For this problem you need the atomic masses of the elements to find the molecular mass (added atomic masses). Then take the Atomic Mass of Cl and divide it by the molecular mass (multiplied by 100) to get a percent. This will be the percent of Cl in all compounds of HCl. Then you can use this percent and apply it to the 2 moles.
H- 1.00
Cl- 35.5
HCl- 36.5
35.5 / 36.5 × 100 = 97.3% Cl in HCl
So we know that in 2 moles of HCl, 97.3% of it is Cl.
97.3% of 2.00 moles HCl = 1.95 moles of Cl in 2 moles HCl
Now we have to find out how many atoms this is (convert moles to atoms). Take the number of moles and multiply it by Avogadro's constant, 6.02 × 1023.
1.95 moles Cl × 6.02 × 1023 = 1.17 × 1024atoms of Cl in 2 moles of HCl
To find the number of moles of Cl₂ in 985 g, use the molar mass of Cl₂, which is about 70.906 g/mol. The number of moles is calculated by dividing the mass by the molar mass: [ \text{moles of Cl₂} = \frac{985 \text{ g}}{70.906 \text{ g/mol}} \approx 13.9 \text{ moles} ] Since Cl₂ consists of two chlorine atoms, the mass of Cl atoms present can be calculated by multiplying the moles of Cl₂ by 2 and then by the molar mass of chlorine (approximately 35.453 g/mol), resulting in approximately 985 g of Cl atoms.
One mole is 6.02 × 1023 molecules. So 2 molecules out of that 6.02 × 1023 would be 2/(6.02 × 1023) or 3.32 ×10-24 moles.
The number of molecules is 12,044280.10e23.
There are approximately 1.204 x 10^24 molecules in 2 moles of water. This is because 1 mole of a substance contains 6.022 x 10^23 molecules. Therefore, 2 moles would contain twice that number.
The reaction is :- 2C2H6 + 7O2 ----------> 4CO2 + 6H2O When one mole ethane is combusted 7/2 moles of oxygen are used. When 3 moles of ethane are combusted 3 x 7/2 moles of oxygen used. No. of oxygen molecules consumed =6.022 x 1023 x7/2= 21.077 x 1023=2.107 x 1024 molecules.
Mg2+ + 2 Cl- are in 1 : 2 ratio (of ions) so also 0.25 : 0.50 mole ratio
2 moles of NaCl, of course. Cl would definitely limit in this one to one reaction and you would have 19998 moles Na in excess.
There are 2 moles of Cl in 1 mole of CaCl2. The molar mass of Cl is 35.45 g/mol. So, in 435 g of CaCl2, there would be 2 moles of Cl, which is equal to 70.9 g of Cl.
To find the number of moles of Cl₂ in 985 g, use the molar mass of Cl₂, which is about 70.906 g/mol. The number of moles is calculated by dividing the mass by the molar mass: [ \text{moles of Cl₂} = \frac{985 \text{ g}}{70.906 \text{ g/mol}} \approx 13.9 \text{ moles} ] Since Cl₂ consists of two chlorine atoms, the mass of Cl atoms present can be calculated by multiplying the moles of Cl₂ by 2 and then by the molar mass of chlorine (approximately 35.453 g/mol), resulting in approximately 985 g of Cl atoms.
Since the charge of Mg^2+ ion is 2+ and Cl^- ion has a charge of 1-, each Mg^2+ ion will combine with 2 Cl^- ions to form MgCl2. Therefore, for 0.25 moles of Mg^2+ ions, you will need 0.50 moles of Cl^- ions for complete combination.
Because it ionizes into Na+ and Cl-, thus ONE mole or molecule of NaCl produces TWO moles or molecules, namely Na and Cl, thus i (the van't Hoff factor) is 2.
One mole is 6.02 × 1023 molecules. So 2 molecules out of that 6.02 × 1023 would be 2/(6.02 × 1023) or 3.32 ×10-24 moles.
The number of molecules is 12,044280.10e23.
To find the molarity of Cl in the solution, first calculate the number of moles of CaCl2 using its molar mass. Then, since each formula unit of CaCl2 contains 2 moles of Cl, multiply the moles of CaCl2 by 2 to get moles of Cl. Finally, divide moles of Cl by the volume of the solution in liters to find the molarity.
Two Chloride ions (2Cl-) ions are needed with their -1 charge on each one to cancel out the +2 charge of the single Magnesium ion (Mg2+). So Magnesium Chloride would have the chemical formula: MgCl2
There are approximately 1.204 x 10^24 molecules in 2 moles of water. This is because 1 mole of a substance contains 6.022 x 10^23 molecules. Therefore, 2 moles would contain twice that number.
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 2.5 moles Na+ and 2.5 moles Cl-, totaling 5 moles of ions altogether.