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There is 9.40 mol of MgCl2 and you want to know how many grams (g). First find the atomic weight of the molecule.
Mg = 24.312
Cl = 35.453 x 2 = 70.906
MgCl2 = 95.218 g/mol
Then multiply the given moles by the atomic weight of the molecule to get the mass.
9.40 mol x 95.218 g/mol = 895.05 g MgCl2
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What is the mass of 6.80 moles of magnesium chloride MgCl2 express the value and units?
6,8 x 95,211 g (molar mass of anhydrous MgCl2)The mass of 6.80 moles of magnesium chloride or MgCl2 is 647,435 g.
How many formula units are there in 2.5 grams of Magnesium Chloride?
The relative molecular mass of magnesium chloride is approximately 60. The molar mass is therefore 60g per mole. Therefore there is 0.42mol of formula units in 2.5 grams.The formula mass of MgCl2 is 24.3 + 2(35.5) = 95.3Amount of MgCl2 = 2.5/95.3 = 0.0262molThere are 0.0262 moles of formula unit in 2.5 grams of magnesium chloride.To get the number (not in moles), multiply the amount in moles by the Avogadro's constant.
How many formula units make up 25.6 g of magnesium chloride (MgCl2)?
The molar mass of magnesium chloride is 95,211 g.25,6/95,211 = 0,269
Number of grams in 2.0 moles of magnesium chloride?
The formula of magnesium carbonate is MgCO3. It therefore has one atom each of magnesium and carbon and 3 atoms of oxygen. The gram molecular weight is therefore 24.305 + 12.011 + 3(15.999) = 84.313. This answer to the problem is twice this value, 168.626 grams, if the number "two" is considered to be exact.
How do you calculate what mass of magnesium chloride is formed when 54.75g of HCl is reacted with sufficient magnesium?
By starting with a balanced equation. Mg + 2HCl -> MgCl2 + H2 when they say sufficient magnesium they imply that magnesium is in excess and HCl limits and drives the reaction, or that both are equal in molarity/mass 54.75 g HCl (1 mole HCl/36.458 g)(1 mole MgCl2/2 mole HCl)(95.21 g/1 mole MgCl2) = 71.49 grams magnesium chloride produced -----------------------------------------------------------
What is the mass of 6.80 moles of magnesium chloride MgCl2 express the value and units?
6,8 x 95,211 g (molar mass of anhydrous MgCl2)The mass of 6.80 moles of magnesium chloride or MgCl2 is 647,435 g.
What is the mass of 6.10 moles of magnesium chloride?
The mass of 6.80 moles of magnesium chloride or MgCl2 is 647,435 g.
How many moles in 53.8 g of magnesium chloride?
Magnesium chloride, MgCl2, has a molecular mass of has a molar mass of 95.21 g/mol. So, 53.8 g MgCl / 95.21 g/mol is 0.565 mol MgCl2.
How many moles are contained in 444 grams of magnesium chloride?
Formula mass of MgCl2 = 24.3+2(35.5) = 95.3Amount of MgCl2 = 444/95.3 = 4.66mol4.66 moles of MgCl2 are contained within a 444g pure sample.
How many formula units are there in 2.5 grams of Magnesium Chloride?
The relative molecular mass of magnesium chloride is approximately 60. The molar mass is therefore 60g per mole. Therefore there is 0.42mol of formula units in 2.5 grams.The formula mass of MgCl2 is 24.3 + 2(35.5) = 95.3Amount of MgCl2 = 2.5/95.3 = 0.0262molThere are 0.0262 moles of formula unit in 2.5 grams of magnesium chloride.To get the number (not in moles), multiply the amount in moles by the Avogadro's constant.
How many formula units make up 25.6 g of magnesium chloride (MgCl2)?
The molar mass of magnesium chloride is 95,211 g.25,6/95,211 = 0,269
Number of grams in 2.0 moles of magnesium chloride?
The formula of magnesium carbonate is MgCO3. It therefore has one atom each of magnesium and carbon and 3 atoms of oxygen. The gram molecular weight is therefore 24.305 + 12.011 + 3(15.999) = 84.313. This answer to the problem is twice this value, 168.626 grams, if the number "two" is considered to be exact.
How many formula units make up 32.0 g of magnesium chloride (MgCl2)?
Approx. 3 formula units (the molar mass of the anhydrous MgCl2 is 95,211).
Calculate the formula mass for MgCl2?
The molar mass of magnesium chloride is 95,205 g.
How many moles of lithium phosphate are in 51 grams of this substance?
Molar mass of MgCl2 is 95gmol-1. So there are 0.566 moles in this mass.
How do you calculate what mass of magnesium chloride is formed when 54.75g of HCl is reacted with sufficient magnesium?
By starting with a balanced equation. Mg + 2HCl -> MgCl2 + H2 when they say sufficient magnesium they imply that magnesium is in excess and HCl limits and drives the reaction, or that both are equal in molarity/mass 54.75 g HCl (1 mole HCl/36.458 g)(1 mole MgCl2/2 mole HCl)(95.21 g/1 mole MgCl2) = 71.49 grams magnesium chloride produced -----------------------------------------------------------
How much is 4 millimoles of magnesium in mg?
1 Mole of magnesium = 24.305 grams The 24.305 comes from the periodic table of elements. Simply find Mg and the atomic mass (the biggest number) is the same if u have 1 mole of that. So 24.305 grams x 4 = 97.22 grams
