1 mole of CaCl2. The molar mass of Cl is 35.45 g/mol. So, in 435 g of CaCl2, there would be 2 moles of Cl, which is equal to 70.9 g of Cl.
To determine how many grams of chlorine gas (Cl₂) are produced from the decomposition of sodium chloride (NaCl), we start with the balanced chemical equation for the reaction: 2 NaCl → 2 Na + Cl₂. From the molar mass of NaCl (approximately 58.44 g/mol), 7.5 grams of NaCl corresponds to about 0.128 moles. According to the stoichiometry of the reaction, 2 moles of NaCl produce 1 mole of Cl₂, so 0.128 moles of NaCl would yield 0.064 moles of Cl₂. The molar mass of Cl₂ is approximately 70.90 g/mol, resulting in about 4.54 grams of Cl₂ being produced.
In 1 mol of NaCl there is 58.44 grams. ( 22.99 grams of Na + 35.45 grams of Cl). Using stoichiometry, you cancel the grams by taking 29.22 grams/58.44 grams. So 0.50 moles of NaCl
To find the grams of NaCl with 2.34 moles of Cl2, you need to consider the molar ratio. For every 1 mole of Cl2, there are 2 moles of Cl in NaCl. So, 2.34 moles of Cl2 would be equivalent to 4.68 moles of Cl in NaCl. Using the molar mass of NaCl (58.44 g/mol), you can calculate that 4.68 moles of NaCl would be approximately 273.64 grams.
0,5 moles Cl-
0.560 moles × 35.453 grams/mole = 19.85 grams
it wouldn't be moles of Cl it would be Cl2 as chlorine doesn't exist as an atom it exsists as two joined to form a compound this is very easy stuff the answer is 15 moles of Cl2 as there 30 moles of Cl hope this helps learn your moles it's easy stuff
Mg2+ + 2 Cl- are in 1 : 2 ratio (of ions) so also 0.25 : 0.50 mole ratio
1 mole Cl = 35.453g Cl 28.4g Cl x 1mol Cl/35.453g Cl = 0.801 mole Cl
2 moles of NaCl, of course. Cl would definitely limit in this one to one reaction and you would have 19998 moles Na in excess.
To find the mass of 4.50 moles of chlorine gas (Cl₂), we first need to determine the molar mass of Cl₂. Chlorine has an atomic mass of approximately 35.45 g/mol, so the molar mass of Cl₂ is about 70.90 g/mol (2 * 35.45 g/mol). Therefore, the mass of 4.50 moles of Cl₂ is calculated as follows: 4.50 moles × 70.90 g/mol = 318.45 grams.