The reaction is :-
2C2H6 + 7O2 ----------> 4CO2 + 6H2O
When one mole ethane is combusted 7/2 moles of oxygen are used.
When 3 moles of ethane are combusted 3 x 7/2 moles of oxygen used.
No. of oxygen molecules consumed =6.022 x 1023 x7/2= 21.077 x 1023=2.107 x 1024 molecules.
1,125 moles of sodium sulfate contain 6,774908464125.10e23 molecules.
2.45 X 1023 molecules CH2 (1 mole CH2/6.022 X 1023)= 0.407 moles CH2============
To find the number of molecules present in 936 g of glucose, you would first calculate the number of moles of glucose using its molecular weight. Then, you would use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
There are 1.28x10^24 molecules of SF4. 2.13 mol * 6.022x10^23 molecules/mol = 1.28x10^24 molecules.
To find the number of molecules in 5 moles of Br2, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) molecules per mole. Therefore, the number of molecules in 5 moles of Br2 is calculated as follows: (5 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} = 3.011 \times 10^{24}) molecules. Thus, there are approximately (3.011 \times 10^{24}) molecules of Br2 in 5 moles.
1,125 moles of sodium sulfate contain 6,774908464125.10e23 molecules.
Since each N2O molecule contains 2 nitrogen atoms, the number of moles of N2O molecules would be half of the moles of nitrogen atoms. Therefore, in this case, there would be 2.615 moles of N2O molecules present in the sample.
First calculate the moles of methanal(formaldehyde) moles(HCHO)= 0.11 / (30; Mr of ethanal) = 0.0036666... Remember the Avogadro Number. (6.022 x 10^(23)) is the number of molecules/atoms in ONE mole . Hence in 0.0036666 moles there are 0.0036666... X 6.022 x 10(23) = 2.20806 x 10^(21) molecules in 0.11 g of methanal. NB ; In modern IUPAC chemical nomenclature formaldehyde is named as METHANAL. NNB Note the 'A' instead 'o' in the name, NNNB The aldehyde formula is written as HCHO ; ( Ethanal would be CH3CHO). The arrangement of the letters in the formula is XCHO Hope that helps!!!!
2.45 X 1023 molecules CH2 (1 mole CH2/6.022 X 1023)= 0.407 moles CH2============
To find the number of moles in 1.21 molecules of HBr, divide the number of molecules by Avogadro's number (6.022 x 10^23 molecules/mol). Thus, 1.21 molecules of HBr is approximately 2.01 x 10^-24 moles.
To find the number of molecules present in 936 g of glucose, you would first calculate the number of moles of glucose using its molecular weight. Then, you would use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
To find the number of moles in 9.0345 x 10^24 molecules of trifluoromethanoic acid (CHF3O3S), you can divide the number of molecules by Avogadro's number (6.022 x 10^23 molecules/mol). Number of moles = 9.0345 x 10^24 molecules / 6.022 x 10^23 molecules/mol = 15 moles.
0,522 moles of ammonia contain 3,143.10e23 molecules of NH3.
There are 1.28x10^24 molecules of SF4. 2.13 mol * 6.022x10^23 molecules/mol = 1.28x10^24 molecules.
23 moles of oxygen contain 138,509.10e23 molecules.
To find the number of molecules in 5 moles of Br2, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) molecules per mole. Therefore, the number of molecules in 5 moles of Br2 is calculated as follows: (5 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} = 3.011 \times 10^{24}) molecules. Thus, there are approximately (3.011 \times 10^{24}) molecules of Br2 in 5 moles.
30.115*10^23 molecules