64 moles of chlorine atoms would be 64 x 35.5 grams, i.e. 2272 grams. If you meant the substance chlorine, which consists of Cl2 molecules, it would be 4544 grams.
There are 2 moles of Cl in 1 mole of CaCl2. The molar mass of Cl is 35.45 g/mol. So, in 435 g of CaCl2, there would be 2 moles of Cl, which is equal to 70.9 g of Cl.
To find the grams of NaCl with 2.34 moles of Cl2, you need to consider the molar ratio. For every 1 mole of Cl2, there are 2 moles of Cl in NaCl. So, 2.34 moles of Cl2 would be equivalent to 4.68 moles of Cl in NaCl. Using the molar mass of NaCl (58.44 g/mol), you can calculate that 4.68 moles of NaCl would be approximately 273.64 grams.
1 mole Cl = 35.453g Cl 28.4g Cl x 1mol Cl/35.453g Cl = 0.801 mole Cl
2 moles of NaCl, of course. Cl would definitely limit in this one to one reaction and you would have 19998 moles Na in excess.
I assume that is 28.0 grams.28.0 grams MgCl2 (1 mole MgCl2/95.21 grams)= 0.294 moles magnesium chloride==========================Now,One mole Mg 2+ = 0.294 moles Mg 2+ ions=============================2 moles Cl - = 0.588 moles Cl - ions=========================
To find the mass in grams of 3.5 moles of chlorine (Cl), you can use the molar mass of chlorine, which is approximately 35.45 grams/mole. Multiply the number of moles by the molar mass: 3.5 moles × 35.45 g/mole = 124.575 grams. Therefore, there are approximately 124.58 grams in 3.5 moles of Cl.
There are 2 moles of Cl in 1 mole of CaCl2. The molar mass of Cl is 35.45 g/mol. So, in 435 g of CaCl2, there would be 2 moles of Cl, which is equal to 70.9 g of Cl.
To determine how many grams of chlorine gas (Cl₂) are produced from the decomposition of sodium chloride (NaCl), we start with the balanced chemical equation for the reaction: 2 NaCl → 2 Na + Cl₂. From the molar mass of NaCl (approximately 58.44 g/mol), 7.5 grams of NaCl corresponds to about 0.128 moles. According to the stoichiometry of the reaction, 2 moles of NaCl produce 1 mole of Cl₂, so 0.128 moles of NaCl would yield 0.064 moles of Cl₂. The molar mass of Cl₂ is approximately 70.90 g/mol, resulting in about 4.54 grams of Cl₂ being produced.
In 1 mol of NaCl there is 58.44 grams. ( 22.99 grams of Na + 35.45 grams of Cl). Using stoichiometry, you cancel the grams by taking 29.22 grams/58.44 grams. So 0.50 moles of NaCl
To find the grams of NaCl with 2.34 moles of Cl2, you need to consider the molar ratio. For every 1 mole of Cl2, there are 2 moles of Cl in NaCl. So, 2.34 moles of Cl2 would be equivalent to 4.68 moles of Cl in NaCl. Using the molar mass of NaCl (58.44 g/mol), you can calculate that 4.68 moles of NaCl would be approximately 273.64 grams.
To determine the grams of sodium chloride (NaCl) formed from the reaction of chlorine gas (Cl₂) with sodium (Na), we first need to consider the balanced chemical equation: 2 Na + Cl₂ → 2 NaCl. From this equation, one mole of Cl₂ produces two moles of NaCl. The molar mass of Cl₂ is approximately 70.9 g/mol, so 2.34 grams of Cl₂ is about 0.0331 moles. Since this produces double the moles of NaCl, we get 0.0662 moles of NaCl. The molar mass of NaCl is about 58.44 g/mol, so the mass of NaCl produced is approximately 3.87 grams.
0,5 moles Cl-
0.560 moles × 35.453 grams/mole = 19.85 grams
it wouldn't be moles of Cl it would be Cl2 as chlorine doesn't exist as an atom it exsists as two joined to form a compound this is very easy stuff the answer is 15 moles of Cl2 as there 30 moles of Cl hope this helps learn your moles it's easy stuff
Mg2+ + 2 Cl- are in 1 : 2 ratio (of ions) so also 0.25 : 0.50 mole ratio
1 mole Cl = 35.453g Cl 28.4g Cl x 1mol Cl/35.453g Cl = 0.801 mole Cl
2 moles of NaCl, of course. Cl would definitely limit in this one to one reaction and you would have 19998 moles Na in excess.