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How many moles are contained in 444 grams of magnesium chloride?
To find the number of moles in 444 grams of magnesium chloride, you first need to calculate the molar mass of magnesium chloride. The molar mass of MgCl2 is about 95.21 g/mol. Next, calculate the number of moles by dividing the given mass by the molar mass: 444 g / 95.21 g/mol ≈ 4.66 moles of magnesium chloride.
How many moles in 53.8 g of magnesium chloride?
To determine the number of moles in 53.8 g of magnesium chloride, you first need to calculate the molar mass of MgCl2 which is 95.21 g/mol. Then, divide the given mass by the molar mass to find the number of moles. In this case, 53.8 g / 95.21 g/mol = 0.565 moles.
How many formula units make up 11.6g of mgcl2?
To find the number of formula units of MgCl2 in 11.6g, first calculate the molar mass of MgCl2 (95.21 g/mol). Then, divide the given mass by the molar mass to find the number of moles (0.122 mol). Since 1 mol of MgCl2 contains 1 formula unit, the number of formula units in 11.6g of MgCl2 is also 0.122 mol.
How many formula units make up 32.0 g of magnesium chloride (MgCl2)?
To find the number of formula units in 32.0 g of magnesium chloride (MgCl2), you first need to calculate the molar mass of MgCl2. The molar mass of MgCl2 is 95.21 g/mol. Next, divide the given mass by the molar mass to get the number of moles, and then use Avogadro's number to convert moles to formula units. So, 32.0 g / 95.21 g/mol ≈ 0.336 moles of MgCl2, and then using Avogadro's number, this corresponds to approximately 2.02 x 10^23 formula units of MgCl2.
How many atoms are in 4 moles of MgCl2?
1 mole of any substance contains 6.02 x 1023 constituent particles, correct to three significant figures (avogadro constant).Number of molecules of 4 moles of MgCl2 = 4 x 6.02 x 1023In every molecule of MgCl2 there are 3 atoms.Thus, number of atoms in 4 moles of MgCl2 = 3 x 4 x 6.02 x 1023 = 7.22 x 1024
How many chloride ions are in a sample of salt that contains 2 moles of MgCl2?
2.4088 x 1024 chloride ions
How many chloride ions are in a sample of salt that contains 2 moles of KCl?
There are 2 moles of KCl in the sample, so there are 2 moles of chloride ions as well. Since each molecule of KCl contains 1 chloride ion, there are 2 moles of chloride ions in total.
How many moles are contained in 444 grams of magnesium chloride?
To find the number of moles in 444 grams of magnesium chloride, you first need to calculate the molar mass of magnesium chloride. The molar mass of MgCl2 is about 95.21 g/mol. Next, calculate the number of moles by dividing the given mass by the molar mass: 444 g / 95.21 g/mol ≈ 4.66 moles of magnesium chloride.
What is the mass of 6.80 moles of magnesium chloride MgCl2 express the value and units?
The molar mass of magnesium chloride MgCl2 is 95.21 g/mol. To find the mass of 6.80 moles, you would multiply the number of moles by the molar mass: 6.80 moles * 95.21 g/mol = 647.868 g. Therefore, the mass of 6.80 moles of MgCl2 is 647.868 grams.
What is the molarity of 80g magnesium chloride dissolved in 250ml of water?
MgCl2 Molarity = moles of solute/Liters of solution ( 250 ml = 0.250 L ) Get moles MgCl2 80 grams MgCl2 (1 mole MgCl2/95.21 grams) = 0.8402 moles MgCl2 Molarity = 0.8402 moles MgCl2/0.250 Liters = 3.4 M MgCl2 ----------------
What is the mass of 6.10 moles of magnesium chloride?
The mass of 6.80 moles of magnesium chloride or MgCl2 is 647,435 g.
124 g of MgCl2 contains __.mol MgCl2?
Mgcl2 contain molar mass=24.31+ 2(35.45)= 95.21 g/mol 124g of Mgcl2 contains moles= 95.21* 124=11806.04moles
105 g of MgCl2 contains how much mol MgCl2?
First, we calculate the molar mass of MgCl2, which is 95.21 g/mol. Then, we divide the given mass by the molar mass to determine the number of moles of MgCl2. So, 105 g of MgCl2 contains approximately 1.10 moles of MgCl2.
What is the mass of 9.40 moles of magnesium chloride MgCl2?
There is 9.40 mol of MgCl2 and you want to know how many grams (g). First find the atomic weight of the molecule. Mg = 24.312 Cl = 35.453 x 2 = 70.906 MgCl2 = 95.218 g/mol Then multiply the given moles by the atomic weight of the molecule to get the mass. 9.40 mol x 95.218 g/mol = 895.05 g MgCl2
How many moles of potassium chloride are there in a 100.0g sample of potassium chloride?
To calculate the number of moles of potassium chloride in a 100.0g sample, you need to divide the mass of the sample by the molar mass of potassium chloride. The molar mass of potassium chloride is approximately 74.55 g/mol. Therefore, 100.0g ÷ 74.55 g/mol = approximately 1.34 moles of potassium chloride in the sample.
How many formula units make up 33.8 g of magnesium chloride (MgCl2)?
To find the number of formula units in 33.8g of magnesium chloride (MgCl2), you first need to calculate the molar mass of MgCl2. The molar mass of MgCl2 is 95.21 g/mol. Then, divide the given mass by the molar mass to find the number of moles, which is 0.355 moles. Finally, multiply the number of moles by Avogadro's number (6.022 x 10^23) to find the number of formula units.
How many moles in 53.8 g of magnesium chloride?
To determine the number of moles in 53.8 g of magnesium chloride, you first need to calculate the molar mass of MgCl2 which is 95.21 g/mol. Then, divide the given mass by the molar mass to find the number of moles. In this case, 53.8 g / 95.21 g/mol = 0.565 moles.
