Approx. 3 formula units (the molar mass of the anhydrous MgCl2 is 95,211).
molar mass of MgCl2=95.211g/mol mol=mass/molar mass=34.8g*mol/95.211g=0.3655039859molMgCl2 #of anything=mol*Avogadro's#=0.3655mol*6.022*1023formula units/mol answer= 2.20*1023
To find the number of formula units of MgCl2 in 11.6g, first calculate the molar mass of MgCl2 (95.21 g/mol). Then, divide the given mass by the molar mass to find the number of moles (0.122 mol). Since 1 mol of MgCl2 contains 1 formula unit, the number of formula units in 11.6g of MgCl2 is also 0.122 mol.
To find out how many formula units of MgCl2 are in 21.2g, you can use the formula: (mass in grams)/(molar mass). The molar mass of MgCl2 is 95.211 g/mol. So, (21.2 g)/(95.211 g/mol) = 0.223 moles of MgCl2. Since there is 1 formula unit of MgCl2 in 1 mole, there are 0.223 formula units in 21.2g of MgCl2.
To find the number of formula units of magnesium oxide in 5.68 moles, you first need to determine the formula of magnesium oxide (MgO). Then use Avogadro's number (6.022 x 10^23) to convert moles to formula units. So, in 5.68 moles of MgO, there are approximately 3.43 x 10^24 formula units.
There are 14 chlorine atoms in seven sodium chloride formula units. This is because each sodium chloride formula unit contains one chlorine atom, so in seven units there are 7 x 1 = 7 chlorine atoms.
To find the number of formula units in 33.8g of magnesium chloride (MgCl2), you first need to calculate the molar mass of MgCl2. The molar mass of MgCl2 is 95.21 g/mol. Then, divide the given mass by the molar mass to find the number of moles, which is 0.355 moles. Finally, multiply the number of moles by Avogadro's number (6.022 x 10^23) to find the number of formula units.
To calculate the number of formula units in 21.2g of magnesium chloride (MgCl2), first calculate the molar mass of MgCl2 which is 95.21 g/mol. Then, divide the given mass by the molar mass to get the number of moles (0.223 mol). As there is one mole of MgCl2 in 1 formula unit, 0.223 mol is equal to 0.223 formula units.
To find the number of formula units in 25.6 g of magnesium chloride (MgCl2), first calculate the molar mass of MgCl2 (95.21 g/mol). Then divide the given mass by the molar mass to find the number of moles (0.269 mol). Finally, use Avogadro's number (6.022 x 10^23 units/mol) to convert moles to formula units, resulting in approximately 1.62 × 10^23 formula units in 25.6 g of MgCl2.
To determine the number of formula units in 12.2g of magnesium chloride, you need to first calculate the molar mass of magnesium chloride (MgCl2). The molar mass of MgCl2 is 95.21 g/mol. Next, divide the given mass (12.2g) by the molar mass of MgCl2 to find the number of moles present. Finally, use Avogadro's number (6.022 x 10^23) to convert moles to formula units.
The relative molecular mass of magnesium chloride is approximately 60. The molar mass is therefore 60g per mole. Therefore there is 0.42mol of formula units in 2.5 grams.The formula mass of MgCl2 is 24.3 + 2(35.5) = 95.3Amount of MgCl2 = 2.5/95.3 = 0.0262molThere are 0.0262 moles of formula unit in 2.5 grams of magnesium chloride.To get the number (not in moles), multiply the amount in moles by the Avogadro's constant.
To determine the number of formula units in 32.2 g of magnesium chloride (MgCl2), you need to first calculate the molar mass of MgCl2. The molar mass of MgCl2 is 95.21 g/mol. Then, divide the given mass by the molar mass to find the number of moles, and finally, use Avogadro's number (6.022 × 10^23) to convert moles to formula units.
The formula for an ionic compound like magnesium chloride is expressed in terms of the ratio of cations to anions to achieve overall charge neutrality. In this case, the formula would be MgCl2, showing that one magnesium ion (Mg2+) combines with two chloride ions (Cl-) to form the compound.
molar mass of MgCl2=95.211g/mol mol=mass/molar mass=34.8g*mol/95.211g=0.3655039859molMgCl2 #of anything=mol*Avogadro's#=0.3655mol*6.022*1023formula units/mol answer= 2.20*1023
To determine the number of formula units, you need to first calculate the molar mass of magnesium chloride (MgCl2). The molar mass is 95.21 g/mol. Next, divide the given mass (25.2 g) by the molar mass to find the number of moles of magnesium chloride. Finally, use Avogadro's number (6.022 x 10^23) to convert moles to formula units.
To find the number of formula units of MgCl2 in 11.6g, first calculate the molar mass of MgCl2 (95.21 g/mol). Then, divide the given mass by the molar mass to find the number of moles (0.122 mol). Since 1 mol of MgCl2 contains 1 formula unit, the number of formula units in 11.6g of MgCl2 is also 0.122 mol.
To find the number of formula units in 40.0 g of magnesium chloride (MgCl2), first calculate its molar mass. The molar mass of MgCl2 is approximately 95.21 g/mol (24.31 g/mol for Mg and 35.45 g/mol for Cl, multiplied by 2). Next, divide the mass of the sample by the molar mass: 40.0 g ÷ 95.21 g/mol ≈ 0.420 mol. Finally, multiply the number of moles by Avogadro's number (6.022 x 10²³ formula units/mol) to get approximately 2.53 x 10²³ formula units of MgCl2.
MgCI2 does not exist. The formula is MgCl2 with a lowercase L. This compound is ionic.