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Two Chloride ions (2Cl-) ions are needed with their -1 charge on each one to cancel out the +2 charge of the single Magnesium ion (Mg2+). So Magnesium Chloride would have the chemical formula: MgCl2

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12y ago
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12y ago

In 2 moles of MgCl2, there are 4 moles of Cl- ions. There are 6.022 X 1023 Cl- ions in a mole of Cl- ions. So,

4 moles Cl- ions X 6.022 X 1023 Cl-/1 mole Cl- = 2.409 X 1024 Cl- ions.

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8y ago

Magnesium chloride, MgCl2 would have 2 negative ions, namely 2 Cl^- ions.

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Q: How many chloride ions are in sample of salt that contains 2 moles of MgCl2?
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How many chloride ions are in a sample of salt that contains 2 moles of MgCl2?

2.4088 x 1024 chloride ions


How many moles are contained in 444 grams of magnesium chloride?

Formula mass of MgCl2 = 24.3+2(35.5) = 95.3Amount of MgCl2 = 444/95.3 = 4.66mol4.66 moles of MgCl2 are contained within a 444g pure sample.


What is the mass of 6.80 moles of magnesium chloride MgCl2 express the value and units?

6,8 x 95,211 g (molar mass of anhydrous MgCl2)The mass of 6.80 moles of magnesium chloride or MgCl2 is 647,435 g.


What is the molarity of 80g magnesium chloride dissolved in 250ml of water?

MgCl2 Molarity = moles of solute/Liters of solution ( 250 ml = 0.250 L ) Get moles MgCl2 80 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.8402 moles MgCl2 Molarity = 0.8402 moles MgCl2/0.250 Liters = 3.4 M MgCl2 ----------------


How many chloride ions are in a sample of salt that contains 2 moles of KCl?

1.20442 x 1024 chloride ions


What is the mass of 6.10 moles of magnesium chloride?

The mass of 6.80 moles of magnesium chloride or MgCl2 is 647,435 g.


124 g of MgCl2 contains __.mol MgCl2?

Mgcl2 contain molar mass=24.31+ 2(35.45)= 95.21 g/mol 124g of Mgcl2 contains moles= 95.21* 124=11806.04moles


How many formula units make up 11.6g of mgcl2?

Magnesium chloride (MgCl2) has a molecular weight of 95.21 grams per mole. 11.6 grams of MgCl2 is therefore .122 moles.


How many moles in 53.8 g of magnesium chloride?

Magnesium chloride, MgCl2, has a molecular mass of has a molar mass of 95.21 g/mol. So, 53.8 g MgCl / 95.21 g/mol is 0.565 mol MgCl2.


How many moles of ions are produced by the dissociation of 1 mole NH4Br?

I assume that is 28.0 grams.28.0 grams MgCl2 (1 mole MgCl2/95.21 grams)= 0.294 moles magnesium chloride==========================Now,One mole Mg 2+ = 0.294 moles Mg 2+ ions=============================2 moles Cl - = 0.588 moles Cl - ions=========================


In the reaction MgCl2 plus 2KOH gives magnesium hydroxide plus 2KCl if 3 moles of MgCl2 are added to 4 moles KOH what determines how much magnesium hydroxide is made?

MgCl2(aq) + 2KOH(aq) --> Mg(OH)2(s) + 2KCl(aq)It is the molar ratio in the equation. Every mole of magnesium chloride requires 2 moles of potassium hydroxide. Thus 3 moles would need 6 moles of alkali for complete reaction. We don't have that much, so potassium hydroxide is the limiting reactant and we can only use 2 moles of the magnesium chloride and produce 2 moles of magnesium hydroxide.


In the reaction MgCl2 plus 2KOH gives magnesium hydroxide plus 2KCl how many moles of KOH react with 1 mole of MgCl2?

1